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An explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges or diverges, and, if it converges, find \(\lim _{n \rightarrow \infty} a_{n}\). $$ a_{n}=2+(0.99)^{n} $$

Short Answer

Expert verified
The sequence converges to 2.

Step by step solution

01

Calculate the First Term

Substitute \(n = 1\) into the given formula:\[ a_1 = 2 + (0.99)^{1} = 2 + 0.99 = 2.99 \]So, the first term \(a_1 = 2.99\).
02

Calculate the Second Term

Substitute \(n = 2\) into the given formula:\[ a_2 = 2 + (0.99)^{2} = 2 + 0.9801 = 2.9801 \]So, the second term \(a_2 = 2.9801\).
03

Calculate the Third Term

Substitute \(n = 3\) into the given formula:\[ a_3 = 2 + (0.99)^{3} = 2 + 0.970299 = 2.970299 \]So, the third term \(a_3 = 2.970299\).
04

Calculate the Fourth Term

Substitute \(n = 4\) into the given formula:\[ a_4 = 2 + (0.99)^{4} = 2 + 0.96059601 = 2.96059601 \]So, the fourth term \(a_4 = 2.96059601\).
05

Calculate the Fifth Term

Substitute \(n = 5\) into the given formula:\[ a_5 = 2 + (0.99)^{5} = 2 + 0.95099005 = 2.95099005 \]So, the fifth term \(a_5 = 2.95099005\).
06

Determine Convergence or Divergence

Examine the expression \( (0.99)^n \). Since \(0.99\) is less than 1, \( (0.99)^n \) approaches 0 as \( n \rightarrow \infty \). Thus, \(a_n = 2 + (0.99)^n\) converges to 2.
07

Find the Limit as n Approaches Infinity

Since we have determined the sequence converges, calculate:\[ \lim_{n \to \infty} a_n = 2 + \lim_{n \to \infty} (0.99)^n = 2 + 0 = 2 \],so the limit is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Explicit Formula for Sequence
An explicit formula for a sequence provides a direct way to find any term in the sequence without having to compute all the preceding terms. In our example, the explicit formula is given as \( a_{n} = 2 + (0.99)^{n} \). This allows us to calculate, say, \( a_{5} \) directly, by simply substituting \( n = 5 \) into the equation. This approach is beneficial because:
  • It saves time and effort, as recalculating every term from the beginning is not necessary.
  • It offers a clear pattern or rule for generating sequence terms.
  • It provides insight into the behavior of the sequence as \( n \) increases.
In general, explicit formulas help us understand how the terms in a sequence progress, and they are particularly useful in mathematical modeling and analysis.
Limit of a Sequence
The limit of a sequence helps us understand the behavior of a sequence as the term numbers get indefinitely large (i.e., \( n \rightarrow \infty \)). With our example, \( a_{n} = 2 + (0.99)^{n} \), we're interested in what happens when \( n \) becomes very large. Observe here that \( (0.99)^n \) gets smaller and smaller as \( n \) increases because any number between 0 and 1 raised to a high power tends to zero. Thus, \[ \lim_{n \to \infty} (0.99)^n = 0 \]and consequently,\[ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \left( 2 + (0.99)^n \right) = 2 + 0 = 2 \]This means the sequence approaches the value 2 as \( n \) gets larger. Understanding limits is crucial because it provides a steady point, or asymptote, that a sequence gravitates towards, which can simplify making future predictions or analyses.
Convergent Sequence
A sequence is termed convergent if it approaches a specific limit as \( n \) goes to infinity. In our case, the sequence \( \{a_{n}\} = \{2 + (0.99)^{n}\} \) converges to the number 2. A few characteristics of convergent sequences include:
  • The terms get closer to a particular value, known as the limit, as \( n \) increases.
  • There is a point after which all terms of the sequence remain arbitrarily close to the limit.
  • The absolute difference between terms and their limit becomes smaller with larger \( n \).
For our sequence, since the number added to 2, namely \( (0.99)^{n} \), becomes negligible when \( n \) is large, the terms effectively approach 2. Recognizing convergent sequences helps with defusing complicated calculations and understanding stability in dynamic systems. This stability signifies that beyond a certain number of terms, the sequence remains virtually unchanging, which is a powerful concept in mathematical calculations.

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