Chapter 3: Problem 49
Find the equation of the tangent line to \(y=x^{2}-2 x+2\) at the point \((1,1)\).
Short Answer
Expert verified
The equation of the tangent line is \(y = 1\).
Step by step solution
01
Identify the Function and Point
The given function is \(y = x^2 - 2x + 2\), and the point of interest is \((1, 1)\). We need the equation of a tangent line at this point.
02
Find the Derivative
To find the slope of the tangent line, differentiate the function with respect to \(x\). \[\frac{dy}{dx} = \frac{d}{dx}(x^2 - 2x + 2) = 2x - 2\]
03
Calculate the Slope of the Tangent Line
Evaluate the derivative at \(x = 1\) to find the slope of the tangent line:\[m = 2(1) - 2 = 0\]The slope at \((1, 1)\) is 0.
04
Write the Equation of the Tangent Line
Use the point-slope form of a line \(y - y_1 = m(x - x_1)\) with \((x_1, y_1) = (1, 1)\) and slope \(m = 0\):\[y - 1 = 0(x - 1)\]Simplifying this,\[y = 1\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative Calculation
Calculating the derivative of a function is essential to determine the behavior of the function at any given point. To find the derivative of a function, we use the rules of differentiation, which provide a way to compute the rate at which the function's value is changing. In this problem, the function given is \(y = x^2 - 2x + 2\).
To find its derivative, we differentiate each term separately:
To find its derivative, we differentiate each term separately:
- The derivative of \(x^2\) is \(2x\).
- The derivative of \(-2x\) is \(-2\).
- The derivative of a constant, 2, is 0.
Slope of Tangent Line
Once the derivative is calculated, finding the slope of the tangent line is straightforward. The derivative at a particular point gives us the exact slope of the function at that point. In this case, we need the slope where \(x = 1\).
By substituting \(x = 1\) into the derivative, \(2x - 2\), we get:
By substituting \(x = 1\) into the derivative, \(2x - 2\), we get:
- \(m = 2(1) - 2 = 0\)
Point-slope Form Equation
After determining the slope at a given point, we use the point-slope form to express the equation of the tangent line. The point-slope form is a simple way to write the equation of a line if you know one point on the line and the slope. It is expressed as:
- \(y - y_1 = m(x - x_1)\)
- \(y - 1 = 0(x - 1)\)
Differentiation
Differentiation is a fundamental concept in calculus that is used to compute the derivative of a function. It involves determining how a function changes as its input changes. This process allows us to find the slope of the function at any point, which is crucial for constructing tangent lines.
When you differentiate a function, you find the derivative, which is the formula for the function's slope at any point on its curve. In essence, differentiation provides a tool for analyzing and understanding the behavior of functions:
When you differentiate a function, you find the derivative, which is the formula for the function's slope at any point on its curve. In essence, differentiation provides a tool for analyzing and understanding the behavior of functions:
- Find instantaneous rates of change.
- Determine the slope of tangent lines to curves.
- Identify points of maximum or minimum on a graph.