Chapter 12: Problem 17
Find the directional derivative of \(f(x, y, z)=x y+z^{2}\) at \((1,1,1)\) in the direction toward \((5,-3,3)\).
Short Answer
Expert verified
The directional derivative is \(\frac{2}{3}\).
Step by step solution
01
Find the Gradient of f
The gradient of the function \( f(x, y, z) = xy + z^2 \) is computed as the vector of partial derivatives. Thus, \( abla f(x, y, z) = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right) \). Calculating the partial derivatives, we get:\[ \frac{\partial f}{\partial x} = y, \quad \frac{\partial f}{\partial y} = x, \quad \frac{\partial f}{\partial z} = 2z \]Therefore, the gradient is:\[ abla f(x, y, z) = (y, x, 2z) \]
02
Evaluate the Gradient at a Point
Now we evaluate the gradient \( abla f(x, y, z) = (y, x, 2z) \) at the point \((1, 1, 1)\). Substitute \(x = 1\), \(y = 1\), and \(z = 1\) to get:\[ abla f(1, 1, 1) = (1, 1, 2) \]
03
Find the Direction Vector and Normalize It
The direction vector is given by the difference between \((5, -3, 3)\) and \((1, 1, 1)\), which is:\[ \vec{v} = (5 - 1, -3 - 1, 3 - 1) = (4, -4, 2) \]To use this as a direction, it must be normalized. The magnitude of \(\vec{v}\) is:\[ \|\vec{v}\| = \sqrt{4^2 + (-4)^2 + 2^2} = \sqrt{16 + 16 + 4} = \sqrt{36} = 6 \]The normalized direction vector \(\vec{u}\) is:\[ \vec{u} = \left( \frac{4}{6}, \frac{-4}{6}, \frac{2}{6} \right) = \left( \frac{2}{3}, -\frac{2}{3}, \frac{1}{3} \right) \]
04
Compute the Directional Derivative
The directional derivative of \( f \) at \((1, 1, 1)\) in the direction of \(\vec{u}\) is given by the dot product of the gradient and \(\vec{u}\):\[ D_{\vec{u}} = abla f(1, 1, 1) \cdot \vec{u} = (1, 1, 2) \cdot \left( \frac{2}{3}, -\frac{2}{3}, \frac{1}{3} \right) \]Calculate this dot product:\[ D_{\vec{u}} = 1 \times \frac{2}{3} + 1 \times -\frac{2}{3} + 2 \times \frac{1}{3} = \frac{2}{3} - \frac{2}{3} + \frac{2}{3} = \frac{2}{3} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient
The gradient of a function is a vector that points in the direction of the greatest rate of increase of the function. If you imagine a mountain, the gradient points "uphill," showing you the steepest path to follow. For a scalar function \( f(x, y, z) \), the gradient is represented by \( abla f \) and is composed of partial derivatives, which are simply the derivative of the function with respect to each variable separately. - You can think of it as the combined slope of the function surface, calculated in multiple dimensions.- The gradient is crucial in optimization, helping find maximum or minimum values.- In our case, the gradient at (1, 1, 1) for \( f(x, y, z) = xy + z^2 \) is \( (1, 1, 2) \).This vector tells you how the function changes around the point \( (1,1,1) \), in each direction \( x, y, \) and \( z \).
Partial Derivatives
Partial derivatives are like regular derivatives but only apply to one variable at a time, keeping other variables constant. When you work with functions of multiple variables, partial derivatives help you understand how changes in one variable impact the function.
Understanding Partial Derivatives
- They give the slope of the tangent line to the curve of the function along the axis of the variable.- It reflects how sensitive a function is to a change in one variable while holding others fixed.For \( f(x, y, z) = xy + z^2 \), the partial derivatives are:- \( \frac{\partial f}{\partial x} = y \)- \( \frac{\partial f}{\partial y} = x \)- \( \frac{\partial f}{\partial z} = 2z \)These calculations help build the gradient vector, combining individual sensitivities.Normalized Vector
Normalization of a vector turns it into a unit vector, a vector with a length of one. If you have a vector and you want to keep its direction but make its size one, you normalize it.
Steps to Normalize a Vector
- Calculate the magnitude (length) of the vector.
- Divide each component of the vector by its magnitude.
Dot Product
The dot product, also known as the scalar product, is an operation that takes two vectors and returns a single number. It combines both vector magnitudes and the cosine of the angle between them.
Importance of Dot Product
- It determines how much one vector goes in the direction of another.
- A useful tool in physics and engineering for calculating work done, where force and displacement vectors are multiplied.