Chapter 4: Problem 24
In applying Newton's Method to solve \(f(x)=0\), one can usually tell by simply looking at the numbers \(x_{1}, x_{2}, x_{3}, \ldots\) whether the sequence is converging. But even if it converges, say to \(\bar{x}\), can we be sure that \(\bar{x}\) is a solution? Show that the answer is yes provided \(f\) and \(f^{\prime}\) are continuous at \(\bar{x}\) and \(f^{\prime}(\bar{x}) \neq 0\).
Short Answer
Step by step solution
Setup Newton's Method
Assume series convergence
Continuity of f and f'
Check derivative condition
Substitute limit into Newton's formula
Derivation of root condition
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence of Sequences
This convergence is important to determine if our sequence is approaching a solution to the equation \(f(x)=0\). Generally, a sequence \(x_1, x_2, x_3, \ldots\) is said to converge to \(\bar{x}\) if for every small tolerance, there is a point beyond which all terms are within that tolerance. Mathematically, \(\lim_{n \to \infty} x_n = \bar{x}\).
This concept is critical in Newton's Method, as it helps ensure that our calculated values are moving toward the solution we seek.
Continuity
For a function to be continuous at \(\bar{x}\), the limit of the function as the input approaches \(\bar{x}\) must equal the function's value at \(\bar{x}\). Mathematically, this means \(\lim_{x \to \bar{x}} f(x) = f(\bar{x})\). Continuity helps ensure that the behaviors and values of solutions we calculate are smooth and reliable.
In our context, if \(x_n\) converges to \(\bar{x}\) and \(f\) and \(f'\) are continuous, then it implies that \(\lim_{n \to \infty} f(x_n) = f(\bar{x})\) and similarly for the derivative: \(\lim_{n \to \infty} f'(x_n) = f'(\bar{x})\). This continuity is crucial because it confirms that the outputs of the function are smoothly approaching the values we expect as inputs approach \(\bar{x}\).
Derivative Conditions
When using the formula \(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\), if \(f'(\bar{x})\) were zero, the denominator would become zero, causing mathematical complications such as division by zero. This could mean the method fails to track correctly toward a root.
Thus, ensuring \(f'(\bar{x}) eq 0\) guarantees that our approach using Newton's Method remains valid and functional. It allows the technique to successfully reduce the difference \(\frac{f(x_n)}{f'(x_n)}\), optimizing our path toward identifying \(\bar{x}\) as a root. This derivative condition plays a pivotal role in the effectiveness of the method.
Roots of Equations
Given the convergence of \(x_n\) to \(\bar{x}\) and continuity of \(f\) and \(f'\), as well as the crucial condition \(f'(\bar{x}) eq 0\), we can safely incorporate \(\bar{x}\) into the formulation. What results is a simplification where the expressions derived confirm \(f(\bar{x}) = 0\).
This means after confirming all the conditions, we establish \(\bar{x}\) as a legitimate root, successfully applying Newton's Method. This outcome is insightful for students, demonstrating that a systematic, rule-abiding approach retrieves solutions efficiently.