Chapter 11: Problem 1
Let \(\mathbf{a}=-3 \mathbf{i}+2 \mathbf{j}-2 \mathbf{k}, \quad \mathbf{b}=-\mathbf{i}+2 \mathbf{j}-4 \mathbf{k}\), and \(\mathbf{c}=7 \mathbf{i}+3 \mathbf{j}-4 \mathbf{k}\). Find each of the following: (a) \(\mathbf{a} \times \mathbf{b}\) (b) \(\mathbf{a} \times(\mathbf{b}+\mathbf{c})\) (c) \(\mathbf{a} \cdot(\mathbf{b}+\mathbf{c})\) (d) \(\mathbf{a} \times(\mathbf{b} \times \mathbf{c})\)
Short Answer
Step by step solution
Compute \( \mathbf{a} \times \mathbf{b} \)
Compute \( \mathbf{b} + \mathbf{c} \)
Compute \( \mathbf{a} \times (\mathbf{b}+\mathbf{c}) \)
Compute \( \mathbf{a} \cdot (\mathbf{b} + \mathbf{c}) \)
Compute \( \mathbf{b} \times \mathbf{c} \)
Compute \( \mathbf{a} \times (\mathbf{b} \times \mathbf{c}) \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
To compute the cross product of vectors \(\mathbf{a}\) and \(\mathbf{b}\):
- Arrange the vectors in a determinant: \[ \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix} \]
- Calculate the determinant by finding the sum of the products of the diagonals.
- Express the result as \( c = c_1 \mathbf{i} + c_2 \mathbf{j} + c_3 \mathbf{k} \).
Dot Product
To calculate the dot product of \(\mathbf{a}\) and \(\mathbf{b}\):
- Multiply corresponding components together: \( a_1 \cdot b_1 \), \( a_2 \cdot b_2 \), \( a_3 \cdot b_3 \).
- Add those products up: \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \).
where \(|\mathbf{a}|\) and \(|\mathbf{b}|\) are magnitudes of \(\mathbf{a}\) and \(\mathbf{b}\), and \(\theta\) is the angle between them. If the dot product is zero, it indicates the vectors are orthogonal.
Determinants
Here’s how they work in a 3x3 matrix:
- Consider a 3x3 matrix: \( \begin{vmatrix} a & b & c \ d & e & f \ g & h & i \end{vmatrix} \)
- The determinant is calculated using: \( a(ei - fh) - b(di - fg) + c(dh - eg) \)
In vector calculus, determinants are invaluable in computing cross products. This is because the cross product of two vectors is actually the determinant of a matrix that includes the unit vectors \(\mathbf{i}\), \(\mathbf{j}\), and \(\mathbf{k}\) as its first row, followed by the two vectors in its subsequent rows.