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In Exercises \(31-42,\) find \(d y / d x\). $$y=\sqrt[4]{x}$$

Short Answer

Expert verified
The derivative of \(y=\sqrt[4]{x}\) or \(y=x^{1/4}\) is \((1/4)/\sqrt[4]{x^3}\) or \((1/4)x^{-3/4}\).

Step by step solution

01

Rewrite the function

Rewrite the equation with fractional exponents instead of a roots. This is important as it makes the function easier to differentiate. So, rewrite the function as \(y = x^{1/4}\).
02

Apply the power rule

The power rule states that the derivative of x to the power of n, \(x^n\), is \(nx^{n-1}\). Appy the rule to the function, which gives \(dy/dx = (1/4)x^{-3/4}\). This is the derivative of the given function.
03

Simplify the function

The derivative function can be simplified further by rewriting \(x^{-3/4}\) as \(1/x^{3/4}\) or \(1/\sqrt[4]{x^3}\). The derivative, dy/dx, simplifies to \((1/4)/\sqrt[4]{x^3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental tool in differential calculus, used to find the derivative of a function of the form \(x^n\). It simplifies the process of differentiation, making it straightforward and quick.

In general, if you have a function \(y = x^n\), where \(n\) is any real number, the power rule indicates that the derivative \(\frac{dy}{dx}\) is \(nx^{n-1}\). It involves multiplying the exponent \(n\) by the function \(x^n\) itself and then reducing the exponent by 1.

Using the power rule ensures that you're able to tackle an extensive variety of polynomial functions comfortably and consistently, ranging from simple to complex expressions.
Fractional Exponents
Fractional exponents denote roots and offer a more manageable form for differentiation compared to radical (square or cube roots) expressions. Representing roots as fractional exponents aligns perfectly with the power rule, enabling simple calculations.

For example, the fourth root of \(x\), written as \(\sqrt[4]{x}\), can be rewritten as \(x^{1/4}\). The exponent \(1/4\) implies the root component. This conversion is essential because applying differentiation methods like the power rule becomes straightforward when dealing with pure powers rather than radical expressions.

Utilizing fractional exponents converts otherwise complex expressions into simpler forms, paving the way to easily apply the power rule for finding derivatives.
Derivatives
Derivatives measure how a function changes as its input changes, providing insights into the rate of change or the slope of the function at any given point. Understanding how to compute derivatives is crucial for understanding the behavior of functions.

In the exercise provided, the derivative \(\frac{dy}{dx}\) of \(y = x^{1/4}\) is found using the power rule, resulting in \(\frac{1}{4}x^{-3/4}\).

After finding the derivative, it's common to simplify the expression, such as converting \(x^{-3/4}\) to \(\frac{1}{x^{3/4}}\) or \(\frac{1}{\sqrt[4]{x^3}}\). This simplification process doesn't change the derivative's meaning but makes it easier to work with and interpret, especially in further calculus applications.

Understanding and interpreting derivatives is a stepping stone to various applications in science, engineering, economics, and beyond, where rate of change is a critical concept.

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Most popular questions from this chapter

Radians vs. Degrees What happens to the derivatives of \(\sin x\) and cos \(x\) if \(x\) is measured in degrees instead of radians? To find out, take the following steps. (a) With your grapher in degree mode, graph \(f(h)=\frac{\sin h}{h}\) and estimate \(\lim _{h \rightarrow 0} f(h) .\) Compare your estimate with \(\pi / 180 .\) Is there any reason to believe the limit should be \(\pi / 180 ?\) (b) With your grapher in degree mode, estimate \(\lim _{h \rightarrow 0} \frac{\cos h-1}{h}\) (c) Now go back to the derivation of the formula for the derivative of sin \(x\) in the text and carry out the steps of the derivation using degree-mode limits. What formula do you obtain for the derivative? (d) Derive the formula for the derivative of cos \(x\) using degree-mode limits. (e) The disadvantages of the degree-mode formulas become apparent as you start taking derivatives of higher order. What are the second and third degree-mode derivatives of \(\sin x\) and \(\cos x\) ?

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