Chapter 12: Problem 37
Let \(f(x, y)=x^{2} y /\left(x^{4}+y^{2}\right)\). (a) Show that \(f(x, y) \rightarrow 0\) as \((x, y) \rightarrow(0,0)\) along any straight line \(y=m x\). (b) Show that \(f(x, y) \rightarrow \frac{1}{2}\) as \((x, y) \rightarrow(0,0)\) along the parabola \(y=x^{2}\). (c) What conclusion do you draw?
Short Answer
Step by step solution
Substitution for Part (a)
Simplifying the Expression
Evaluating the Limit as x Approaches 0
Substitution for Part (b)
Simplifying the Expression for Part (b)
Evaluating the Limit for Part (b)
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
Limits establish the foundation for continuity and differentiability in calculus.
When working with a function like \( f(x, y) = \frac{x^2 y}{x^4 + y^2} \), the objective is to find if there's a single value that \( f \) approaches as \( (x, y) \) gets closer to \( (0,0) \).
The catch with multivariable functions is that points can be approached from different directions, unlike single-variable functions where you approach one point from either side.
To check for continuity or differentiability at a point in multivariable functions, assessing the limit is essential.
Path-dependent Limits
For example, while evaluating the limit of our function \( f(x, y) \) as \( (x, y) \rightarrow (0,0) \), the answer varied depending upon the path used for approaching \( (0,0) \).
- Along any line \( y = mx \), the limit of the function \( f(x, y) \) approached 0.
- But, along a parabola \( y = x^2 \), it reached \( \frac{1}{2} \).
Functions of Two Variables
Multivariable functions are all around us. For instance, the expression given in our exercise \( f(x, y) = \frac{x^2 y}{x^4 + y^2} \) describes a 3D surface, depicting how changes in \( x \) and \( y \) impact the result.
Limits and Continuity
A function is continuous at a point if the function's limit as it approaches that point equals the function's value at the point. With our multivariable function \( f(x, y) \), different paths to \( (0, 0) \) returned different results, implying no single approach toward one limit. This discrepancy means the function is not continuous at \( (0, 0) \).
- Check if a single limit value exists regardless of paths.
- If not, the function is likely discontinuous at that point.
Parabolas in Calculus
In our exercise, when analyzing the function \( f(x, y) \) along the parabola \( y = x^2 \), it reveals critical insights about its limit behavior when approaching the origin. Despite the zeroing nature when lines are used, a parabola leads us to find a different limit, \( \frac{1}{2} \).
Parabolas hence illustrate how curves often demonstrate different limits due to their inherent geometric properties, offering a more nuanced view than straight lines. Consequently, understanding parabolic behavior in calculus extends analytical skills and improves the comprehension of a function’s limit properties from diverse perspectives.