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In Problems 13–30, classify each series as absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty} \frac{\cos n \pi}{n} $$

Short Answer

Expert verified
The series is conditionally convergent.

Step by step solution

01

Identify the Series Type

The given series is \( \sum_{n=1}^{\infty} \frac{\cos n \pi}{n} \). Notice the term \( \cos n \pi \), which alternates between -1 and 1 for odd and even \( n \), respectively. This reveals that the series is an alternating series.
02

Test for Absolute Convergence

To determine if the series is absolutely convergent, consider the series \( \sum_{n=1}^{\infty} \left| \frac{\cos n \pi}{n} \right| = \sum_{n=1}^{\infty} \frac{1}{n} \), which is the harmonic series. The harmonic series is known to diverge, so the given series is not absolutely convergent.
03

Test for Conditional Convergence

An alternating series \( \sum (-1)^n a_n \) is convergent if \( a_n \to 0 \) as \( n \to \infty \) and \( a_n \) is decreasing. Here, \( a_n = \frac{1}{n} \), which clearly tends to 0 and is decreasing. Therefore, \( \sum_{n=1}^{\infty} \frac{\cos n \pi}{n} \) converges conditionally.
04

Final Classification

Since the series is not absolutely convergent but is conditionally convergent based on the Alternating Series Test, it is classified as conditionally convergent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alternating Series
In mathematics, an alternating series is a series in which the terms alternate in sign. This means one term is positive, and the next is negative, repeating this pattern throughout the series. For example, a simple alternating series might look like this: \( 1, -1, 1, -1, \ldots \) or in a general form \( \sum (-1)^n a_n \).

The series presented in the exercise, \( \sum_{n=1}^{\infty} \frac{\cos n \pi}{n} \), uses the property of the cosine function. The term \( \cos n \pi \) yields +1 when \( n \) is even and -1 when \( n \) is odd, thus making the series alternating. The presence of the negative sign in alternating series can have significant effects on the convergence properties of the series.

The Alternating Series Test helps determine whether such a series converges. According to this test, if \( a_n \) is a decreasing sequence that approaches zero as \( n \to \infty \), then the alternating series \( \sum (-1)^n a_n \) converges. For the given series, since \( a_n = \frac{1}{n} \) is decreasing and approaches zero, it passes the Alternating Series Test, indicating convergence.
Absolute Convergence
Absolute convergence is a stronger form of convergence in mathematical series. A series is said to be absolutely convergent if the series of its absolute values also converges. In other words, \( \sum_{n=1}^{\infty} a_n \) is absolutely convergent if \( \sum_{n=1}^{\infty} |a_n| \) converges.

Assessing absolute convergence often simplifies the analysis. For the series \( \sum_{n=1}^{\infty} \frac{\cos n \pi}{n} \), we can remove the alternating part by taking the absolute value, leading to \( \sum_{n=1}^{\infty} \frac{1}{n} \). This is known as the harmonic series.

The harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \) lacks absolute convergence because it diverges, meaning it does not have a finite sum as \( n \) approaches infinity. Therefore, our original series is not absolutely convergent. However, this doesn't mean it fails to converge at all; it might still converge conditionally.
Harmonic Series
The harmonic series is a famous mathematical series expressed as \( \sum_{n=1}^{\infty} \frac{1}{n} \). Despite its simple structure, it has much to teach about convergence. It is called 'harmonic' because its terms resemble the harmonics found in music, where each term is a fraction of a fundamental tone.

The series is divergent, which means that as we add more and more terms, the sum grows without bound. While each individual term becomes smaller and approaches zero, the alternating sums do not converge to a particular value.

Even though the harmonic series itself diverges, it plays a crucial role in understanding the convergence of other series, particularly in the study of conditional convergence. In the given exercise, we derived a harmonic series through considering absolute values, contributing crucial insight into the behavior of the original series.

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Most popular questions from this chapter

In Problems 1-20, an explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges or diverges, and, if it converges, find \(\lim _{n \rightarrow \infty} a_{n}\) \(a_{n}=\frac{\sqrt{3 n^{2}+2}}{2 n+1}\)

In Problems \(1-8\), find the convergence set for the given power series. $$ \sum_{n=1}^{\infty} \frac{(x+1)^{n}}{n !} $$

In Problems 1-20, an explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges or diverges, and, if it converges, find \(\lim _{n \rightarrow \infty} a_{n}\) \(a_{n}=\frac{4 n^{2}+2}{n^{2}+3 n-1}\)

In Problems 21-30, find an explicit formula \(a_{n}=\) for each sequence, determine whether the sequence converges or diverges, and, if it converges, find \(\lim _{n \rightarrow \infty} a_{n}\). \(\frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \ldots\)

Let $$ f(x)= \begin{cases}e^{-1 / x^{2}} & \text { if } x \neq 0 \\ 0 & \text { if } x=0\end{cases} $$ (a) Show that \(f^{\prime}(0)=0\) by using the definition of the derivative. (b) Show that \(f^{\prime \prime}(0)=0\). (c) Assuming the known fact that \(f^{(n)}(0)=0\) for all \(n\), find the Maclaurin series for \(f(x)\). (d) Does the Maclaurin series represent \(f(x)\) ? (e) When \(a=0\), the formula in Theorem \(\mathrm{B}\) is called Maclaurin's Formula. What is the remainder in Maclaurin's Formula for \(f(x)\) ? This shows that a Maclaurin series may exist and yet not represent the given function (the remainder does not tend to 0 as \(n \rightarrow \infty)\).

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