Chapter 1: Problem 38
Find a formula for \(f^{-1}(x)\) and then verify that \(f^{-1}(f(x))=x\) and \(f\left(f^{-1}(x)\right)=x\) $$ f(x)=(x-3)^{2}, x \geq 3 $$
Short Answer
Expert verified
The inverse function is \( f^{-1}(x) = \sqrt{x} + 3 \). Verification shows \( f^{-1}(f(x))=x \) and \( f(f^{-1}(x))=x \).
Step by step solution
01
Understand the Function
The given function is \( f(x) = (x-3)^2 \) with the condition that \( x \geq 3 \). This restriction ensures that the function is one-to-one and thus invertible on this domain.
02
Solve for the Inverse Function
To find the inverse function \( f^{-1}(x) \), start by setting \( y = (x-3)^2 \). Solve for \( x \) in terms of \( y \):\[(x-3)^2 = y\]Take the square root of both sides: \( x - 3 = \sqrt{y} \). Since \( x \geq 3 \), we only consider the non-negative square root, yielding \( x = \sqrt{y} + 3 \). Thus, the inverse function is \( f^{-1}(x) = \sqrt{x} + 3 \).
03
Verify \(f^{-1}(f(x))=x\)
Let \( f^{-1}(x) = \sqrt{x} + 3 \) and substitute \( f(x) \) into it: \[f^{-1}(f(x)) = f^{-1}((x-3)^2) = \sqrt{(x-3)^2} + 3\]. Since \( x \geq 3 \) and square root and square are inverse operations, \( \sqrt{(x-3)^2} = x-3 \). Adding 3 back gives \( f^{-1}(f(x)) = x \).
04
Verify \(f(f^{-1}(x))=x\)
Substitute \( f^{-1}(x) = \sqrt{x} + 3 \) into \( f(x) \): \[f(f^{-1}(x)) = f(\sqrt{x} + 3) = ((\sqrt{x} + 3)-3)^2 = (\sqrt{x})^2 = x \]. Thus, \( f(f^{-1}(x)) = x \), completing the verification.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-to-One Function
A one-to-one function, also known as an injective function, is a type of mathematical function where each element of the domain is paired with a unique element of the codomain. This uniqueness is crucial because it guarantees that no two different inputs will produce the same output.
In other words, a one-to-one function ensures that for any two inputs, say \(x_1\) and \(x_2\), if \(f(x_1) = f(x_2)\), then \(x_1 = x_2\). Without this property, it would not be possible to define a true inverse function.
In other words, a one-to-one function ensures that for any two inputs, say \(x_1\) and \(x_2\), if \(f(x_1) = f(x_2)\), then \(x_1 = x_2\). Without this property, it would not be possible to define a true inverse function.
- To confirm a function is one-to-one, check that it passes the **horizontal line test**: a horizontal line should intersect the graph of the function at most once.
- In the context of this exercise, the function \(f(x) = (x-3)^2\) is restricted to \(x \geq 3\), making it one-to-one within this domain.
Function Verification
Function verification involves demonstrating that two functions are truly inverses of each other. When a function \(f\) has an inverse \(f^{-1}\), two key relationships must hold: \(f^{-1}(f(x)) = x\) and \(f(f^{-1}(x)) = x\). These relationships highlight the concept that applying a function and its inverse in succession should return the original value.
In our exercise, we verify these relationships by substitution and simplification:
In our exercise, we verify these relationships by substitution and simplification:
- **Verification of \(f^{-1}(f(x)) = x\)**: Substitute \(f(x)\) into \(f^{-1}(x)\) and show that you return to the original \(x\).
- **Verification of \(f(f^{-1}(x)) = x\)**: Replace \(x\) with \(f^{-1}(x)\) in \(f(x)\) and simplify to get back to \(x\).
Square Root Function
A square root function involves finding a number that, when squared, yields another given number. In mathematical terms, for any non-negative number \(x\), the square root is signified as \(\sqrt{x}\).
The square root function is described by the equation \(y = \sqrt{x}\), which inherently involves positive values because we consider non-negative square roots. This function has a key property: reversing a squared value using a square root should retrieve the original non-negative value.
The square root function is described by the equation \(y = \sqrt{x}\), which inherently involves positive values because we consider non-negative square roots. This function has a key property: reversing a squared value using a square root should retrieve the original non-negative value.
- The principal square root of a squared quantity \((x-3)^2\) is \(x-3\), as noted in the verification of \(f^{-1}(f(x)) = x\). The restriction of \(x \geq 3\) ensures that the square root reflects the non-negative domain.
- In an inverse scenario like our exercise, square roots undo the squaring operation, which is fundamental to solving the inverse and verifying its correctness.