Chapter 3: Problem 10
Use \(f^{\prime}(x)=\lim _{h \rightarrow 0}[f(x+h)-f(x)] / h\) to find the derivative at \(x\). $$ f(x)=x^{4} $$
Short Answer
Expert verified
The derivative of \( f(x) = x^4 \) is \( 4x^3 \).
Step by step solution
01
Identify the Function and Variable
The given function is \( f(x) = x^4 \). We need to find the derivative of this function with respect to \( x \) at any point \( x \).
02
Set Up the Difference Quotient
The difference quotient for the derivative of \( f(x) \) is given by \( \frac{f(x+h) - f(x)}{h} \). First, calculate \( f(x+h) \), which is \((x+h)^4\).
03
Expand \((x+h)^4\) Using the Binomial Theorem
Expand \((x+h)^4\) using the binomial theorem: \[(x+h)^4 = x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4.\]
04
Substitute and Simplify the Difference Quotient
Substitute \( f(x+h) \) and \( f(x) \) into the difference quotient:\[\frac{(x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4) - x^4}{h} = \frac{4x^3h + 6x^2h^2 + 4xh^3 + h^4}{h}.\]Cancel \( x^4 \) and then simplify by dividing each term by \( h \):\[4x^3 + 6x^2h + 4xh^2 + h^3.\]
05
Calculate the Limit as \( h \to 0 \)
Calculate the limit of the simplified expression as \( h \to 0 \):\[\lim_{h \to 0} (4x^3 + 6x^2h + 4xh^2 + h^3) = 4x^3.\]Since the terms containing \( h \) vanish as \( h \to 0 \), we are left with \( 4x^3 \).
06
Conclude the Derivative
We have found the derivative of the function \( f(x)=x^4 \) to be \( f'(x) = 4x^3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference Quotient
A fundamental concept in calculus is the difference quotient, which is crucial for finding derivatives. It essentially measures how a function changes as its input changes by a tiny amount. This concept forms the backbone of derivative calculation. For any given function \( f(x) \), the difference quotient is given by:
- \( \frac{f(x+h) - f(x)}{h} \)
Binomial Theorem
The binomial theorem is a powerful tool that helps expand expressions raised to a power. In our exercise, we had \( (x+h)^4 \), which requires expansion to simplify the difference quotient.
The binomial theorem states that for any non-negative integer \( n \):
In our function, expanding \( (x+h)^4 \) gives us a polynomial:
The binomial theorem states that for any non-negative integer \( n \):
- \((x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k\)
In our function, expanding \( (x+h)^4 \) gives us a polynomial:
- \( x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 \)
Limit Process
The limit process is the final and critical step in finding the derivative using the difference quotient. When we calculate \(\lim_{h \to 0} \left(\frac{f(x+h) - f(x)}{h}\right),\)we evaluate how the expression behaves as \( h \) gets closer and closer to zero. This procedure is what we call finding the limit.
For our function \( f(x) = x^4 \), after expanding and simplifying the difference quotient, we had:
For our function \( f(x) = x^4 \), after expanding and simplifying the difference quotient, we had:
- \( 4x^3 + 6x^2h + 4xh^2 + h^3 \)
- \( \lim_{h \to 0} (6x^2h + 4xh^2 + h^3) = 0 \)