Chapter 11: Problem 23
Find the volume of the parallelepiped with edges \(\langle 2,3,4\rangle,\langle 0,4,-1\rangle\), and \(\langle 5,1,3\rangle\) (see Example 4).
Short Answer
Expert verified
The volume of the parallelepiped is 69 cubic units.
Step by step solution
01
Understanding the formula for volume of a parallelepiped
The volume of a parallelepiped can be calculated using the scalar triple product of its three vectors. The formula is given by: \( V = |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| \), where \( \mathbf{a}, \mathbf{b}, \mathbf{c} \) are the vectors of the parallelepiped.
02
Write down the vectors
We are given three vectors as the edges of the parallelepiped: \( \mathbf{a} = \langle 2, 3, 4 \rangle \), \( \mathbf{b} = \langle 0, 4, -1 \rangle \), and \( \mathbf{c} = \langle 5, 1, 3 \rangle \).
03
Calculate the cross product \( \mathbf{b} \times \mathbf{c} \)
The cross product \( \mathbf{b} \times \mathbf{c} \) is calculated as follows:\[ \mathbf{b} \times \mathbf{c} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 0 & 4 & -1 \ 5 & 1 & 3 \end{vmatrix} \]This can be expanded as:\[ \mathbf{b} \times \mathbf{c} = \mathbf{i}(4 \times 3 - (-1) \times 1) - \mathbf{j}(0 \times 3 - (-1) \times 5) + \mathbf{k}(0 \times 1 - 4 \times 5) \]\[ = 13\mathbf{i} - 5\mathbf{j} - 20\mathbf{k} \]So, \( \mathbf{b} \times \mathbf{c} = \langle 13, -5, -20 \rangle \).
04
Calculate the dot product \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) \)
Now, calculate the dot product of \( \mathbf{a} \) with the cross product \( \mathbf{b} \times \mathbf{c} \): \[ \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = \langle 2, 3, 4 \rangle \cdot \langle 13, -5, -20 \rangle \]\[ = 2 \times 13 + 3 \times (-5) + 4 \times (-20) \]\[ = 26 - 15 - 80 \]\[ = -69 \]
05
Find the absolute value
The volume is the absolute value of the dot product calculated. Thus, the volume of the parallelepiped is:\[ V = |-69| = 69 \] cubic units.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Scalar Triple Product
The scalar triple product is a powerful concept in vector mathematics used to calculate the volume of a parallelepiped. In simpler terms, a parallelepiped is like a 3D box whose edges are defined by three vectors. To calculate the volume of this box, the scalar triple product formula can be used:
- Formula: \( V = |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| \)
- Components: In the formula, \( \mathbf{a}, \mathbf{b}, \mathbf{c} \) represent the vectors corresponding to the edges of the parallelepiped.
Cross Product Calculation
The cross product is a central operation in vector calculus, helping us find a vector that is orthogonal to two given vectors. For vectors \( \mathbf{b} = \langle 0, 4, -1 \rangle \) and \( \mathbf{c} = \langle 5, 1, 3 \rangle \), the cross product \( \mathbf{b} \times \mathbf{c} \) can be calculated as follows:
- Setup the determinant: Write a determinant with unit vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) on the first row, with the components of \( \mathbf{b} \) and \( \mathbf{c} \) on the remaining rows.
- Calculate: The computed cross product is \[ \mathbf{b} \times \mathbf{c} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 0 & 4 & -1 \ 5 & 1 & 3 \end{vmatrix} \]
- Expand: By solving the determinant, we get \( \langle 13, -5, -20 \rangle \), which is orthogonal to both \( \mathbf{b} \) and \( \mathbf{c} \).
Vector Dot Product
The dot product of two vectors is a mathematical operation where we multiply corresponding components of the vectors and sum them to get a scalar value. This operation plays an integral role in the volume calculation of a parallelepiped.For vectors \( \mathbf{a} = \langle 2, 3, 4 \rangle \) and the cross product \( \mathbf{b} \times \mathbf{c} = \langle 13, -5, -20 \rangle \), the calculation is:
- Compute: \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = 2 \times 13 + 3 \times (-5) + 4 \times (-20) \)
- Result: The dot product equals \(-69\).