Chapter 5: Problem 26
Prove the following formula for a geometric sum: $$ \sum_{k=0}^{n} a r^{k}=a+a r+a r^{2}+\cdots+a r^{n}=\frac{a-a r^{n+1}}{1-r}(r \neq 1) $$
Short Answer
Expert verified
The geometric sum formula is valid and is \( S = \frac{a - ar^{n+1}}{1-r} \) when \( r \neq 1 \).
Step by step solution
01
Define the Geometric Series
Consider the finite geometric series given as \( S = a + ar + ar^2 + \cdots + ar^n \). Our goal is to find an expression for this sum.
02
Multiply the Series by the Common Ratio
Multiply the entire series \( S \) by the common ratio \( r \):\[ rS = ar + ar^2 + ar^3 + \cdots + ar^{n+1} \].
03
Subtract the Two Equations
Subtract the equation for \( rS \) from the equation for \( S \):\[ S - rS = (a + ar + ar^2 + \cdots + ar^n) - (ar + ar^2 + ar^3 + \cdots + ar^{n+1}) = a - ar^{n+1} \].
04
Factor and Simplify
After subtraction, the left side becomes \( S(1-r) \). Thus, \\[ S(1-r) = a - ar^{n+1} \], hence, \\[ S = \frac{a - ar^{n+1}}{1-r} \].
05
Ensure the Validity Condition
The formula is valid only when \( r eq 1 \), as dividing by zero is undefined.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Sum Formula
The geometric sum formula provides a way to calculate the sum of a series of terms where each term is a constant multiple of the previous one. This type of series, known as a geometric series, can be expressed as \( S = a + ar + ar^2 + \cdots + ar^n \). Here, \( a \) represents the first term and \( r \) is the common ratio. The formula for calculating this sum is:\[ S = \frac{a - ar^{n+1}}{1-r} \]This formula is particularly useful because it simplifies the process of summing terms exponentially growing or decreasing at a constant rate. To make sure we use this equation correctly, note that it applies only when \( r eq 1 \), because if \( r = 1 \), the series becomes a simple arithmetic sum.
Proof by Subtraction
To derive the geometric sum formula, a method called proof by subtraction is used. This involves manipulating the series algebraically to isolate the desired expression. Here’s how it works:
- Start with the original sum \( S = a + ar + ar^2 + \cdots + ar^n \).
- Multiply each term in the series by the common ratio \( r \), giving: \( rS = ar + ar^2 + ar^3 + \cdots + ar^{n+1} \).
- Subtract this new equation from the original sum: \( S - rS = a - ar^{n+1} \).
Common Ratio in Series
The common ratio, denoted as \( r \), is a crucial element of geometric series. It is the constant factor between consecutive terms of the series. For the series \( a, ar, ar^2, \cdots \), the common ratio is \( r \).
- If \( |r| < 1 \), the terms get progressively smaller, and the series converges.
- If \( |r| > 1 \), the terms increase exponentially.
- The series is undefined for \( r = 1 \) under the geometric series formula because it simplifies instead to an arithmetic progression.
Finite Geometric Series
A finite geometric series is one that contains a limited number of terms, unlike an infinite geometric series which goes on indefinitely. In this context, the series is given as:\( S = a + ar + ar^2 + \cdots + ar^n \)In a finite geometric series, the number of terms is \( n+1 \). The simplicity of the geometric sum formula makes it easy to compute the sum of all these terms without having to add each individually.Some key points about a finite geometric series include:
- The formula for the sum can only be used when \( r eq 1 \).
- In practical applications, finite series are common in disciplines like economics and physics where exponential growth or decay sectors are analyzed.