Chapter 12: Problem 24
The period \(T\) of a pendulum of length \(L\) is given by \(T=2 \pi \sqrt{L / g}\), where \(g\) is the acceleration of gravity. Show that \(d T / T=\frac{1}{2}[d L / L-d g / g]\), and use this result to estimate the maximum percentage error in \(T\) due to an error of \(0.5 \%\) in measuring \(L\) and \(0.3 \%\) in measuring \(g\).
Short Answer
Step by step solution
Understand the Formula
Calculate Error in T
Derive Relative Change
Calculate Maximum Percentage Error
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pendulum Period Calculation
- \(L\) is the length of the pendulum,
- \(g\) is the acceleration due to gravity (approximately 9.8 m/s² near the surface of the Earth), and
- \(T\) is the pendulum period.