Chapter 3: Problem 7
In Problems 1-18, find \(D_{x} y\). $$ y=\tan x=\frac{\sin x}{\cos x} $$
Short Answer
Expert verified
The derivative \( D_{x} y = \sec^2 x \).
Step by step solution
01
Understand the function
We are given the function \( y = \tan x = \frac{\sin x}{\cos x} \). This means \( y \) is a tangent function, which is a ratio of sine to cosine.
02
Identify the method to use
To find \( D_{x} y \), where \( y = \frac{\sin x}{\cos x} \), we'll use the quotient rule for differentiation because \( y \) is in the form of a fraction.
03
Recall the quotient rule
The quotient rule states that if \( u(x) = \frac{f(x)}{g(x)} \), then the derivative \( u'(x) = \frac{f'(x)g(x) - f(x)g'(x)}{(g(x))^2} \). Here, \( f(x) = \sin x \) and \( g(x) = \cos x \).
04
Differentiate numerator and denominator
Differentiate \( f(x) = \sin x \) to get \( f'(x) = \cos x \). Differentiate \( g(x) = \cos x \) to get \( g'(x) = -\sin x \).
05
Apply the quotient rule
Substitute into the quotient rule formula: \( u'(x) = \frac{\cos x \cdot \cos x - \sin x \cdot (-\sin x)}{(\cos x)^2} \).
06
Simplify
Simplify the expression: \( u'(x) = \frac{\cos^2 x + \sin^2 x}{\cos^2 x} \). Recall that \( \cos^2 x + \sin^2 x = 1 \), so the expression becomes \( \frac{1}{\cos^2 x} \), which is equal to \( \sec^2 x \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Quotient Rule
The quotient rule is a fundamental tool in calculus used to find the derivative of a function that is the quotient of two other functions. It is essential when working with rational expressions where one function is divided by another.
When you have a function in the form \( u(x) = \frac{f(x)}{g(x)} \), the derivative, \( u'(x) \), can be calculated using the formula:
\[ u'(x) = \frac{f'(x)g(x) - f(x)g'(x)}{(g(x))^2}. \]
This formula requires you to differentiate both the numerator and the denominator separately.
In this particular problem, we are differentiating \( \frac{\sin x}{\cos x} \). Here, \( f(x) = \sin x \) and \( g(x) = \cos x \). Differentiating these gives \( f'(x) = \cos x \) and \( g'(x) = -\sin x \).
The quotient rule will help us combine these derivatives to find the solution efficiently, even when the function appears complex.
When you have a function in the form \( u(x) = \frac{f(x)}{g(x)} \), the derivative, \( u'(x) \), can be calculated using the formula:
\[ u'(x) = \frac{f'(x)g(x) - f(x)g'(x)}{(g(x))^2}. \]
This formula requires you to differentiate both the numerator and the denominator separately.
In this particular problem, we are differentiating \( \frac{\sin x}{\cos x} \). Here, \( f(x) = \sin x \) and \( g(x) = \cos x \). Differentiating these gives \( f'(x) = \cos x \) and \( g'(x) = -\sin x \).
The quotient rule will help us combine these derivatives to find the solution efficiently, even when the function appears complex.
Analyzing the Tangent Function
The tangent function, \( \tan x \), is essential in calculus and trigonometry. It is often represented as the ratio of sine and cosine: \( \tan x = \frac{\sin x}{\cos x} \). This fundamental property is crucial when differentiating because it turns a trigonometric problem into a calculus problem involving fractions.
Because tangent is derived from a sine and cosine fraction, its behavior hinges on these two functions. For example:
Various calculus problems, like the one we're solving, require recognizing these relationships to find the derivative correctly.
Because tangent is derived from a sine and cosine fraction, its behavior hinges on these two functions. For example:
- \( \sin x \) increases from 0 to 1 in the first quadrant, contrasting with cosine, which decreases from 1 to 0.
- Both sine and cosine reach their extrema at \( x = \frac{\pi}{2} \), where sine equals 1 and cosine equals 0.
Various calculus problems, like the one we're solving, require recognizing these relationships to find the derivative correctly.
Mastering Calculus Problem Solving
Solving calculus problems requires a strategic approach. Whenever you encounter a differentiation problem like this one, having a clear framework is vital to guide you.
Here's a simple structure to help solve calculus problems effectively:
Here's a simple structure to help solve calculus problems effectively:
- Understand the problem: Clearly define what you're asked to find. In this case, we need to differentiate \( y = \tan x \).
- Choose the right method: Decide on the most appropriate technique for differentiation. The function's form as \( \frac{\sin x}{\cos x} \) signaled the use of the quotient rule.
- Apply the technique: Use the quotient rule formula, substituting the derivatives of the numerator and denominator.
- Simplify the result: Clean up the final expression. As seen in our exercise, simplification led to \( \sec^2 x \).
- Review and check: Double-check each step to ensure correctness and accuracy.