Chapter 1: Problem 24
Specify whether the given function is even, odd, or neither, and then sketch its graph. $$ h(x)=\sqrt{x^{2}+4} $$
Short Answer
Expert verified
The function is even. It is symmetric about the y-axis.
Step by step solution
01
Understand the Definitions of Even and Odd Functions
A function is **even** if for every x, \( f(-x) = f(x) \). It is **odd** if for every x, \( f(-x) = -f(x) \). To determine if a function is even or odd, check these conditions.
02
Replace x with -x in h(x)
Given the function \( h(x) = \sqrt{x^2 + 4} \), replace \( x \) with \( -x \). \( h(-x) = \sqrt{(-x)^2 + 4} = \sqrt{x^2 + 4} \).
03
Compare h(x) and h(-x)
Compare \( h(x) = \sqrt{x^2 + 4} \) and \( h(-x) = \sqrt{x^2 + 4} \). Both expressions are identical, showing that \( h(x) = h(-x) \).
04
Determine if the Function is Even, Odd, or Neither
Since \( h(x) = h(-x) \), the function \( h(x) \) is even. It is not odd because it does not meet the condition \( h(-x) = -h(x) \).
05
Sketch the Graph
To sketch the graph of \( h(x) = \sqrt{x^2 + 4} \):1. Note that since \( x^2 \) and 4 are always positive, \( h(x) > 0 \) for all real \( x \).2. Plot key points, such as when \( x = 0 \), \( h(x) = \sqrt{0 + 4} = 2 \).3. Since \( h(x) \) is even, it is symmetric about the y-axis.4. The graph is a curve starting at \((0,2)\) ascending gradually on both sides.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Symmetry
When investigating functions, symmetry plays an important role. A function can show two types of symmetry: even and odd. Understanding these can greatly simplify graph sketching and analyzing.
- An **even function** satisfies the condition: \( f(-x) = f(x) \) for every x in the domain. This means its graph will mirror itself about the y-axis. Think of even functions like a reflection in a pond.
- An **odd function** will satisfy: \( f(-x) = -f(x) \). In simple terms, this means its graph is symmetric with respect to the origin, giving it a rotating symmetry.
For the given function \( h(x) = \sqrt{x^2 + 4} \), we found that:
- \( h(-x) = \sqrt{(-x)^2 + 4} = \sqrt{x^2 + 4} \), meaning it’s identical to \( h(x) \). Therefore, it is an **even function**.
Recognizing these patterns not only helps in sketching but is also crucial in solving many function-related problems in calculus.
- An **even function** satisfies the condition: \( f(-x) = f(x) \) for every x in the domain. This means its graph will mirror itself about the y-axis. Think of even functions like a reflection in a pond.
- An **odd function** will satisfy: \( f(-x) = -f(x) \). In simple terms, this means its graph is symmetric with respect to the origin, giving it a rotating symmetry.
For the given function \( h(x) = \sqrt{x^2 + 4} \), we found that:
- \( h(-x) = \sqrt{(-x)^2 + 4} = \sqrt{x^2 + 4} \), meaning it’s identical to \( h(x) \). Therefore, it is an **even function**.
Recognizing these patterns not only helps in sketching but is also crucial in solving many function-related problems in calculus.
Graph Sketching
Graphing can visually bring a function to life, providing insights into its structure and behavior. Once the symmetry of the function is identified, as with our **even** function, the task becomes simpler.
For \( h(x) = \sqrt{x^2 + 4} \), here are some key steps to create a sketch:
By carefully considering symmetry and key points, a reasonable graph sketch can serve shortcut to understanding function behavior.
For \( h(x) = \sqrt{x^2 + 4} \), here are some key steps to create a sketch:
- Start by noting that since the inner term \( x^2 \) is always non-negative, the smallest value for \( h(x) \) is its value at x = 0.
- At \( x = 0 \), \( h(0) = \sqrt{0 + 4} = 2 \). This point \( (0,2) \) is crucial for your graph.
- The even nature of the function means the graph will mirror along the y-axis. Plot key points on one side and reflect them across.
- The curve starts at \( (0,2) \) and rises smoothly away from the y-axis as x increases or decreases, forming a symmetric arch.
By carefully considering symmetry and key points, a reasonable graph sketch can serve shortcut to understanding function behavior.
Function Analysis
Analyzing a function involves understanding not just symmetry, but also its behavior over its entire domain. For \( h(x) = \sqrt{x^2 + 4} \), here’s a deeper look:
These observations give a clearer picture of the function's properties. By examining both domain and range, intercepts, and general growth behavior, you build a solid understanding beyond merely graphing.
- **Domain**: The expression under the square root \( x^2 + 4 \) is always positive, meaning \( h(x) \) is defined for all real numbers \( x \).
- **Range**: Since the smallest value of \( \sqrt{x^2 + 4} \) is 2, the function only takes values \( y \geq 2 \).
- **Intercepts**: We've identified the y-intercept at \( (0,2) \). There are no x-intercepts because the minimum value is 2.
- **Behavior**: As \( x \) grows larger positively or negatively, the x-term grows rapidly. Thus, the function \( h(x) \) increases indefinitely.
These observations give a clearer picture of the function's properties. By examining both domain and range, intercepts, and general growth behavior, you build a solid understanding beyond merely graphing.