/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Consider the sequence \(\left\\{... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the sequence \(\left\\{a_{n}\right\\}_{n=1}^{+\infty}\) whose \(n\) th term is$$ a_{n}=\frac{1}{n} \sum_{k=1}^{n} \frac{1}{1+(k / n)} $$ $$ \begin{array}{l}{\text { Show that } \lim _{n \rightarrow+\infty} a_{n}=\ln 2 \text { by interpreting } a_{n} \text { as the Rie- }} \\ {\text { mann sum of a definite integral. }}\end{array} $$

Short Answer

Expert verified
\( \lim_{n \rightarrow \infty} a_n = \ln 2 \) by interpreting it as the Riemann sum of the integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \).

Step by step solution

01

Understand the Riemann Sum

A Riemann sum is an approximation of a definite integral, calculated as \( \frac{1}{n} \sum_{k=1}^{n} f(\frac{k}{n}) \). This expression represents the sum of the function \( f(x) \) evaluated at specific points multiplied by the width of the intervals, which approaches the definite integral as \( n \to \infty \).
02

Identify Function and Interval

We need to express \( a_n \) in a form that resembles a Riemann sum. Notice that \( a_n = \frac{1}{n} \sum_{k=1}^{n} \frac{1}{1+(\frac{k}{n})} \). Here, the function is \( f(x) = \frac{1}{1+x} \), and it is sampled at \( x_k = \frac{k}{n} \). The interval for \( x \) goes from 0 to 1.
03

Express as a Definite Integral

The Riemann sum \( \frac{1}{n} \sum_{k=1}^{n} \frac{1}{1+(\frac{k}{n})} \) approximates the integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \). As \( n \to \infty \), this sum becomes the exact value of the integral.
04

Compute the Definite Integral

Calculate \( \int_{0}^{1} \frac{1}{1+x} \, dx \). The antiderivative of \( \frac{1}{1+x} \) is \( \ln(1+x) \). Evaluating from 0 to 1 gives \( \ln(1+1) - \ln(1+0) = \ln 2 - 0 = \ln 2 \).
05

Conclusion

Since \( a_n \) is the Riemann sum that converges to the integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \) as \( n \rightarrow \infty \), we have shown that \( \lim_{n \rightarrow \infty} a_n = \ln 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
A definite integral is a fundamental concept in calculus that represents the area under a curve, described by a function, within a specific interval. This area is calculated by integrating the function over the interval using limits of integration. In mathematical terms, for a function \( f(x) \) defined on an interval \([a, b]\), the definite integral is denoted as \( \int_{a}^{b} f(x) \, dx \).

This integral essentially sums up an infinite number of infinitesimally small areas beneath the curve of \( f(x) \) from \( x = a \) to \( x = b \). This is especially useful to compute physical quantities like distance, area, and total accumulated change.

In the context of a Riemann sum, as you increase the number of partitions, \( n \), the approximated sum converges to the actual value of the definite integral. For example, in the exercise, the sequence \( a_n \) is interpreted as a Riemann sum that approximates the definite integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \). As the number of partitions grows infinitely large, this sum becomes an exact representation, thus demonstrating the concept of convergence to the definite integral.
Convergence
Convergence is a concept in mathematics where a sequence or series approaches a specific value as the number of terms increases. In terms of the exercise, we are examining the convergence of a sequence of Riemann sums \( \{a_n\} \) as \( n \) approaches infinity.

The sequence \( a_n \) is a sum built from dividing the interval \([0, 1]\) into smaller sub-intervals. Each partition gets smaller as \( n \) increases, leading to more precise approximations of a definite integral.

When \( n \to \infty \), the Riemann sum effectively becomes the exact value of the integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \).
  • This reflects a key property of integrals: they can be approximated by Riemann sums, which, when summed over an increasingly subdivided interval, converge to the integral's exact value.
  • In the given task, it helps establish that \( \lim_{n \to \infty} a_n = \ln 2 \).
Antiderivative
An antiderivative, also known as an indefinite integral, is a function that reverses the process of differentiation. In other words, the derivative of an antiderivative returns the original function. For a function \( f(x) \), its antiderivative is denoted by \( F(x) \), such that \( F'(x) = f(x) \).

Finding the antiderivative is crucial for evaluating definite integrals, as it helps in determining the area under a curve. In the exercise provided, identifying the antiderivative of \( \frac{1}{1+x} \) was necessary to evaluate the integral \( \int_{0}^{1} \frac{1}{1+x} \, dx \).
  • The antiderivative of \( \frac{1}{1+x} \) is \( \ln(1+x) \).
  • To compute the definite integral, substitute the limits of integration: Evaluate \( F(x) \) from 0 to 1, resulting in \( \ln 2 \).
This demonstrates how an antiderivative directly facilitates computing the values of definite integrals, thus playing a pivotal role in understanding the entire integration process.

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