Chapter 1: Problem 54
What relationship between \(a, b\), and \(c\) must hold if \(x^{2}+a x+y^{2}+b y+c=0\) is the equation of a circle?
Short Answer
Expert verified
The relationship is that \( c = \frac{a^2}{4} + \frac{b^2}{4} - r^2 \), where \( r \) is the radius.
Step by step solution
01
Recognizing the General Equation for a Circle
The general equation for a circle in the coordinate plane with center at \(h, k\) and radius \(r\) is given by \[ (x - h)^2 + (y - k)^2 = r^2 \].Expanding this equation, we get \[ x^2 - 2hx + h^2 + y^2 - 2ky + k^2 = r^2 \].Rearrange the terms to obtain: \[ x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 \].This can be written in the form \x^2 + y^2 + Ax + By + C = 0\, where \(A = -2h\), \(B = -2k\), and \(C = h^2 + k^2 - r^2\).
02
Comparing Given Equation with Circle Equation
The given equation is \[ x^2 + ax + y^2 + by + c = 0 \].Comparing this with \[ x^2 + y^2 + Ax + By + C = 0 \],we can see that \(a = A\), \(b = B\), and \(c = C\). Therefore, \(a, b\), and \(c\) must satisfy \(a = -2h\), \(b = -2k\), and \(c = h^2 + k^2 - r^2\).
03
Analyzing the Relationship for a Real Circle
To ensure that the equation represents a real circle, the term \(h^2 + k^2 - r^2\) should be non-negative since it corresponds to \(c\). Rewrite the relationship using squares: \(a^2/4 + b^2/4 \) gives \(h^2 + k^2\), meaning that:\[ c = h^2 + k^2 - r^2 \] implies \[ r^2 = h^2 + k^2 - c \].Thus, for a real circle, this requires that \(h^2 + k^2 \geq c\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Circle Equation
In coordinate geometry, the equation of a circle is a fundamental concept. At its core, the circle equation is defined in the form \[ (x - h)^2 + (y - k)^2 = r^2 \] where
- \( h, k \) are the coordinates of the center of the circle.
- \( r \) is the radius.
Center and Radius of a Circle
The center and radius are critical components of a circle's equation. From the standard circle equation \[ (x - h)^2 + (y - k)^2 = r^2 \], the center \( (h, k) \) gives the exact position of the circle on the coordinate plane. The radius \( r \) determines the size, representing the distance from the center to any point on the circle. This equation implies that if you know \( h, k, \) and \( r \), you can completely describe the circle’s size and location. When this equation is expanded to the form \[ x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 \], comparing terms allows us to recognize the center as \( h = -A/2 \) and \( k = -B/2 \). Additionally, solving for \( r \) involves the relationship \( r^2 = h^2 + k^2 - c \), connecting directly to the circle's dimensions.
Algebraic Manipulation
Algebraic manipulation is an essential skill for working with the equation of a circle, especially when transforming it into a more useful form. Initially, the circle's equation may not look like the conventional form. However, by expanding and rearranging the terms, you bring it into a recognizable format. Consider the equation \[ x^2 + y^2 + ax + by + c = 0 \].To identify \( h, k, \) and \( r \), compare it to \[ x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 \].To solve for the coefficients,
- \( a = -2h \)
- \( b = -2k \)
- \( c = h^2 + k^2 - r^2 \)
Condition for Real Circle
To ensure an equation truly represents a circle, not just any set of points, certain conditions must hold. The crucial aspect revolves around ensuring a non-negative radius \( r \), since a circle with a negative or imaginary radius isn't possible. For the equation \[ x^2 + ax + y^2 + by + c = 0 \]identifying it as a real circle involves verifying \[ h^2 + k^2 - r^2 \geq 0 \].This can be rewritten in terms of given parameters as: \[ a^2/4 + b^2/4 \geq c \]. This inequality must be satisfied to validate that the circle's equation reflects a tangible geometric entity. If this condition holds, it confirms the equation translates to an actual circle with a specified center and positive radius in the coordinate plane.