Chapter 1: Problem 62
Use a computer or a graphing calculator in Problems \(62-65 .\) Let \(f(x)=x^{2}-3 x\). Using the same axes, draw the graphs of \(y=f(x), y=f(x-0.5)-0.6\), and \(y=f(1.5 x)\), all on the domain \([-2,5]\).
Short Answer
Expert verified
Plot three transformed parabolas on the same graph over the domain \([-2, 5]\).
Step by step solution
01
Understanding the Functions
We begin by identifying the transformations applied to the original function \( f(x) = x^2 - 3x \). For \( y = f(x-0.5)-0.6 \), the function is shifted right by 0.5 units and down by 0.6 units. For \( y = f(1.5x) \), the function is horizontally compressed by a factor of 1/1.5.
02
Graphing the Original Function
The function \( f(x) = x^2 - 3x \) is a quadratic function, which takes the shape of a parabola. Plot this function on the graph over the domain \([-2, 5]\). The vertex of this parabola is at \( x = \frac{3}{2} \), and it opens upwards.
03
Graphing the Transformed Function y=f(x-0.5)-0.6
For \( y = f(x-0.5) - 0.6 \), first apply the rightward shift by plotting the parabola using \( (x-0.5)^2 - 3(x-0.5) \). Then shift the entire graph downward by 0.6 units. Plot this new graph within the domain \([-2, 5]\).
04
Graphing the Transformed Function y=f(1.5x)
For \( y = f(1.5x) \), replace \( x \) in the function with \( 1.5x \), resulting in \( (1.5x)^2 - 3(1.5x) \). This compresses the parabola horizontally, effectively changing its width. Plot this function over the domain \([-2, 5]\).
05
Compile the Graphs
On the same set of axes, plot all three functions: the original \( y = f(x) \), the transformed \( y = f(x-0.5) - 0.6 \), and the horizontally compressed \( y = f(1.5x) \). Make sure each function is clearly labeled and covers the domain \([-2, 5]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Transformations
When you transform a function, you essentially change its shape or position on a graph. For quadratic functions like our example, these transformations can involve sliding the graph up, down, left, or right, and even reshaping it. Let's consider the specific transformations in our exercise.
- Shift Right and Down: In the function \( y = f(x-0.5)-0.6 \), the term \( x-0.5 \) indicates a shift to the right by 0.5 units. This is because subtracting from \( x \) moves the graph to the right. Then, \(-0.6\) means moving the graph downwards by 0.6 units.
- Horizontal Compression: For \( y = f(1.5x) \), the replacement of \( x \) with \( 1.5x \) compresses the graph horizontally. Think of it as squeezing the graph towards the \( y \)-axis, making it narrower. This happens because you're multiplying \( x \) by a number greater than 1.
Parabola Graphing
Graphing a parabola can be straightforward once you grasp the basic shape of quadratic functions. The simplest parabolic function is \( y = x^2 \), which has a distinct U-shape opening upwards. In our scenario, the function \( f(x) = x^2 - 3x \) possesses a similar shape but is adjusted slightly based on its equation.
- Vertex Calculation: The vertex of a parabola \( ax^2 + bx + c \) occurs at the point \( x = -\frac{b}{2a} \). For \( f(x) = x^2 - 3x \), which equates to \( a = 1 \) and \( b = -3 \), the vertex is found at \( x = \frac{3}{2} \).
- Opening Direction: Since \( a = 1 \) (positive), our parabola opens upwards. If \( a \) were negative, the parabola would open downwards.
Domain and Range in Graphs
Understanding the domain and range is essential for graphing functions. The domain of a function is the set of all possible input values (\( x \)-values). In our exercise, the domain is specified as \([-2, 5]\). This means we only consider \( x \)-values within this interval for our graphs.
The range, on the other hand, is the set of all possible output values (\( y \)-values) that the function can produce. For a quadratic function like \( f(x) = x^2 - 3x \), the range depends on its vertex and the direction it opens. Since our parabola opens upwards, the lowest point, or minimum \( y \)-value, will be at its vertex.
The range, on the other hand, is the set of all possible output values (\( y \)-values) that the function can produce. For a quadratic function like \( f(x) = x^2 - 3x \), the range depends on its vertex and the direction it opens. Since our parabola opens upwards, the lowest point, or minimum \( y \)-value, will be at its vertex.
- Finding the Range: Calculate \( y \) at the vertex and that's the minimum value. Given our vertex at \( x = \frac{3}{2} \), compute \( f\left(\frac{3}{2}\right) \) to find this minimum \( y \)-value.
- Determining Full Range: As \( x \) moves within \([-2, 5]\), \( y \) will increase from this minimum point upward.