/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Find the length of the indicated... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the length of the indicated curve. \(y=\cosh x\), between \(x=0\) and \(x=4\)

Short Answer

Expert verified
The length of the curve is approximately 27.29.

Step by step solution

01

Recall the formula for arc length

The formula to find the arc length of a curve given by a function \(y = f(x)\) from \(x = a\) to \(x = b\) is \( L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2} \, dx \). For our problem, \(a = 0\) and \(b = 4\).
02

Differentiate the function

Find \( \frac{dy}{dx} \) for \( y = \cosh x \). The derivative \( \frac{dy}{dx} = \sinh x \) since the derivative of \( \cosh x \) is \( \sinh x \).
03

Substitute into the arc length formula

The arc length formula becomes \( L = \int_{0}^{4} \sqrt{1 + (\sinh x)^2} \, dx \).
04

Simplify the integrand

Use the identity \( \cosh^2 x - \sinh^2 x = 1 \) to simplify \( \sqrt{1 + \sinh^2 x} \). It becomes \( \sqrt{\cosh^2 x} \), which simplifies to \( \cosh x \) since \( \cosh x > 0 \) for all \(x\).
05

Set up the integral

The integral now is \( L = \int_{0}^{4} \cosh x \, dx \).
06

Compute the integral

Integrate \( \cosh x \) to get \( L = [\sinh x]_{0}^{4} \).
07

Evaluate the definite integral

Substitute the limits into the integral result: \( L = \sinh(4) - \sinh(0) \).
08

Calculate the values

Calculate \( \sinh(4) = \frac{e^4 - e^{-4}}{2} \) and \( \sinh(0) = 0 \). Therefore, \( L = \sinh(4) \approx 27.2899 \).
09

Conclusion

The length of the curve \( y = \cosh x \) from \( x = 0 \) to \( x = 4 \) is approximately 27.29.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Functions
Hyperbolic functions are analogs to the trigonometric functions but for the hyperbola, just as trigonometric functions relate to the circle. The two primary hyperbolic functions are the hyperbolic sine, \( \sinh x \), and the hyperbolic cosine, \( \cosh x \). These functions have similar properties to sine and cosine, yet they involve exponential functions:
  • \( \sinh x = \frac{e^x - e^{-x}}{2} \)
  • \( \cosh x = \frac{e^x + e^{-x}}{2} \)
One fundamental identity, similar to the Pythagorean identity for sine and cosine, is \( \cosh^2 x - \sinh^2 x = 1 \). This identity was pivotal in simplifying the original arc length problem. Hyperbolic functions are used in many areas of calculus, especially where growth rates and curves are essential, such as in hyperbolic geometry and engineering scenarios. They are also invaluable in solving certain types of differential equations.
Definite Integral
The definite integral allows you to calculate the accumulation of quantities, like areas under a curve. It is expressed as \( \int_{a}^{b} f(x) \, dx \), where \( f(x) \) is your function and \( a \) and \( b \) are the limits of integration. With definite integrals, you get a specific numerical value, representing the accumulated area or "net change."
In the context of finding the arc length of the curve \( y = \cosh x \) from \( x = 0 \) to \( x = 4 \), the definite integral is used to sum up infinitely small line segments along the curve. The specific integral used was \( \int_{0}^{4} \cosh x \, dx \), which gave the total length of the hyperbolic cosine curve over the interval. This provides a real-world application of definite integrals in calculating lengths, areas, and other extensive properties.
Derivative Calculus
Derivative calculus is all about understanding how a function changes. It involves taking the derivative, which tells you the slope or rate of change at any point in the function. For \( y = \cosh x \), the derivative \( \frac{dy}{dx} \) is \( \sinh x \).
This is because the derivative of \( \cosh x \) naturally leads to \( \sinh x \). Derivatives are essential for finding instantaneous rates of change and are crucial in the formula for calculating arc length, as in the given problem. Here, knowing the derivative \( \sinh x \) was a key step before substituting into the arc length formula. Derivatives help in understanding the overarching behavior of functions, whether they are increasing, decreasing, or constant over certain intervals.
Calculus Identities
Calculus identities are fundamental equations that hold true for all variables involved and form the backbone of many calculations. An example is the identity \( \cosh^2 x - \sinh^2 x = 1 \), which is particularly useful when working with hyperbolic functions. This identity was used to simplify the expression under the integral in the arc length problem.
In calculus, such identities save time and make for more efficient problem-solving by reducing complex expressions into simpler forms. These include Pythagorean identities for trigonometric functions, basic derivatives and integrals, and hyperbolic identities, among others. Understanding these identities is essential as they frequently appear in exams and practical applications, facilitating easier manipulation and integration of functions. Identifying and effectively using calculus identities often simplifies the underlying mathematics, allowing one to focus on the broader problem at hand.

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Most popular questions from this chapter

A bucket weighing 100 pounds is filled with sand weighing 500 pounds. A crane lifts the bucket from the ground to a point 80 feet in the air at a rate of 2 feet per second, but sand simultaneously leaks out through a hole at 3 pounds per second. Neglecting friction and the weight of the cable, determine how much work is done. Hint: Begin by estimating \(\Delta W\), the work required to lift the bucket from \(y\) to \(y+\Delta y\).

Use an \(x\) -integration to find the length of the segment of the line \(y=2 x+3\) between \(x=1\) and \(x=3 .\) Check by using the distance formula.

Use a \(y\) -integration to find the length of the segment of the line \(2 y-2 x+3=0\) between \(y=1\) and \(y=3 .\) Check by using the distance formula.

A company monitors the total impurities in incoming batches of chemicals. The PDF for total impurity \(X\) in a batch, measured in parts per million (PPM), has PDF \(f(x)=\) \(k x^{2}(200-x)^{8}, 0 \leq x \leq 200\) (a) Find the value of \(k\) that makes this a valid PDF. (b) The company does not accept batches whose total impurity is 100 or above. What is the probability that a batch is not accepted? (c) Find the expected value of the total impurity in PPM. (d) Find the \(\operatorname{CDF} F(x)\). (e) Let \(Y\) denote the total impurity in percent, rather than in PPM. What is the CDF of \(Y\) ?

A force of 6 pounds is required to keep a spring stretched \(\frac{1}{2}\) foot beyond its normal length. Find the value of the spring constant and the work done in stretching the spring \(\frac{1}{2}\) foot beyond its natural length.

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