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Find the sum of each of the following series by recognizing how it is related to something familiar. (a) \(x-x^{2}+x^{3}-x^{4}+x^{5}-\cdots\) (b) \(\frac{1}{2 !}+\frac{x}{3 !}+\frac{x^{2}}{4 !}+\frac{x^{3}}{5 !}+\cdots\) (c) \(2 x+\frac{4 x^{2}}{2}+\frac{8 x^{3}}{3}+\frac{16 x^{4}}{4}+\cdots\)

Short Answer

Expert verified
(a) \(\frac{x}{1+x}\). (b) \(\frac{e^x - 1 - x}{x^2}\). (c) \(-\ln(1+2x)\).

Step by step solution

01

Identify the Type of Series for Part (a)

The series given is of the form \(x - x^2 + x^3 - x^4 + x^5 - \cdots\). This is a geometric series where the first term \(a = x\) and the common ratio \(r = -x\).
02

Determine Sum of Infinite Geometric Series for Part (a)

The formula for the sum \(S\) of an infinite geometric series is \(S = \frac{a}{1-r}\), where \(|r| < 1\). For our series, \(a = x\) and \(r = -x\), so the sum is \(S = \frac{x}{1-(-x)} = \frac{x}{1+x}\).
03

Identify the Pattern for Part (b)

The series is \(\frac{1}{2 !} + \frac{x}{3 !} + \frac{x^{2}}{4 !} + \cdots\), which resembles an exponential series shifted by one index. It can be rewritten as \(\sum_{n=2}^{\infty} \frac{x^{n-2}}{n!}\).
04

Relate Part (b) to Known Exponential Series

The series \(\sum_{n=0}^{\infty} \frac{x^{n}}{n!}\) is the expansion of \(e^x\). Therefore, \(\sum_{n=2}^{\infty} \frac{x^{n-2}}{n!} = \frac{e^x - 1 - x}{x^2}\), where terms for \(n=0\) and \(n=1\) are subtracted.
05

Factorial and Fraction Simplification for Part (c)

Consider \(2x + \frac{4x^2}{2} + \frac{8x^3}{3} + \cdots\), which can be rewritten as \(\sum_{n=1}^{\infty} \frac{2^n x^n}{n}\). This resembles the series \(-\ln(1-r)\) where \(r = -2x\).
06

Use Logarithmic Series for Part (c)

The sum of the series \(\sum_{n=1}^{\infty} \frac{r^n}{n} = -\ln(1-r)\), applies. Setting \(r = -2x\), we get \(-\ln(1+2x)\). Therefore, this series sums to \(-\ln(1+2x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
Geometric series are a fundamental concept in calculus and algebra. A geometric series is a series of the form \( a + ar + ar^2 + ar^3 + \cdots \), where each term increases by a common ratio \( r \). The first term is denoted by \( a \). To find the sum of an infinite geometric series, you need to ensure that \(|r| < 1\). If this condition is met, the sum \( S \) of the series can be determined using the formula:
  • \( S = \frac{a}{1 - r} \)
This formula gives you a powerful tool to sum an entire infinite series with just a few calculations by recognizing the first term and common ratio. It's crucial, however, to verify that the series actually converges by checking the condition \(|r| < 1\). Otherwise, the series would not have a finite sum. In the example given in the exercise, the series \( x - x^2 + x^3 - x^4 + \cdots \) is identified as a geometric series where \( a = x \) and \( r = -x \). Based on the context of the exercise, when \(|x| < 1\), the series converges to \( \frac{x}{1+x} \). This demonstrates how identifying a geometric pattern allows us to simplify complex problems dramatically.
Exponential Series
An exponential series is directly related to the concept of the exponential function, most commonly symbolized by \( e^x \). This type of series plays a critical role in calculus, particularly in solving differential equations and modeling growth processes. The standard exponential series is given by
  • \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \)
which represents \( e^x \). Each term in this series is formed by raising \( x \) to successive powers and dividing by the factorial of that power. This series converges for all real numbers \( x \).
In the exercise, the series \( \frac{1}{2!} + \frac{x}{3!} + \frac{x^2}{4!} + \cdots \) is identified as a shifted exponential series. By rewriting it as \( \sum_{n=2}^{\infty} \frac{x^{n-2}}{n!} \), it relates directly back to the exponential series for \( e^x \). However, some terms are missing (those corresponding to \( n = 0 \) and \( n = 1 \)), so their contributions \( 1 \) and \( x \) are subtracted, resulting in the expression \( \frac{e^x - 1 - x}{x^2} \). Understanding these shifting patterns is vital for accurately applying exponential functions to real-world problems.
Logarithmic Series
Logarithmic series are used to express logarithmic functions as infinite sums and have numerous applications in mathematics and the sciences. The basic form of a logarithmic series is:
  • \( \sum_{n=1}^{\infty} \frac{r^n}{n} = -\ln(1-r) \)
for \(|r| < 1\). This expression allows us to approximate the natural logarithm of expressions close to 1, which is particularly useful in calculus. In the exercise, the series \( 2x + \frac{4x^2}{2} + \frac{8x^3}{3} + \cdots \) simplifies to \( \sum_{n=1}^{\infty} \frac{(2x)^n}{n} \), showcasing its resemblance to the logarithmic series with \( r = -2x \). By applying the logarithm property, it leads to the solution \( -\ln(1+2x) \). These insights reveal the power of recognizing a pattern within series, enabling one to solve seemingly complex series by relating them to familiar logarithmic expressions. With a strong grasp of these natural patterns, students can tackle a wide range of mathematical problems more efficiently.

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