Chapter 3: Problem 5
Find \(d^{3} y / d x^{3}\). $$ y=\sin (7 x) $$
Short Answer
Expert verified
The third derivative is \(-343 \cos(7x)\).
Step by step solution
01
Understand the problem
We need to find the third derivative of the function \(y = \sin(7x)\) with respect to \(x\). This means we'll differentiate the function three times sequentially.
02
First Derivative
Find the first derivative of \(y\) with respect to \(x\).Given \(y = \sin(7x)\), we apply the chain rule:\[ \frac{dy}{dx} = 7 \cos(7x) \].
03
Second Derivative
Find the second derivative by differentiating the first derivative.Starting from \(\frac{dy}{dx} = 7 \cos(7x)\), apply the chain rule again:\[ \frac{d^2y}{dx^2} = -49 \sin(7x) \].
04
Third Derivative
Find the third derivative by differentiating the second derivative.Starting from \(\frac{d^2y}{dx^2} = -49 \sin(7x)\), apply the chain rule:\[ \frac{d^3y}{dx^3} = -343 \cos(7x) \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental technique used in calculus for finding derivatives of composite functions. When you have a function within another function, like in our case where it's a trigonometric function composed with a linear function, the chain rule becomes essential.
To apply the chain rule, follow these steps:
In our example, the original function is given by \( y = \sin(7x) \).
When differentiating \( \sin(7x) \), treat \( \sin(u) \) as the outer function and \( u=7x \) as the inner function.
The derivative of \( \sin(u) \) is \( \cos(u) \), and the derivative of \( u \), which is \( 7x \), is 7.
Thus, the first derivative becomes \( \frac{dy}{dx} = 7 \cos(7x) \).
To apply the chain rule, follow these steps:
- Differentiate the outer function, keeping the inner function unchanged.
- Multiply this result by the derivative of the inner function.
In our example, the original function is given by \( y = \sin(7x) \).
When differentiating \( \sin(7x) \), treat \( \sin(u) \) as the outer function and \( u=7x \) as the inner function.
The derivative of \( \sin(u) \) is \( \cos(u) \), and the derivative of \( u \), which is \( 7x \), is 7.
Thus, the first derivative becomes \( \frac{dy}{dx} = 7 \cos(7x) \).
Trigonometric Differentiation
Trigonometric differentiation involves finding derivatives of trigonometric functions. It's an essential part of calculus, especially when combined with the chain rule.
Some basic derivatives of trigonometric functions include:
In the exercise, we differentiate the trigonometric function multiple times. Starting with \( \sin(7x) \), the chain rule was applied to find its derivative, giving us \( 7 \cos(7x) \).
For the second derivative, we differentiate \( \cos(7x) \), which becomes \( -\sin(7x) \), and the outer derivative multiplies again by 7, resulting in \( -49 \sin(7x) \).
Some basic derivatives of trigonometric functions include:
- The derivative of \( \sin(x) \) is \( \cos(x) \)
- The derivative of \( \cos(x) \) is \( -\sin(x) \)
In the exercise, we differentiate the trigonometric function multiple times. Starting with \( \sin(7x) \), the chain rule was applied to find its derivative, giving us \( 7 \cos(7x) \).
For the second derivative, we differentiate \( \cos(7x) \), which becomes \( -\sin(7x) \), and the outer derivative multiplies again by 7, resulting in \( -49 \sin(7x) \).
Higher-Order Derivatives
Higher-order derivatives refer to the process of differentiating a function multiple times. This concept is crucial for tasks involving rates of change and concavity of functions.
The third derivative is a higher-order derivative found by differentiating a function three times sequentially.
Starting with \( y = \sin(7x) \), the third derivative involves differentiating the first and second derivatives.
The third derivative, \( \frac{d^3y}{dx^3} = -343 \cos(7x) \), is particularly useful for understanding the behavior of functions, like checking for points of inflection or analyzing motion.
The third derivative is a higher-order derivative found by differentiating a function three times sequentially.
Starting with \( y = \sin(7x) \), the third derivative involves differentiating the first and second derivatives.
- First derivative: \( \frac{dy}{dx} = 7 \cos(7x) \)
- Second derivative: \( \frac{d^2y}{dx^2} = -49 \sin(7x) \)
- Third derivative: \( \frac{d^3y}{dx^3} = -343 \cos(7x) \)
The third derivative, \( \frac{d^3y}{dx^3} = -343 \cos(7x) \), is particularly useful for understanding the behavior of functions, like checking for points of inflection or analyzing motion.