/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Sketch the graph of a function w... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of a function with the given properties. \(f\) is continuous but not necessarily differentiable, has domain \([0,6]\), reaches a maximum of 6 (attained when \(x=0\) ) and a minimum of \(0(\) attained when \(x=6\) ). Additionally, \(f\) has two stationary points and two singular points in \((0,6)\).

Short Answer

Expert verified
Sketch a continuous graph from \((0,6)\) to \((6,0)\) with two flat regions and two sharp turns within \((0,6)\).

Step by step solution

01

Understand Stationary and Singular Points

A stationary point is where the derivative of the function is zero, implying that the graph flattens out. A singular point is where the function isn't differentiable, for example, a corner or a cusp. Identify where these may occur within the interval \((0,6)\).
02

Determine Maximum and Minimum Points

The function reaches a maximum value of 6 at \(x = 0\) and a minimum value of 0 at \(x = 6\). Hence, the function starts at a height of 6 when \(x = 0\) and ends at a height of 0 when \(x = 6\).
03

Sketch a Rough Outline

Between \((0,6)\), decide points where the stationary positions and singular points might occur. For instance, place stationary points around \(x = 2\) and \(x = 4\) for smooth flat regions. Choose singular points like \(x = 1.5\) and \(x = 4.5\) where there may be sharp turns.
04

Connect the Points with Continuity

Sketch a continuous graph starting at \((0,6)\), going through the determined stationary and singular points, while ensuring that at \(x = 6\) it reaches a value of 0. Maintain continuity by avoiding jumps or gaps in the function.
05

Review the Graph

Verify that the graph meets all conditions: maximum and minimum values at specified points, continuity across the range, and inclusion of stationary and singular points within \((0,6)\). Adjust the curve if necessary to fit all these requirements.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stationary Points
In graph sketching, understanding stationary points is crucial. A stationary point occurs where the derivative (slope) of a function equals zero. This means the graph has a flat section. Stationary points can represent local maxima, minima, or points of inflection where the graph changes concavity. For the given exercise, you need to identify two stationary points within the interval \(0,6\). These could be strategically placed around \(x = 2\) and \(x = 4\). At these points, ensure the graph smoothly flattens without showing any sudden changes or turns.

Remember that stationary points are critical for understanding how a function behaves. Since these are not the absolute maximum or minimum of the function, observing them helps paint a fuller picture of the graph's overall shape and behavior.
Singular Points
Singular points on a graph occur where the function is not differentiable. This means the slope doesn't exist or becomes infinite. Common examples of singular points include cusps and corners. In the problem, the function has two singular points within the interval \(0,6\). You could place these at \(x = 1.5\) and \(x = 4.5\). These points might be characterized by sharp turns, indicating a sudden change in direction or gradient.

When sketching, mark these singular points distinctly as they signal a dramatic feature on the graph. It's vital to be able to identify and differentiate between the smooth transition of a stationary point and the abrupt change at singular points. This understanding is key to creating accurate and visually representative graphs.
Continuity
Continuity in a function means there are no breaks, jumps, or holes in the graph. A continuous function flows seamlessly from one point to the next without interruption. In this exercise, the function is defined to be continuous over its domain of \[0,6\]. This means your plotted graph should be a smooth, unbroken curve that aligns with the given stationary and singular points.

To ensure continuity, closely observe transitions between regular points, stationary points, and singular points. The graph mustn't jump or have gaps between \(x = 0\) and \(x = 6\). Upholding continuity is essential as it guides how the function behaves across its entire domain, presenting a coherent picture of the function's characteristics.
Maximum and Minimum Points
The concepts of maximum and minimum points refer to the highest and lowest values a function can reach. In this exercise, the function reaches its maximum value of 6 at \(x = 0\), and its minimum value of 0 at \(x = 6\). These points are the endpoints of your graph, setting the range within which it varies.

When sketching, start your graph at the point \(0,6\) and ensure it ends at \(6,0\). These points are not just significant for defining the edges of the graph but also for understanding the overall plot. They illustrate the limits of the function's height and provide foundational reference points throughout your sketching process. So, any sketch must reflect these crucial values accurately, ensuring no confusion about the function's boundary points.

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Most popular questions from this chapter

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Suppose that every customer order taken by the XYZ Company requires exacty 5 hours of labor for handling the paperwork; this length of time is fixed and does not vary from lot to lot. The total number of hours \(y\) required to manufacture and sell a lot of size \(x\) would then be \(y=(\) number of hours to produce a lot of size \(x)+5\) Some data on XYZ's bookcases are given in the following table. $$ \begin{array}{ccc} \hline & & \text { Total Labor } \\ \text { Order } & \text { Lot Size } x & \text { Hours } y \\ \hline 1 & 11 & 38 \\ 2 & 16 & 52 \\ 3 & 8 & 29 \\ 4 & 7 & 25 \\ 5 & 10 & 38 \\ \hline \end{array} $$ (a) From the description of the problem, the least-squares line should have 5 as its \(y\) -intercept. Find a formula for the value of the slope \(b\) that minimizes the sum of squares $$ S=\sum_{i=1}^{n}\left[y_{i}-\left(5+b x_{i}\right)\right]^{2} $$ (b) Use this formula to estimate the slope \(b\). (c) Use your least-squares line to predict the total number of labor hours to produce a lot consisting of 15 bookcases.

The XYZ Company manufactures wicker chairs. With its present machines, it has a maximum yearly output of 500 units. If it makes \(x\) chairs, it can set a price of \(p(x)=200-0.15 x\) dollars each and will have a total yearly cost of \(C(x)=5000+6 x-0.002 x^{2}\) dollars. The company has the opportunity to buy a new machine for \(\$ 4000\) with which the company can make up to an additional 250 chairs per year. The cost function for values of \(x\) between 500 and 750 is thus \(C(x)=9000+6 x-0.002 x^{2} .\) Basing your analysis on the profit for the next year, answer the following questions. (a) Should the company purchase the additional machine? (b) What should be the level of production?

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