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In Exercises \(1-28\) , find \(d y / d x\) . Remember that you can use NDER to support your computations. $$y=e^{2 x}$$

Short Answer

Expert verified
The derivative of the function \(y = e^{2x}\) is \(dy/dx = 2e^{2x}\)

Step by step solution

01

Identify the outer and the inner function

The given function is \(y = e^{2x}\). Here, the inner function is \(u = 2x\) and the outer function is \(y = e^u\). We always look for the 'innermost' layer of the function to find out the inner function and work our way outwards to identify the outer function.
02

Differentiate the inner function

The derivative of the inner function \(u = 2x\) with respect to \(x\) is just \(2\). We use the rule that the derivative of \(x\) is just \(1\), hence \(2x\) differentiated would just be \(2\).
03

Differentiate the outer function

The derivative of the outer function \(e^u\) with respect to \(u\) is just \(e^u\). This is a property of the exponential function \(e^u\), that it is its own derivative.
04

Apply the chain rule

The chain rule states that the derivative of a composition of functions is the derivative of the outer function times the derivative of the inner function. So, differentiating the function \(y = e^{2x}\) would be the derivative of \(e^{u}\) times the derivative of \(u\). Substituting the results from Steps 2 and 3, we get \(dy/dx = e^u * 2 = 2e^{2x}\)
05

Simplify, if needed

In our case, no further simplification is required, and we have the final derivative as \(dy/dx = 2e^{2x}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule in Calculus
Understanding the chain rule is essential when dealing with composite functions, those consisting of one function inside of another. When differentiating such functions, we employ the chain rule to take the derivative systematically.

Let's say you have a composite function, expressible as \( f(g(x)) \). To apply the chain rule, you'd differentiate the outer function \( f \) as if the inner function \( g \) were a simple variable, and multiply it by the derivative of the inner function \( g \). In mathematical terms, if \( y = f(u) \) and \( u = g(x) \) then the chain rule tells us that \( \frac{dy}{dx} = \frac{df}{du} \cdot \frac{du}{dx} \).

The chain rule is a way to navigate through the layers of functions, just like peeling an onion. You start with the outermost layer and work your way to the innermost part, differentiating at each stage. This rule is indispensable because it allows us to differentiate a vast array of functions that are otherwise difficult to handle. An analogy might be how a machine assembles a product piece by piece—every component must be accounted for to get the final product right.
Derivative of Exponential Functions
Understanding the derivative of exponential functions opens the door to many fields such as economics, biology, and physics where these functions model growth and decay processes.

Exponential functions are unique in calculus because they have a constant base, commonly \( e \) (Euler's number approximately equal to 2.71828), raised to a variable power. One of the most striking properties of the exponential function \( e^x \) is that it is its own derivative, i.e., \( \frac{d}{dx}e^x = e^x \). This simplifies the differentiation process significantly. The function \( e^{2x} \) is a slightly more complex exponential function, but it follows the same principle. When differentiating \( e^{2x} \) the constant multiplier in the exponent emerges as part of the result through the use of the chain rule, yielding a derivative that involves both the original function and the constant from the power, as shown in the step-by-step solution.
Implicit Differentiation
When functions are interwoven and not easily separated, implicit differentiation becomes a crucial tool. Unlike explicit functions where \( y \) is given directly in terms of \( x \) (e.g., \( y = 3x + 2 \) or \( y = e^{2x} \) from our exercise), implicit functions involve \( y \) and \( x \) mixed together (e.g., \( x^2 + y^2 = 1 \) representing a circle).

To differentiate implicitly, we take the derivative of both sides of the equation with respect to \( x \) and solve for \( \frac{dy}{dx} \). This requires treating \( y \) as an implicit function of \( x \) throughout the differentiation process. The chain rule often plays a role here as well when \( y \) appears in combination with \( x \) because \( y \) itself is a function of \( x \) even though it's not explicitly stated. As we differentiate terms with \( y \) in them, we multiply by \( \frac{dy}{dx} \) to account for the fact that 'y' changes with 'x'.

Implicit differentiation can be seen as detective work, where we are finding out information about how \( y \) changes with \( x \) without ever isolating \( y \) on its own.

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Most popular questions from this chapter

Derivatives of Exponential and Logarithmic Functions 179 Let \(f(x)=2^{x}\)\ (a) Find \(f^{\prime}(0) . \quad\) ln 2 (b) Use the definition of the derivative to write \(f^{\prime}(0)\) as a limit (c) Deduce the exact value of \(\lim _{h \rightarrow 0} \frac{2^{h}-1}{h}\) (d) What is the exact value of \(\lim _{h \rightarrow 0} \frac{7^{h}-1}{h} ?\)

Multiple Choice Which of the following is \(\frac{d}{d x} \sin ^{-1}\left(\frac{x}{2}\right) ?\) \((\mathbf{A})-\frac{2}{\sqrt{4-x^{2}}} \quad(\mathbf{B})-\frac{1}{\sqrt{4-x^{2}}} \quad\) (C) \(\frac{2}{4+x^{2}}\) (D) \(\frac{2}{\sqrt{4-x^{2}}} \quad\) (E) \(\frac{1}{\sqrt{4-x^{2}}}\)

Bacterium Population When a bactericide was added to a nutrient broth in which bacteria were growing, the bacterium population continued to grow for a while but then stopped growing and began to decline. The size of the population at time \(t\) (hours) was \(b(t)=10^{6}+10^{4} t-10^{3} t^{2}\) . Find the growth rates at \(t=0, t=5,\) and \(t=10\) hours.

Multiple Choice Which of the following is \(d y / d x\) if \(y=\cos ^{2}\left(x^{3}+x^{2}\right) ?\) (A) \(-2\left(3 x^{2}+2 x\right)\) (B) \(-\left(3 x^{2}+2 x\right) \cos \left(x^{3}+x^{2}\right) \sin \left(x^{3}+x^{2}\right)\) (C) \(-2\left(3 x^{2}+2 x\right) \cos \left(x^{3}+x^{2}\right) \sin \left(x^{3}+x^{2}\right)\) (D) 2\(\left(3 x^{2}+2 x\right) \cos \left(x^{3}+x^{2}\right) \sin \left(x^{3}+x^{2}\right)\) (E) 2\(\left(3 x^{2}+2 x\right)\)

Generating the Birthday Probabilities Example 5 of this section concerns the probability that, in a group of \(n\) people, at least two people will share a common birthday. You can generate these probabilities on your calculator for values of \(n\) from 1 to \(365 .\) Step 1: Set the values of \(N\) and \(P\) to zero: Step \(2 :\) Type in this single, multi-step command: Now each time you press the ENTER key, the command will print a new value of \(N(\) the number of people in the room) alongside \(P\) (the probability that at least two of them share a common birthday): If you have some experience with probability, try to answer the following questions without looking at the table: (a) If there are three people in the room, what is the probability that they all have different birthdays? (Assume that there are 365 possible birthdays, all of them equally likely.) (b) If there are three people in the room, what is the probability that at least two of them share a common birthday? (c) Explain how you can use the answer in part (b) to find the probability of a shared birthday when there are four people in the room. (This is how the calculator statement in Step 2 generates the probabilities.) (d) Is it reasonable to assume that all calendar dates are equally likely birthdays? Explain your answer.

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