Chapter 12: Problem 18
In Problems 17-22, sketch the level curve \(z=k\) for the indicated values of \(k\). $$ z=\frac{x}{y}, k=-2,-1,0,1,2 $$
Short Answer
Expert verified
Sketch the lines for \( x = ky \) with \( k = -2, -1, 0, 1, 2 \) as their respective level curves.
Step by step solution
01
Understanding the Level Curve Equation
The expression given is \( z = \frac{x}{y} \). For a level curve, we fix \( z = k \) where \( k \) is a constant. Thus, the equation becomes \( \frac{x}{y} = k \). Rearranging this, we find \( x = ky \). For each value of \( k \), this represents a different line through the origin in the xy-plane.
02
Sketch for k = -2
Substituting \( k = -2 \) into \( x = ky \), we get \( x = -2y \). This equation represents a line through the origin with a slope of -2. The line will pass through points such as (0, 0), (-2, 1), and (2, -1). Sketch this line on a graph.
03
Sketch for k = -1
Substituting \( k = -1 \) into \( x = ky \), we get \( x = -y \). This represents a line with a slope of -1. The line will pass through points such as (0, 0), (-1, 1), and (1, -1). Sketch this line on the same graph.
04
Sketch for k = 0
Substituting \( k = 0 \) into \( x = ky \), we get \( x = 0 \). This is the y-axis itself. The line represents all points where \( x = 0 \), like (0, 1), (0, -1), and (0, 0). Sketch this vertical line.
05
Sketch for k = 1
Substituting \( k = 1 \) into \( x = ky \), we get \( x = y \). This is a line with a slope of 1. The line will pass through points such as (0, 0), (1, 1), and (-1, -1). Sketch this line on the same graph.
06
Sketch for k = 2
Substituting \( k = 2 \) into \( x = ky \), we get \( x = 2y \). This is a line with a slope of 2. The line will pass through points such as (0, 0), (2, 1), and (-2, -1). Sketch this line on the same graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Multivariable Calculus
Multivariable calculus extends the concepts of calculus from dealing with functions of a single variable to functions of multiple variables. In this context, the function given is \( z = \frac{x}{y} \), where both \( x \) and \( y \) are independent variables. The variable \( z \) depends on both \( x \) and \( y \), creating a surface in three-dimensional space.
Level curves are a vital concept in multivariable calculus. They represent the intersection of a surface in three dimensions with a horizontal plane, resulting in a curve or a set of curves on a two-dimensional plane. For our function \( z = \frac{x}{y} \), level curves are found by setting \( z \) to a constant, \( k \), which simplifies the three-dimensional problem to two dimensions, as in \( \frac{x}{y} = k \).With this approach,
Level curves are a vital concept in multivariable calculus. They represent the intersection of a surface in three dimensions with a horizontal plane, resulting in a curve or a set of curves on a two-dimensional plane. For our function \( z = \frac{x}{y} \), level curves are found by setting \( z \) to a constant, \( k \), which simplifies the three-dimensional problem to two dimensions, as in \( \frac{x}{y} = k \).With this approach,
- We can directly visualize changes in \( z \).
- We gain insights into the behavior of the function on the xy-plane.
Coordinate Geometry
Coordinate geometry provides a bridge between algebraic equations and geometric figures through the coordinate plane. In this exercise, we use the equation \( x = ky \) to represent lines on the coordinate plane. The equation is derived from fixing \( z = k \) in the expression \( z = \frac{x}{y} \).
- Each value of \( k \) gives us a linear equation \( x = ky \).
- Geometrically, this represents a line through the origin (0,0), with slope \( k \).
Graphing Techniques
Graphing techniques simplify the visualization of mathematical relationships. For the given function \( z = \frac{x}{y} \), each level curve \( x = ky \) is effectively a straight line graph.By plotting these:- Start by choosing specific points that satisfy the equation for each \( k \).- Typical points include the origin and points where either \( x \) or \( y \) is set to 1, making calculations straightforward.- For instance, \( k = -2 \) leads to points like (0, 0), (-2, 1), and (2, -1).Once points are determined, you connect them to form the line. Repeating for every \( k \) value results in a series of lines
- Through the origin.
- With varying slopes depending on \( k \).
Linear Equations
Linear equations are straightforward polynomial equations of the first degree, typically written as \( ax + by = c \). For our function \( z = \frac{x}{y} \), by setting \( z = k \), we express it in the form \( x = ky \), a linear relation.These particular equations of the form \( x = ky \):
- Describe lines through the origin on the coordinate plane.
- Reveal the slope directly as \( k \), the coefficient of \( y \).