Chapter 5: Problem 51
, use the Substitution Rule for Definite Integrals to evaluate each definite integral. $$ \int_{0}^{1} x \sin \left(\pi x^{2}\right) d x $$
Short Answer
Expert verified
The value of the integral is \( \frac{1}{\pi} \).
Step by step solution
01
Identify the substitution
We start by identifying the substitution needed to simplify the integral. Notice that inside the sine function, we have \(\pi x^2\). Thus, we set \(u = \pi x^2\). Calculate the derivative of \(u\) with respect to \(x\) which gives \(du = 2\pi x \, dx\).
02
Solve for dx
From \(du = 2\pi x \, dx\), we express \(dx\) in terms of \(du\): \(dx = \frac{du}{2\pi x}\).
03
Change limits of integration
When \(x = 0\), \(u = \pi (0)^2 = 0\). When \(x = 1\), \(u = \pi (1)^2 = \pi\). Therefore, the new limits of integration for \(u\) are from 0 to \(\pi\).
04
Substitute into the integral
Substitute \(u\) and \(dx\) into the original integral. The integral becomes: \[\int_{0}^{\pi} \frac{x}{x} \sin(u) \frac{du}{2\pi} = \int_{0}^{\pi} \frac{1}{2\pi} \sin(u) \, du\]
05
Evaluate the new integral
This integral can be directly evaluated: \[\int_{0}^{\pi} \frac{1}{2\pi} \sin(u) \, du = \left[ -\frac{1}{2\pi} \cos(u) \right]_{0}^{\pi}\]For \(u = \pi\), \(\cos(\pi) = -1\). For \(u = 0\), \(\cos(0) = 1\).
06
Calculate the definite integral
Substitute the upper and lower limits into the evaluated function:\[\left[ -\frac{1}{2\pi} (-1) \right] - \left[ -\frac{1}{2\pi} (1) \right]\]Simplifying this expression, we get:\[\frac{1}{2\pi} + \frac{1}{2\pi} = \frac{2}{2\pi} = \frac{1}{\pi}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals are a fundamental concept in calculus, often used to determine the area under a curve between two points. Unlike indefinite integrals, which represent families of functions or antiderivatives, definite integrals result in a specific numerical value. In definite integrals, limits of integration are specified, giving a boundary for evaluation. These limits are depicted as numbers written at the lower and upper bounds of the integral symbol. For instance, \[ \int_{a}^{b} f(x) \, dx \]where \(a\) and \(b\) are the limits, defines the definite integral of the function \(f(x)\) from \(x = a\) to \(x = b\).
Using definite integrals involves several steps:
Using definite integrals involves several steps:
- Finding the antiderivative of the function, called the indefinite integral.
- Applying the limits of integration to this antiderivative.
- Subtracting the lower limit value from the upper limit value.
Trigonometric Substitution
Trigonometric substitution is a calculus technique used when faced with integrals involving square roots or quadratic expressions. This method simplifies the integral by substituting a trigonometric function for a variable, effectively transforming a complex expression into an easier trigonometric integral.
When using trigonometric substitution, there are typical substitutions:
When using trigonometric substitution, there are typical substitutions:
- For \( \sqrt{a^2 - x^2} \), use \( x = a \sin \theta \).
- For \( \sqrt{a^2 + x^2} \), use \( x = a \tan \theta \).
- For \( \sqrt{x^2 - a^2} \), use \( x = a \sec \theta \).
Calculus Techniques
In calculus, various techniques are employed to tackle integrals, each suited to different functions. Some common methods include:
- Substitution Rule: Simplifies an integral by changing variables. We introduce a new variable, \(u\), to express the integral in terms of \(u\) rather than \(x\).
- Integration by Parts: Useful when integrating the product of two functions. This technique is based on the product rule for differentiation.
- Partial Fraction Decomposition: Used for rational functions. It involves expressing the function as a sum of simpler fractions, making the integral easier to solve.
Integral Evaluation
Evaluating integrals is the process of finding a numerical value for a definite integral. This requires understanding the function, applying appropriate techniques, and calculating the antiderivatives.
The evaluation follows these steps:
The evaluation follows these steps:
- Identify a method for integration. This could be substitution, integration by parts, etc.
- Perform the integration by calculating the antiderivative of the transformed function.
- Apply the limits of integration to the antiderivative.
- Subtract the lower limit evaluation from the upper limit evaluation to find the result.