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a parametric representation of a curve is given. $$ x=2 t, y=3 t ;-\infty

Short Answer

Expert verified
The curve is a straight line given by \( y = \frac{3}{2}x \).

Step by step solution

01

Identify the Parametric Equations

The parametric equations are given as: \( x = 2t \) and \( y = 3t \). These equations express \( x \) and \( y \) as functions of the parameter \( t \).
02

Eliminate the Parameter

To find the relation between \( x \) and \( y \), solve one of the parametric equations for \( t \). Let's solve \( x = 2t \): \( t = \frac{x}{2} \). Substitute this into \( y = 3t \): \( y = 3\left(\frac{x}{2}\right) = \frac{3}{2}x \).
03

Write the Resulting Equation

The equation relating \( x \) and \( y \) is \( y = \frac{3}{2}x \). This is the equation of a straight line in Cartesian coordinates without any parameter.
04

Verify the Domain Restrictions

The parameter \( t \) can range from \(-\infty\) to \(+\infty\). This means there are no restrictions to the values of \( x \) and \( y \) as \( t \) takes all real values. Hence, the line is defined for all real \( x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Curve Sketching
Curve sketching is a useful technique in mathematics that helps visualize the path a set of equations creates. When dealing with parametric equations like the ones given, our goal is to understand what shape or curve is described in space. The parametric equations express both the horizontal (x-axis) and vertical (y-axis) coordinates as functions of a parameter, which commonly is "t". By altering the value of "t", the curve is traced out point by point in the graphical plane.

To sketch the curve, you evaluate the equations at several values of "t" and plot these points on the graph. For example, with the equations \( x = 2t \) and \( y = 3t \), you'll find points like (0,0) when \( t = 0 \), (2,3) when \( t = 1 \), and (-2,-3) when \( t = -1 \). These points should be drawn and connected in order as "t" increases, giving us a clearer picture of the curve. In this case, the curve is a straight line through these points.

Understanding the path of a curve through parametric equations is important, especially in physics and engineering, where objects follow precise trajectories.
Eliminating the Parameter
Eliminating the parameter in parametric equations is a process used to find a relationship between the dependent variables, usually x and y, without any parameter involved. This step is crucial because it converts the parametric form into a more familiar Cartesian equation.

The initial step involves solving one of the equations for the parameter ("t", in most cases). For instance, given \( x = 2t \), we rearrange it as \( t = \frac{x}{2} \). Next, substitute this expression for "t" in the other parametric equation \( y = 3t \). Doing this yields \( y = 3\left(\frac{x}{2}\right) = \frac{3}{2}x \).

After the parameter is eliminated, we arrive at the Cartesian equation \( y = \frac{3}{2}x \), a linear equation describing a straight line. This process simplifies complex curves into simpler expressions, making them easier to analyze.
Cartesian Coordinates
Cartesian coordinates provide a systematic way of describing the position of points on a plane. When we use a parameter to describe a curve, converting it to Cartesian coordinates gives a more straightforward representation.

In the example of \( x = 2t \) and \( y = 3t \), the task was to transition from parametric forms to \( y = \frac{3}{2}x \), which is its Cartesian form. This line equation is easily recognizable and tells us that the line has a slope of \( \frac{3}{2} \) and passes through the origin (0,0).

The Cartesian coordinate system uses an x-axis and a y-axis, both of which are perpendicular, to define the position of points in a two-dimensional space. Each point can be described simply by a pair of values (x, y), making this system highly intuitive and favored for graphing linear relationships. Through Cartesian coordinates, we can interpret and analyze the geometric nature of equations effectively.

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Most popular questions from this chapter

Graph the curve \(r=\cos (8 \theta / 5)\) using the parametric graphing facility of a graphing calculator or computer. Notice that it is necessary to determine the proper domain for \(\theta\). Assuming that you start at \(\theta=0\), you have to determine the value of \(\theta\) that makes the curve start to repeat itself. Explain why the correct domain is \(0 \leq \theta \leq 10 \pi\)

Sketch the graph of the given equation. \(4 x^{2}+16 x-16 y+32=0\)

Let \(C\) be the curve of intersection of a right circular cylinder and a plane making an angle \(\phi(0<\phi<\pi / 2)\) with the axis of the cylinder. Show that \(C\) is an ellipse.

Show that, if \(A+C\) and \(\Delta=4 A C-B^{2}\) are both positive, then the graph of \(A x^{2}+B x y+C y^{2}=1\) is an ellipse (or circle) with area \(2 \pi / \sqrt{\Delta}\). (Recall from Problem 55 of Section \(10.2\) that the area of the ellipse \(x^{2} / p^{2}+y^{2} / q^{2}=1\) is \(\left.\pi p q .\right)\)

The position of a comet with a highly eccentric elliptical orbit \((e\) very near 1\()\) is measured with respect to a fixed polar axis (sun is at a focus but the polar axis is not an axis of the ellipse) at two times, giving the two points \((4, \pi / 2)\) and \((3, \pi / 4)\) of the orbit. Here distances are measured in astronomical units \((1 \mathrm{AU} \approx 93\) million miles). For the part of the orbit near the sun, assume that \(e=1\), so the orbit is given by $$r=\frac{d}{1+\cos \left(\theta-\theta_{0}\right)}$$ (a) The two points give two conditions for \(d\) and \(\theta_{0}\). Use them to show that \(4.24 \cos \theta_{0}-3.76 \sin \theta_{0}-2=0\) (b) Solve for \(\theta_{0}\) using Newton's Method. (c) How close does the comet get to the sun?

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