Chapter 1: Problem 48
\(f(x)=\sqrt{|x|-\\{x\\}}\) is defined if \(|x| \geq\\{x\\}\) or \(\quad x \in\left(-\infty-\frac{1}{2}\right] \cup[0, \infty)\) or \(Y \in[0, \infty)\)
Short Answer
Expert verified
The function is defined for \(x \in (-\infty, -\frac{1}{2}] \cup [0, \infty)\) when \(Y \geq 0\).
Step by step solution
01
Understanding the Function
The given function is defined as \(f(x) = \sqrt{|x| - \{x\}}\). The expression inside the square root, \(|x| - \{x\}\), must be non-negative for the square root to be real. We need to analyze when this condition holds true.
02
Analyzing the Modulus
The modulus \(|x|\) is the absolute value of \(x\). We consider two cases: \(x \geq 0\) (then \(|x| = x\)) and \(x < 0\) (then \(|x| = -x\)). This helps us examine the expression \(|x| - \{x\}\).
03
Understanding the Fractional Part
The function \(\{x\}\) denotes the fractional part of \(x\), which is \(x - \lfloor x \rfloor\). It ranges from \(0\) to \(1\) (not inclusive of \(1\)).
04
Determining When the Expression is Non-negative
For the expression to be non-negative, analyze the inequality \(|x| \geq \{x\}\). If \(x\) is non-negative (\(|x| = x\)), the inequality becomes \(x \geq x - \lfloor x \rfloor\), which is always true for any integer or non-negative number \(x\). If \(x\) is negative (\(|x| = -x\)), then we simplify the inequality as \(-x \geq x - \lfloor x \rfloor\), ensuring no real values unless it's narrowly defined.
05
Interpreting the Given Set
The problem states three possible conditions for the domain: \(|x| \geq \{x\}\), \(x \in (-\infty, -\frac{1}{2}] \cup [0, \infty)\), or \(Y \geq 0\). The condition \(x \in (-\infty, -\frac{1}{2}] \cup [0, \infty)\) aligns with making the expression non-negative largely because \(-\frac{1}{2}\) as a boundary ensures that \(-x > \{x\}\) can't be satisfied easily in the negative realm unless it's paired to these bounds cleverly.
06
Final Interpretation of Conditions
The correct interpretation combines our insights from above: indeed, \(|x| \geq \{x\}\) is satisfied on viable numbers meeting \(x \in (-\infty, -\frac{1}{2}] \cup [0, \infty)\), securing that the domain only includes expressions evaluated non-negatively, allowing \(Y\) to reflect non-negative real calculations.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value
The absolute value of a number, represented as \(|x|\), is a fundamental concept in mathematics, and it refers to the non-negative value of a number without regard to its sign. In simpler terms, regardless of whether \(x\) is positive or negative, the absolute value \(|x|\) is always positive. Here’s how it works:
- If \(x \geq 0\), then \(|x| = x\).
- If \(x < 0\), then \(|x| = -x\).
Square Root Functions
Square root functions involve the square root of a quantity. The square root of a number \(a\) is a value that, when multiplied by itself, gives the number \(a\). Mathematically, it is expressed as \(\sqrt{a}\). For the function \(f(x) = \sqrt{|x| - \{x\}}\),we are looking for when the expression inside the square root \(|x| - \{x\}\) is non-negative.This is crucial because a square root function is only defined for non-negative numbers in the real number system. Hence, the expression inside must be zero or positive.
- If \(|x|\) is greater than or equal to \(\{x\}\), the square root function can accept the value, ensuring \(f(x)\) is real.
- This means if you find a scenario where \(|x| < \{x\}\), it becomes undefined or imaginary, which is generally not acceptable for real numbers.
Inequalities in Functions
Inequalities are used to define a range or domain for which a function is valid. In the problem at hand, the inequality \(|x| \geq \{x\}\) determines when the function \(f(x) = \sqrt{|x| - \{x\}}\) is defined. What this inequality is asking is for the absolute value of \(x\) to be larger than or equal to its fractional part \(\{x\}\).
The fractional part \(\{x\}\) is essentially the non-integer part of \(x\), calculated as \(x - \lfloor x \rfloor\), and it lies between 0 (inclusive) and 1 (exclusive). Exploring this inequality helps establish boundaries for \(x\):
The fractional part \(\{x\}\) is essentially the non-integer part of \(x\), calculated as \(x - \lfloor x \rfloor\), and it lies between 0 (inclusive) and 1 (exclusive). Exploring this inequality helps establish boundaries for \(x\):
- For non-negative values of \(x\), this inequality generally holds, making the square root function defined over degrees in this range.
- When \(x\) is negative, additional care must be taken to ensure \(|x|\) sufficiently exceeds \(\{x\}\), typically resulting in specific allowable intervals.