Chapter 12: Problem 15
Find the equation \(w=T(x, y, z)\) of the tangent "hyperplane" at \(\mathbf{p}\). $$ f(x, y, z)=3 x^{2}-2 y^{2}+x z^{2}, \mathbf{p}=(1,2,-1) $$
Short Answer
Expert verified
The tangent hyperplane is \( w = 7x - 8y - 2z + 3 \).
Step by step solution
01
Understand the Hyperplane
The problem requires finding the equation of the tangent hyperplane to the surface defined by the function \( f(x, y, z) = 3x^2 - 2y^2 + xz^2 \) at the point \( \mathbf{p} = (1, 2, -1) \). The equation of a tangent hyperplane at a point \( (a, b, c) \) is given by: \[ w = f(a, b, c) + f_x(a, b, c)(x-a) + f_y(a, b, c)(y-b) + f_z(a, b, c)(z-c), \] where \(f_x\), \(f_y\), and \(f_z\) are the partial derivatives of \( f \).
02
Calculate Partial Derivatives
Calculate the partial derivatives of the function \( f(x, y, z) \):1. \( f_x(x, y, z) = \frac{\partial f}{\partial x} = 6x + z^2 \).2. \( f_y(x, y, z) = \frac{\partial f}{\partial y} = -4y \).3. \( f_z(x, y, z) = \frac{\partial f}{\partial z} = 2xz \).
03
Evaluate Partial Derivatives at the Point
Evaluate the partial derivatives at the point \( \mathbf{p} = (1, 2, -1) \):1. \( f_x(1, 2, -1) = 6 \cdot 1 + (-1)^2 = 7 \).2. \( f_y(1, 2, -1) = -4 \cdot 2 = -8 \).3. \( f_z(1, 2, -1) = 2 \cdot 1 \cdot (-1) = -2 \).
04
Evaluate the Function at the Point
Evaluate the function at the point \( \mathbf{p} \):\[ f(1, 2, -1) = 3(1)^2 - 2(2)^2 + 1(-1)^2 = 3 - 8 + 1 = -4. \]
05
Form the Equation of the Tangent Hyperplane
Using the formula for the tangent hyperplane, substitute the values:\[ w = -4 + 7(x - 1) - 8(y - 2) - 2(z + 1). \]Simplify the equation:\[ w = -4 + 7x - 7 - 8y + 16 - 2z - 2. \]Thus, the equation becomes:\[ w = 7x - 8y - 2z + 3. \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Hyperplane
In multivariable calculus, a **tangent hyperplane** is akin to the tangent line we are familiar with from single-variable calculus. However, as we move to multiple dimensions, the concept extends into higher dimensions too.
A tangent hyperplane is simply a flat surface that just "touches" a given surface without intersecting it, at least on an infinitesimally small scale. It provides the best linear approximation of the surface at a specific point.
The tangent hyperplane at a point \(\mathbf{p} = (a, b, c)\) on a surface defined by a function \(f(x, y, z)\) can be expressed as:
A tangent hyperplane is simply a flat surface that just "touches" a given surface without intersecting it, at least on an infinitesimally small scale. It provides the best linear approximation of the surface at a specific point.
The tangent hyperplane at a point \(\mathbf{p} = (a, b, c)\) on a surface defined by a function \(f(x, y, z)\) can be expressed as:
- \(w = f(a, b, c) + f_x(a, b, c)(x-a) + f_y(a, b, c)(y-b) + f_z(a, b, c)(z-c)\)
Partial Derivatives
**Partial derivatives** are the building blocks for understanding how multivariable functions change. When we compute a partial derivative of a function like \(f(x, y, z)\), we find how the function changes concerning one variable while keeping the other variables constant.
In our example:
In our example:
- \(f_x(x, y, z) = 6x + z^2\) assesses changes along the \(x\)-axis.
- \(f_y(x, y, z) = -4y\) focuses on changes along the \(y\)-axis.
- \(f_z(x, y, z) = 2xz\) relates to changes along the \(z\)-axis.
Surface Equation
The **surface equation** in multivariable calculus describes a 3D object using a function of several variables. In this case, \(f(x, y, z) = 3x^2 - 2y^2 + xz^2\) represents a surface in a 3D space.
Understanding how this surface looks at various points requires using principles like partial derivatives. At the point \(\mathbf{p} = (1, 2, -1)\), we evaluate not only its function value but also its first-order partial derivatives.
The calculation of these values provides information essential for higher concept evaluations, such as forming a tangent hyperplane that approximates our surface locally at point \(\mathbf{p}\). This gives insight into the behavior and shape of the surface.
Understanding how this surface looks at various points requires using principles like partial derivatives. At the point \(\mathbf{p} = (1, 2, -1)\), we evaluate not only its function value but also its first-order partial derivatives.
The calculation of these values provides information essential for higher concept evaluations, such as forming a tangent hyperplane that approximates our surface locally at point \(\mathbf{p}\). This gives insight into the behavior and shape of the surface.
Function Evaluation
**Function evaluation** involves computing the value of a function at a specific point to understand the characteristics of a surface at that location. For the function \((f(x, y, z) = 3x^2 - 2y^2 + xz^2)\), computing it at \(\mathbf{p} = (1, 2, -1)\) tells us the height or depth of the surface at that exact point.
From our calculations, \(f(1, 2, -1) = 3 - 8 + 1 = -4\). This result is critical because it determines where the tangent hyperplane will be anchored in a vertical sense.
By combining this height with slopes determined by the partial derivatives, we form a tangent hyperplane equation to closely approximate the behavior of the surface around that point.
From our calculations, \(f(1, 2, -1) = 3 - 8 + 1 = -4\). This result is critical because it determines where the tangent hyperplane will be anchored in a vertical sense.
By combining this height with slopes determined by the partial derivatives, we form a tangent hyperplane equation to closely approximate the behavior of the surface around that point.