Chapter 4: Problem 58
Let \(F_{0}(x)=x \sin x\) and \(F_{n+1}(x)=\int F_{n}(x) d x\). (a) Determine \(F_{1}(x), F_{2}(x), F_{3}(x)\), and \(F_{4}(x)\). (b) On the basis of part (a), conjecture the form of \(F_{16}(x)\).
Short Answer
Expert verified
F_1(x) = -x cos(x) + sin(x), F_2(x) = -x sin(x), F_3(x) = -x cos(x) + sin(x), F_4(x) = -x sin(x), F_16(x) = -x sin(x).
Step by step solution
01
Define F_0(x)
Given that \(F_{0}(x) = x \sin(x)\). This is the base function from which we will derive the succeeding functions by integration.
02
Find F_1(x)
We need to compute \(F_1(x)\), which is the integral of \(F_0(x)\):\[F_1(x) = \int x \sin(x) \, dx\]Using integration by parts, where \(u = x\) and \(dv = \sin(x)\,dx\):\- \(du = dx\) and \(v = -\cos(x)\).Apply the integration by parts formula \(\int u\,dv = uv - \int v\,du\):\[F_1(x) = -x\cos(x) + \int \cos(x) \, dx = -x\cos(x) + \sin(x) + C_1\]
03
Find F_2(x)
Compute \(F_2(x)\) by integrating \(F_1(x)\):\[F_2(x) = \int (-x\cos(x) + \sin(x)) \, dx\]Integrate term by term, using integration by parts for \(-x\cos(x)\):- Let \(u = x\) and \(dv = -\cos(x)\,dx\): \(du = dx\) and \(v = -\sin(x)\).Apply again:\[\int -x\cos(x) \, dx = -x\sin(x) + \int \sin(x) \, dx = -x\sin(x) + \cos(x) + C_2\]\[\int \sin(x) \, dx = -\cos(x)\]So, \(F_2(x) = -x\sin(x) + \cos(x) - \cos(x) + C_2 = -x\sin(x) + C_2\).
04
Find F_3(x)
Integrate \(F_2(x)\) to find \(F_3(x)\):\[F_3(x) = \int -x\sin(x) \, dx\]Using integration by parts, where \(u = x\) and \(dv = -\sin(x)\,dx\): \(du = dx\) and \(v = \cos(x)\).Apply:\[\int -x\sin(x) \, dx = -x\cos(x) + \int \cos(x) \, dx = -x\cos(x) + \sin(x) + C_3\]
05
Find F_4(x)
Compute \(F_4(x)\) by integrating \(F_3(x)\):\[F_4(x) = \int (-x\cos(x) + \sin(x)) \, dx\]Integrate term by term:From Step 2: \(-x\cos(x) + \sin(x)\) integrates to:\[-x\sin(x) + \cos(x) + C_4\]So, \(F_4(x) = -x\sin(x) + \cos(x) + C_4\).
06
Analyze the pattern
Observe the pattern:- \(F_0(x) = x\sin(x)\)- \(F_1(x) = -x\cos(x) + \sin(x)\)- \(F_2(x) = -x\sin(x)\)- \(F_3(x) = -x\cos(x) + \sin(x)\)- \(F_4(x) = -x\sin(x)\)The pattern alternates between forms similar to \(F_1(x)\) and \(F_2(x)\).
07
Conjecture F_16(x)
From the pattern observed:- (Odd n, like \(F_1\) and \(F_3\)) : \(-x\cos(x) + \sin(x)\)- (Even n, like \(F_2\) and \(F_4\)) : \(-x\sin(x)\)Since 16 is even, \(F_16(x)\) would follow the pattern for even indices:\[F_{16}(x) = -x\sin(x)\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals offer a way to calculate the accumulated area under a curve over a specific interval. Unlike indefinite integrals, which provide a general solution with a constant of integration, definite integrals deliver an exact numerical value. This numerical value represents the net area under the curve, taking into account areas above and below the x-axis by considering them with positive and negative signs, respectively.
Here's a quick look at how a definite integral is structured:
In exercises like the one given, definite integrals weren't directly calculated, but understanding them provides a deeper grasp of indefinite integrals since the processes are intertwined.
Here's a quick look at how a definite integral is structured:
- It involves an integral symbol, the function to be integrated, and the limits of integration, which denote the interval over which the area is calculated.
- The result is sensitive to the limits of integration: changing these limits changes the area computed.
In exercises like the one given, definite integrals weren't directly calculated, but understanding them provides a deeper grasp of indefinite integrals since the processes are intertwined.
Indefinite Integrals
Indefinite integrals are essentially the antiderivative of a function. When solving an indefinite integral, the result is a family of functions with an added constant of integration, denoted as \( C \). This constant arises because differentiating a constant yields zero, making it impossible to detect through differentiation alone which specific constant was in the original function set.
There are various techniques to solve indefinite integrals:
There are various techniques to solve indefinite integrals:
- Basic Antiderivatives: Recognize the antiderivatives of basic functions such as sin(x) and cos(x).
- Integration by Parts: A technique useful when handling products of functions, often using the formula \( \int u \, dv = uv - \int v \, du \).
- Substitution: Simplifies the integral by substituting part of the integral with a single variable, useful when dealing with composite functions.
Pattern Recognition in Calculus
Pattern recognition is a powerful tool in calculus, especially when dealing with sequences or series of functions. When evaluating problems like the exercise, recognizing patterns can simplify predicting the behavior of future functions in a sequence.
For example, in the given exercise, a pattern emerged in the functions \( F_n(x) \):
For example, in the given exercise, a pattern emerged in the functions \( F_n(x) \):
- The functions alternated between two main forms, \(-x\cos(x) + \sin(x)\) for odd indices and \(-x\sin(x)\) for even indices.
- Recognizing this pattern enabled the conjecture of \( F_{16}(x) \) without calculating every intermediary function.
- Alternating behaviors as seen in this exercise.
- Repeating cycles or motifs across intervals.
- Symmetries or other predictable behaviors.