Chapter 10: Problem 26
Let \(r=f(\theta)\), where \(f\) is continuous on the closed interval \([\alpha, \beta]\). Derive the following formula for the length \(L\) of the corresponding polar curve from \(\theta=\alpha\) to \(\theta=\beta\). $$ L=\int_{\alpha}^{\beta} \sqrt{[f(\theta)]^{2}+\left[f^{\prime}(\theta)\right]^{2}} d \theta $$
Short Answer
Step by step solution
Understand the problem
Identify the polar coordinates
Compute the derivatives
Use the arc length formula
Simplify the expression
Derive the integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arc Length Formula
\[L = \int_{\alpha}^{\beta} \sqrt{[f(\theta)]^{2} + \left[f^{\prime}(\theta)\right]^{2}} \, d\theta\]
This formula tells us that to find the length \(L\) of a polar curve from \(\theta = \alpha\) to \(\theta = \beta\), we integrate the square root of the sum of the squares of two terms, \([f(\theta)]^{2}\) and \([f'(\theta)]^{2}\), over the interval. Each part of the formula captures different components of the curve's geometry, and combined, they provide a holistic measure of length.
Polar Coordinates
Within this system, any point is described using \(r\), the distance from the origin, and \(\theta\), the angle measured from the positive x-axis. For a curve defined by \(r = f(\theta)\), \(r\) varies as \(\theta\) changes, tracing the curve as \(\theta\) goes from \(\alpha\) to \(\beta\).
Helpful formulas in this coordinate system include:
- \(x = r \cos(\theta)\)
- \(y = r \sin(\theta)\)
Calculus Derivation
We begin by translating \(r = f(\theta)\) into the Cartesian format:
- \(x = f(\theta) \cos(\theta)\)
- \(y = f(\theta) \sin(\theta)\)
\[L = \int \sqrt{\left(\frac{dx}{d\theta}\right)^2 + \left(\frac{dy}{d\theta}\right)^2} \, d\theta\]
This approach allows us to find precise changes along \(x\) and \(y\) as \(\theta\) changes, laying the groundwork to evaluate the integral representing the curve's length.
Product Rule
\[\frac{d}{d\theta}[u(\theta)v(\theta)] = u'(\theta)v(\theta) + u(\theta)v'(\theta)\]
In the context of deriving the polar arc length, the product rule is crucial when differentiating:
- \(x = f(\theta) \cos(\theta)\)
- \(y = f(\theta) \sin(\theta)\)
- \(\frac{dx}{d\theta} = f'(\theta) \cos(\theta) - f(\theta) \sin(\theta)\)
- \(\frac{dy}{d\theta} = f'(\theta) \sin(\theta) + f(\theta) \cos(\theta)\)