Chapter 2: Problem 19
In Exercises \(19 - 28 ,\) determine the limit graphically. Confirm algebraically. $$\lim _ { x \rightarrow 1 } \frac { x - 1 } { x ^ { 2 } - 1 }$$
Short Answer
Expert verified
The limit of the given function as \(x\) approaches 1 is \(0.5\).
Step by step solution
01
Graphical Method
The first approach should be to plot the function \(f(x) = \frac { x - 1 } { x ^ { 2 } - 1 }\). As \(x\) approaches 1, observe the direction and value the function is approaching. That will provide an intuitive understanding of the limit.
02
Algebraic Method - Step 1: Identifying the form
There would be a direct substitution for \(x = 1\) in the function. \(f(1) = \frac { 1 - 1 } { 1 ^ { 2 } - 1 } = \frac { 0 } { 0 }\). This is an indeterminate form, so the limit isn't immediately apparent and requires further manipulation.
03
Algebraic Method - Step 2: Factorisation
Given the equation \(\frac { x - 1 } { x ^ { 2 } - 1 }\), the denominator \(x^{2} - 1\) can be factored to \((x-1)(x+1)\) via the difference of two squares identity. Hence, the function becomes \(\frac { x - 1 } { (x-1)(x+1) }\).
04
Algebraic Method - Step 3: Simplification
Cancel out the common factors in the numerator and denominator, the function simplifies to \(\frac {1}{x+1}\). Now, resubstitute \(x = 1\) to get the limit.
05
Algebraic Method - Step 4: Substitution of Limit Point
Now subtitute \(x = 1\) into the simplified function \( \frac {1}{ x + 1 }\), hence the limit as \(x\) approaches \(1\) is \(\frac{1}{1+1} = \frac{1}{2}\). Therefore, the limit of the function as \(x\) approaches 1 is \(0.5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphical Method
The graphical method is an intuitive way to understand the behavior of a function as it approaches a particular value. For the function \( f(x) = \frac{x - 1}{x^2 - 1} \), we start by plotting it around \( x = 1 \). As you plot the graph, pay special attention to the behavior of the curve near \( x = 1 \). If you see the graph approaching a particular y-value as \( x \) nears 1, this y-value is the limit of the function.
Keep in mind that due to the potential for vertical asymptotes or undefined points at \( x = 1 \), the graphical approach can suggest the limit, but confirming it algebraically is important to address these undefined or asymptotic behaviors. The graph might show a hole at \( x = 1 \), indicating the function doesn't reach a value there, reinforcing the need for further analysis.
Keep in mind that due to the potential for vertical asymptotes or undefined points at \( x = 1 \), the graphical approach can suggest the limit, but confirming it algebraically is important to address these undefined or asymptotic behaviors. The graph might show a hole at \( x = 1 \), indicating the function doesn't reach a value there, reinforcing the need for further analysis.
Algebraic Method
The algebraic method provides a structured approach to finding limits by manipulating the function's expression to avoid undefined forms.
Cancel out the common \( x - 1 \) term in both the numerator and the denominator, leaving \( \frac{1}{x+1} \). This step of algebra allows us to rewrite the function so that \( x \) can be substituted in without specific exclusion points. When we substitute \( x = 1 \) back, we find the limit as \( x \rightarrow 1 \) is \( \frac{1}{2} \). This cleanly demonstrates that simplifying the expression can unveil the true behavior of the function at that limit point.
- Identifying the Form: We first substitute \( x = 1 \) into the function, \( f(1) = \frac{1 - 1}{1^2 - 1} = \frac{0}{0} \), which is known as an indeterminate form and tells us that straightforward substitution won't work.
- Simplification through Algebra: To resolve this indeterminate form, we can factor the denominator. Recognize \( x^2 - 1 \) as a difference of squares, \( (x-1)(x+1) \). So, the function simplifies to \( \frac{x - 1}{(x-1)(x+1)} \).
Cancel out the common \( x - 1 \) term in both the numerator and the denominator, leaving \( \frac{1}{x+1} \). This step of algebra allows us to rewrite the function so that \( x \) can be substituted in without specific exclusion points. When we substitute \( x = 1 \) back, we find the limit as \( x \rightarrow 1 \) is \( \frac{1}{2} \). This cleanly demonstrates that simplifying the expression can unveil the true behavior of the function at that limit point.
Factoring
Factoring is a crucial mathematical technique used to simplify expressions, especially useful in solving limits.
For instance, in \( f(x) = \frac{x - 1}{x^2 - 1} \), we can factor the denominator using the difference of squares identity: \( x^2 - 1 = (x-1)(x+1) \).
By factoring, we can then cancel common terms between the numerator and the denominator, thus simplifying the function that was indeterminate at \( x = 1 \) due to the \( \frac{0}{0} \) form.
It's important to remember that factoring is not eliminating or ignoring the original function's properties; rather, it is a way to reveal and understand them without the hindrance of indeterminate forms. So, despite \( f(x) \) having a potential undefined point at \( x = 1 \), factoring helps us see that the general behavior of \( f(x) \) near \( x = 1 \) is smoothly defined by \( \frac{1}{x+1} \).
For instance, in \( f(x) = \frac{x - 1}{x^2 - 1} \), we can factor the denominator using the difference of squares identity: \( x^2 - 1 = (x-1)(x+1) \).
By factoring, we can then cancel common terms between the numerator and the denominator, thus simplifying the function that was indeterminate at \( x = 1 \) due to the \( \frac{0}{0} \) form.
It's important to remember that factoring is not eliminating or ignoring the original function's properties; rather, it is a way to reveal and understand them without the hindrance of indeterminate forms. So, despite \( f(x) \) having a potential undefined point at \( x = 1 \), factoring helps us see that the general behavior of \( f(x) \) near \( x = 1 \) is smoothly defined by \( \frac{1}{x+1} \).
- This technique ensures we interpret limits accurately.
- It helps transition from indeterminate to determinate forms.
- Key for applied math problems involving limits and continuity.