/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Find the image of the rectangle ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the image of the rectangle with the given corners and find the Jacobian of the transformation. $$ x=u, y=u^{2}-v^{2} ;(0,0),(3,0),(3,1),(0,1) $$

Short Answer

Expert verified
The image is a quadrilateral with vertices at (0,0), (3,9), (3,8), (0,-1) and the Jacobian determinant is \(-2v\).

Step by step solution

01

Understand the Transformation

We begin with the given transformation equations: \( x = u \) and \( y = u^2 - v^2 \). Our goal is to apply these equations to transform the corners of the rectangle from the \((u, v)\) coordinates to the \((x, y)\) coordinates.
02

Transform the Corner (0,0)

For the corner \((0,0)\), substitute \( u = 0 \) and \( v = 0 \) into the transformation equations. We get \( x = 0 \) and \( y = 0^2 - 0^2 = 0 \). Thus, \((x, y) = (0, 0)\).
03

Transform the Corner (3,0)

For the corner \((3,0)\), substitute \( u = 3 \) and \( v = 0 \) into the transformation equations. We get \( x = 3 \) and \( y = 3^2 - 0^2 = 9 \). So, \((x, y) = (3, 9)\).
04

Transform the Corner (3,1)

For the corner \((3,1)\), substitute \( u = 3 \) and \( v = 1 \) into the transformation equations. This gives us \( x = 3 \) and \( y = 3^2 - 1^2 = 8 \). Thus, \((x, y) = (3, 8)\).
05

Transform the Corner (0,1)

For the corner \((0,1)\), substitute \( u = 0 \) and \( v = 1 \) into the transformation equations. We get \( x = 0 \) and \( y = 0^2 - 1^2 = -1 \). So, \((x, y) = (0, -1)\).
06

Identify the Image of the Rectangle

The image of the rectangle in the \((u,v)\) space through the transformation is a quadrilateral with transformed vertices \((0,0), (3,9), (3,8), (0,-1)\).
07

Calculate the Jacobian of the Transformation

The Jacobian matrix \( J \) of the transformation is given by the partial derivatives:\[J = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix}\]Where:- \( \frac{\partial x}{\partial u} = 1 \), \( \frac{\partial x}{\partial v} = 0 \)- \( \frac{\partial y}{\partial u} = 2u \), \( \frac{\partial y}{\partial v} = -2v \)Thus:\[J = \begin{bmatrix} 1 & 0 \ 2u & -2v \end{bmatrix}\]
08

Determine the Determinant of the Jacobian

The determinant of the Jacobian matrix is:\[\text{det}(J) = (1)(-2v) - (0)(2u) = -2v\]Thus, the determinant of the Jacobian matrix is \(-2v\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Jacobian
In mathematics, the Jacobian is a central concept used to understand transformations of coordinates. It is essentially a matrix of all first-order partial derivatives of a vector function. When trying to understand how a transformation affects area, volume, or shape in multidimensional space, the Jacobian provides the scale of this transformation.

### How to Find the JacobianTo calculate the Jacobian for a transformation, organize variables in a function and calculate the partial derivatives:
  • Given a function: \( x = u \) and \( y = u^2 - v^2 \),
  • The Jacobian matrix, \( J \), is:
    \[ J = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} \]
### Interpreting the DeterminantOnce the Jacobian matrix is constructed, its determinant helps to determine how much a small area around a point is scaled when transforming from one system of coordinates to another. A positive determinant indicates a scale up, while a negative suggests an inversion.

In our case, the determinant is \(-2v\), indicating that the transformation on the \((u, v)\) plane experiences compression/expansion dependent on \(v\) and an inversion depending on the sign of \(-2v\).
Coordinate Transformation
Coordinate transformation is a fundamental concept to help change perspective, location, or focus in mathematical problems. It involves altering the coordinate system to express a function or a problem differently.

### Example of Coordinate TransformationIn our original problem, the transformation from \( (u,v) \) coordinates to \( (x,y) \) coordinates via the functions
  • \( x = u \)
  • \( y = u^2 - v^2 \)
helps reshape a rectangle into a new geometric figure.

### Practical ImportanceSuch transformations are more than just academic exercises:
  • They can simplify complex geometric problems.
  • Coordinate transformations are pivotal in fields like computer graphics, physics, and engineering.
Through these transformations, calculations become more manageable, making abstract concepts more accessible.
Rectangular to Quadrilateral transformation
Understanding the transformation from a rectangle to a quadrilateral provides deep insights into geometric manipulations using math. Initially, we have a rectangular shape defined in \( (u,v) \) space by corners \( (0,0), (3,0), (3,1), (0,1) \). Using the transformation equations, each corner is mapped to a new point in \( (x,y) \) coordinates.

### The Transformation ProcessThrough the exercises, the rectangle gets its vertices remapped, creating a distorted yet fascinating quadrilateral:
  • From \( (0,0) \) to \( (0,0) \)
  • From \( (3,0) \) to \( (3,9) \)
  • From \( (3,1) \) to \( (3,8) \)
  • From \( (0,1) \) to \( (0,-1) \)
### Visualization in MathematicsThis transformation illustrates how algebraic manipulations map geometric figures into different shapes, crucial in visualization, simulations, and various analyses. By changing only our view or expression of coordinates, what was once a simple rectangle translates into a more complex geometric form.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use triple iterated integrals to find the indicated quantities. Moment of inertia \(I_{x}\) about the \(x\) -axis of the solid bounded by the cylinder \(y^{2}+z^{2}=4\) and the planes \(x-y=0, x=0\), and \(z=0\) if the density \(\delta(x, y, z)=z .\) Hint: You will need to develop your own formula; slice, approximate, integrate.

Let \(S\) be a lamina in the \(x y\) -plane with center of mass at the origin, and let \(L\) be the line \(a x+b y=0\), which goes through the origin. Show that the (signed) distance \(d\) of a point \((x, y)\) from \(L\) is \(d=(a x+b y) / \sqrt{a^{2}+b^{2}}\), and use this to conclude that the moment of \(S\) with respect to \(L\) is \(0 .\) Note: This shows that a lamina will balance on any line through its center of mass.

Suppose that the random variables \(X\) and \(Y\) have joint PDF $$ f(x, y)=\left\\{\begin{array}{ll} \frac{1}{4}, & \text { if } 0 \leq x \leq 2,0 \leq y \leq 2 \\ 0, & \text { otherwise } \end{array}\right. $$ that is, \(X\) and \(Y\) are uniformly distributed over the square \(0 \leq x \leq 2,0 \leq y \leq 2\). Find (a) the joint PDF of \(U=X+Y\) and \(V=X-Y\), and (b) the marginal PDF of \(U\). 25\. Suppose \(X\) and \(Y\) have joint \(\mathrm{PDF}\) $$ f(x, y)=\left\\{\begin{array}{ll} e^{-x-y}, & \text { if } x \geq 0, y \geq 0 \\ 0, & \text { otherwise } \end{array}\right. $$ Find (a) the joint PDF of \(U=X+Y\) and \(V=X\) (b) the marginal PDF of \(U\).

Find the mass \(m\) and center of mass \((\bar{x}, \bar{y})\) of the lamina bounded by the given curves and with the indicated density. \(r=1+\cos \theta ; \delta(r, \theta)=r\)

Use spherical coordinates to find the indicated quantity. For any homogeneous solid \(S\), show that the average value of the linear function \(f(x, y, z)=a x+b y+c z+d\) on \(S\) is \(f(\bar{x}, \bar{y}, \bar{z})\), where \((\bar{x}, \bar{y}, \bar{z})\) is the center of mass.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.