Chapter 3: Problem 28
Let \(g(x)=f^{-1}(x) \quad \therefore f(g(x))=x\)
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Chapter 3: Problem 28
Let \(g(x)=f^{-1}(x) \quad \therefore f(g(x))=x\)
These are the key concepts you need to understand to accurately answer the question.
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\(\frac{d}{d x}\left(\frac{g(x)}{g(g(x))}\right)=\frac{g(g(x)) \cdot g^{\prime}(x)-g(x) \cdot g^{\prime}(g(x)) \cdot g^{\prime}(x)}{\left(g(g(x))^{2}\right.}\)
Let \(y=\sin ^{2} \cot ^{-1}\left\\{\sqrt{\frac{1-x}{1+x}}\right\\}\)
\(\frac{d}{d x}\left(\tan ^{-1} \frac{(\sqrt{x}(3-x))}{1-3 x}\right)\)
\(y=\sin x+e^{x}\) or \(\frac{d y}{d x}=\cos x+e^{x}\)
\(\frac{d y}{d x}=\frac{d}{d x}\left[\left(x+\sqrt{x^{2}+a^{2}}\right)^{n}\right]\)
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