Chapter 1: Problem 11
Express the solution set of the given inequality in interval notation and sketch its graph. $$ x^{2}+2 x-12<0 $$
Short Answer
Expert verified
The solution set is \((-4, 3)\).
Step by step solution
01
Factor the Quadratic Expression
To solve the inequality \(x^2 + 2x - 12 < 0\), we need to factor the quadratic expression. We look for two numbers that multiply to \(-12\) and add to \(2\).The factors are \((x+4)(x-3)\) since \(4 \times -3 = -12\) and \(4 + (-3) = 1\). Thus, the inequality becomes \((x+4)(x-3) < 0\).
02
Find the Critical Points
The critical points occur where the expression equals zero. Set \((x+4)(x-3) = 0\) and solve for \(x\):- \(x+4=0\) gives \(x=-4\)- \(x-3=0\) gives \(x=3\)Critical points are \(-4\) and \(3\).
03
Determine the Test Intervals
Use the critical points to divide the number line into intervals. The intervals are :1. \((-\infty, -4)\)2. \((-4, 3)\)3. \((3, \infty)\)
04
Test Each Interval
Select a test point from each interval and plug it into the inequality \((x+4)(x-3) < 0\):1. For \((-\infty, -4)\), choose \(-5\): \((-5+4)(-5-3) = (-1)(-8) = 8\), not less than 0.2. For \((-4, 3)\), choose \(0\): \((0+4)(0-3) = (4)(-3) = -12\), less than 0.3. For \((3, \infty)\), choose \(4\): \((4+4)(4-3) = (8)(1) = 8\), not less than 0.
05
Write the Solution in Interval Notation
Since the expression is less than zero only over the interval \((-4, 3)\), the solution set is \((-4, 3)\).
06
Sketch the Graph
On a number line, draw open circles at \(-4\) and \(3\) to indicate these points are not included, and shade the region between \(-4\) and \(3\) to represent \((-4, 3)\), where the inequality is satisfied.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expression
A quadratic expression is a polynomial of degree two, generally expressed as \( ax^2 + bx + c \). When solving inequalities with quadratic expressions, a common technique is to factor the quadratic to make analysis simpler. This involves finding two numbers that multiply to the constant term (here, \(-12\)) and add to the linear coefficient (here, \(2\)). Once factored, the quadratic expression \( x^2 + 2x - 12 \) becomes \( (x+4)(x-3) \). This new form is often easier to work with when solving inequalities because it breaks down the problem into more manageable parts. Each term in the factored form represents a potential critical point where the inequality changes its behavior.
Critical Points
In analyzing quadratic inequalities, critical points play a vital role. These are the points where the expression equals zero. For \( (x+4)(x-3) = 0 \), solving the equation gives the critical points \( x = -4 \) and \( x = 3 \).
- The critical points divide the number line into distinct segments or intervals.
- These intervals help determine where the expression is greater than, less than, or equal to zero.
Interval Notation
Interval notation is a way of describing a set of numbers, typically representing the solution set of an inequality. Here, the solution obtained after analyzing the intervals is expressed using interval notation, \((-4, 3)\). This particular format communicates:
- Open circles at points \(-4\) and \(3\) indicate these endpoints are not included in the solution.
- The parentheses \(( )\) further confirm that the interval does not include \(-4\) and \(3\).
Test Intervals
Testing intervals is a critical step after identifying the critical points. Each interval between and beyond these points needs to be tested to determine where the inequality holds:- For the interval \((-\infty, -4)\), a test point like \(-5\) yields a positive product, not satisfying the \(< 0\) condition.- The interval \((-4, 3)\) with a test point like \(0\) results in a negative product, meeting the inequality condition.- Finally, in the interval \((3, \infty)\), using a test point like \(4\) gives a positive result again, not satisfying the inequality.This process ensures that only the interval \((-4, 3)\) is included in the final solution, as it is the only interval that satisfies the quadratic inequality \((x+4)(x-3) < 0\). Choosing appropriate test points and properly evaluating them is crucial for correctly solving such inequalities.