Chapter 3: Problem 8
In Problems \(1-8\), find \(d^{3} y / d x^{3}\). $$ y=\frac{3 x}{1-x} $$
Short Answer
Expert verified
The third derivative \( \frac{d^3y}{dx^3} = \frac{18}{(1-x)^4} \).
Step by step solution
01
Find the First Derivative
To find the first derivative \( \frac{dy}{dx} \) of \( y = \frac{3x}{1-x} \), apply the quotient rule: \( \frac{d}{dx}\left( \frac{u}{v} \right) = \frac{u'v - uv'}{v^2} \), where \( u = 3x \) and \( v = 1-x \). The derivatives are \( u' = 3 \) and \( v' = -1 \). Thus, \( \frac{dy}{dx} = \frac{3(1-x) - 3x(-1)}{(1-x)^2} = \frac{3 - 3x + 3x}{(1-x)^2} = \frac{3}{(1-x)^2} \).
02
Find the Second Derivative
Differentiate the first derivative \( \frac{dy}{dx} = \frac{3}{(1-x)^2} \) with respect to \( x \). Using the chain rule, estimate the derivative: \( \frac{d}{dx}[ (1-x)^{-2} ] = -2(1-x)^{-3}(-1) \). So, \( \frac{d^2y}{dx^2} = 3 \times 2(1-x)^{-3} = \frac{6}{(1-x)^3} \).
03
Find the Third Derivative
Differentiate the second derivative \( \frac{d^2y}{dx^2} = \frac{6}{(1-x)^3} \). Using the chain rule again, \( \frac{d}{dx}[ (1-x)^{-3} ] = -3(1-x)^{-4}(-1) \). Thus, \( \frac{d^3y}{dx^3} = 6 \times 3(1-x)^{-4} = \frac{18}{(1-x)^4} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
The quotient rule is a technique used in calculus when you need to differentiate a function that is the division of two other functions. For a function given by the quotient \( y = \frac{u}{v} \), where both \( u \) and \( v \) are functions of \( x \), the quotient rule states that the derivative \( \frac{dy}{dx} \) is calculated as:
- Numerator: \( u'v - uv' \), where \( u' \) is the derivative of \( u \) and \( v' \) is the derivative of \( v \).
- Denominator: \( v^2 \), which is the square of the function \( v \).
Chain Rule
To differentiate composite functions, where one function is applied to the result of another, the chain rule is essential. It is used when a function exists within the domain of another function, forming a composition like \( f(g(x)) \). The chain rule formula is:
- If \( y = f(g(x)) \), then \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
Differentiation Steps
Differentiating functions involves a series of carefully executed steps, especially when finding higher-order derivatives like the third derivative \( \frac{d^3y}{dx^3} \).
- First Derivative: Use initial rules like the quotient rule to find the first derivative, simplifying expressions wherever possible.
- Second Derivative: Apply the chain rule, focusing on differentiating the rational function repeatedly as needed.
- Third Derivative: Continue using the chain rule and adjust coefficients accordingly, being careful with negative signs and changes in exponents.