Chapter 11: Problem 14
Find the symmetric equations of the line through \((-5,7,-2)\) and perpendicular to both \(\langle 2,1,-3\rangle\) and \(\langle 5,4,-1\rangle\).
Short Answer
Expert verified
The symmetric equations are \(\frac{x+5}{11} = \frac{y-7}{-13} = \frac{z+2}{3}\).
Step by step solution
01
Find the Direction Vector
To find a direction vector for the line that is perpendicular to both vectors \(\langle 2,1,-3\rangle\) and \(\langle 5,4,-1\rangle\), we need to compute their cross product. The cross product \(\mathbf{v} \times \mathbf{w}\) for two vectors \(\mathbf{v} = \langle a_1, b_1, c_1 \rangle\) and \(\mathbf{w} = \langle a_2, b_2, c_2 \rangle\)\ is given by:\[\mathbf{v} \times \mathbf{w} = \langle b_1c_2 - c_1b_2, c_1a_2 - a_1c_2, a_1b_2 - b_1a_2 \rangle\]Applying this to our vectors:\[\langle 2,1,-3\rangle \times \langle 5,4,-1\rangle\]\[= \langle 1(-1) - (-3)4, (-3)5 - 2(-1), 2(4) - 1(5) \rangle\]\[= \langle -1 + 12, -15 + 2, 8 - 5 \rangle\]\[= \langle 11, -13, 3 \rangle\]Thus, the direction vector of the line is \(\langle 11, -13, 3 \rangle\).
02
Write the Symmetric Equations
The symmetric equations of a line are derived from the parametric equations of the line through a point \((x_0, y_0, z_0)\) with direction vector \(\langle a, b, c\rangle\). The parametric equations are:\[x = x_0 + at, \, y = y_0 + bt, \, z = z_0 + ct\]For the given point \((-5,7,-2)\) and direction vector \(\langle 11, -13, 3 \rangle\), the parametric equations are:\[x = -5 + 11t, \, y = 7 - 13t, \, z = -2 + 3t\]The symmetric equations eliminate the parameter \(t\) by setting it from each equation:\[\frac{x + 5}{11} = \frac{y - 7}{-13} = \frac{z + 2}{3}\]These are the symmetric equations of the line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a powerful mathematical tool used to find a vector that is perpendicular to two given vectors in three-dimensional space. It is particularly useful in physics and engineering to determine perpendicular directions. The result of a cross product is a vector, and its magnitude corresponds to the area of the parallelogram spanned by the original vectors. In the context of lines, we use the cross product to find a direction vector for a line that must be perpendicular to two given vectors. When you apply the cross product to two vectors, \(\mathbf{v} = \langle a_1, b_1, c_1 \rangle\) and \(\mathbf{w} = \langle a_2, b_2, c_2 \rangle\), the resulting vector is given by:
- \(b_1c_2 - c_1b_2\)
- \(c_1a_2 - a_1c_2\)
- \(a_1b_2 - b_1a_2\)
Directional Vector
The directional vector defined in a problem gives insight into the line's orientation in space. In mathematical terms, a directional vector represents the "direction" of a line. This is critical to understanding the orientation, as it gives parameters in 3D space that influence line equations. To illustrate, when you have a line passing through a point with a direction vector \(\langle a, b, c \rangle\), it implies that any movement along the line will follow these ratios:
- \(a\) units along the x-axis
- \(b\) units along the y-axis
- \(c\) units along the z-axis
Parametric Equations
Parametric equations are commonly used in mathematics to express the coordinates of the points that make up a curve or line, with respect to a parameter, typically denoted as \(tn\). They are a concise way to model relationships and movements along a line or curve in space. The general form for a line through a point \(( x_0, y_0, z_0 ) \), with a direction vector \(\langle a, b, c \rangle\), is:
- \(x = x_0 + at\)
- \(y = y_0 + bt\)
- \(z = z_0 + ct\)
Perpendicular Lines
Perpendicular lines are an iconic concept in geometry, signified by intersecting lines that meet at a 90-degree angle. This characteristic is pivotal in axes, creating grids, and defining shapes. But in vector terms, a line perpendicular to two vectors is represented by a directional vector derived through the cross product of the original two vectors. Redundancy occurs when two lines in a plane are perpendicular.
- If two lines are perpendicular, their respective direction vectors have a cross product with a magnitude indicative of the area covered by both.
- The result is a vector perpendicular to each, utilized to describe another line perpendicular to both original directions.