/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 In Exercises \(33-36,\) find the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(33-36,\) find the first four derivatives of the function. $$y=x^{2}+x+3$$

Short Answer

Expert verified
The first four derivatives of the function \(y=x^{2}+x+3\) are \(y'=2x+1\), \(y''=2\), \(y'''=0\), and \(y''''=0\).

Step by step solution

01

Function Definition

Define the function \(y=x^{2}+x+3\). This is the function whose derivatives are to be found.
02

First Derivative

Apply the power rule for differentiation, which states if \(y = ax^n\), then the derivative of \(y\) is \( y'=nax^{n-1}\). In this case, the first derivative is \(y'=2x^{1}+1 + 0 = 2x+1\). The term '3' is a constant and the derivative of a constant is zero.
03

Second Derivative

Next, take the derivative of \(y'\) (from Step 2) to get the second derivative \(y''= 2 + 0 = 2\). Note that the derivative of \(x\) is 1 and the derivative of a constant '1' is zero.
04

Third Derivative

Then, take the derivative of \(y''\) (from Step 3) to get the third derivative. Since \(y''\) is a constant '2', its derivative is zero. Therefore, \(y'''=0\).
05

Fourth Derivative

Finally, take the derivative of \(y'''\) (from Step 4) to get the fourth derivative. Since \(y'''\) is zero, its derivative is also zero. Therefore, \(y''''=0\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a straightforward and essential rule in calculus used to differentiate functions of the form \( y = x^n \). It greatly simplifies finding derivatives, especially for polynomial functions. If you have a term \( ax^n \), the power rule helps you quickly determine its derivative: simply multiply the exponent \( n \) by the coefficient \( a \), and then reduce the power of \( x \) by one. Therefore, the derivative of \( ax^n \) is given by \( y' = nax^{n-1} \). This rule makes it easy to handle polynomial terms by repeatedly applying it to each term.
For example, if your function is \( y = x^2 + x + 3 \), you would apply the power rule to each term individually:
  • For \( x^2 \), the derivative is \( 2x^{1} = 2x \).
  • For \( x \), the derivative is \( 1 \times x^{1-1} = 1 \).
  • The constant \( 3 \) becomes \( 0 \) since the derivative of a constant is always zero.
By adding the results from each term, you find that the first derivative is \( y' = 2x + 1 \). Use this rule to efficiently compute derivatives of many standard functions.
Higher Order Derivatives
When we talk about higher order derivatives, we refer to derivatives beyond the first one. These provide insights into the behavior and properties of a function beyond just its slope. After computing the first derivative, you obtain the slope of the tangent at any point on the curve. The second derivative can tell you about the concavity of the function. Is it curving upwards or downwards?
As we differentiate further, the third derivative, and beyond, highlight changes about the preceding derivatives, though their interpretations become more specialized beyond practical visuals.
In our exercise, after finding the first derivative \( y' = 2x + 1 \), the second derivative is \( y'' = 2 \). The second derivative \( 2 \) clearly indicates the graph is consistently curving in an upward manner, a sign of convexity without any change across x-values.
By examining even higher derivatives, i.e., the third derivative \( y''' = 0 \) and the fourth derivative \( y'''' = 0 \), we see the function reaches a stage where it flattens out, which is typical for polynomial functions when extending beyond their degree. Hence, make sure to embrace these higher order derivatives to fully understand a function's dynamic.
Constant Function Differentiation
In calculus, understanding the differentiation of constants can simplify the differentiation process significantly. A constant function can be something like \( y = c \) where \( c \) represents any real number that does not change. When you differentiate a constant function, its derivative is always zero. This is because constant terms do not contribute to the rate of change of the function.
Consider this function's constant term: \( y = x^2 + x + 3 \). While differentiating, \( 3 \) becomes \( 0 \), as the rate of change over any point on a constant is negligible – it stays the same everywhere! This holds true not only across polynomial components but also underscores the third and fourth derivatives in the exercise. When the function reduces to a constant, subsequent derivatives remain zero.
It's crucial to remember that although constants simplify the differentiation process, they inherently affect initial values and vertical shifts of functions. By recognizing when and how to identify these constants, the task of differentiation, especially of polynomials, becomes much more manageable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Thoroughbred Racing A racehorse is running a 10 -furlong race. (A furlong is 220 yards, although we will use furlongs and seconds as our units in this exercise.) As the horse passes each furlong marker \((F),\) a steward records the time elapsed \((t)\) since the beginning of the race, as shown in the table below: \(\begin{array}{c|ccccccccccc}{\mathbf{F}} & {0} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {9} & {10} \\ \hline t & {0} & {20} & {33} & {46} & {59} & {73} & {86} & {100} & {112} & {124} & {135}\end{array}\) (a) How long does it take the horse to finish the race? (b) What is the average speed of the horse over the first 5 furlongs? (c) What is the approximate speed of the horse as it passes the 3 -furlong marker? (d) During which portion of the race is the horse running the fastest? (e) During which portion of the race is the horse accelerating the fastest?

(a) Write the area A of an equilateral triangle as a function of the side length s. (b) Find the (instantaneous) rate of change of the area A with respect to a side s. (c) Evaluate the rate of change of A at s " 2 and s " 10. (d) If \(s\) is measured in inches and \(A\) is measured in square inches, what units would be appropriate for \(d A / d s ?\)

Using one-sided derivatives, show that the function \(f(x)=\left\\{\begin{array}{c}{x^{2}+x,} & {x \leq 1} \\ {3 x-2,} & {x>1}\end{array}\right.\) does not have a derivative at \(x=1\)

Marginal Cost Suppose that the dollar cost of producing \(x\) washing machines is \(c(x)=2000+100 x-0.1 x^{2} .\) (a) Find the average cost of producing 100 washing machines. (b) Find the marginal cost when 100 machines are produced. (c) Show that the marginal cost when 100 washing machines are produced is approximately the cost of producing one more washing machine after the first 100 have been made, by calculating the latter cost directly.

Group Activity In Exercises 5 and 6, the coordinates s of a moving body for various values of t are given. (a) Plot s versus t on coordinate paper, and sketch a smooth curve through the given points. (b) Assuming that this smooth curve represents the motion of the body, estimate the velocity at \(t=1.0, t=2.5,\) and \(t=3.5 .\) \(\frac{t(\mathrm{sec})}{s(\mathrm{ft})} \left| \begin{array}{ccccccccc}{0} & {0.5} & {1.0} & {1.5} & {2.0} & {2.5} & {3.0} & {3.5} & {4.0} \\ \hline s(\mathrm{ft}) & {12.5} & {26} & {36.5} & {44} & {48.5} & {50} & {48.5} & {44} & {36.5}\end{array}\right.\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.