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Use any method to determine whether the series converges. $$ \sum_{k=0}^{\infty} \frac{(k+4) !}{4 ! k ! 4^{k}} $$

Short Answer

Expert verified
The series converges because \(|x| = \frac{1}{4} < 1\).

Step by step solution

01

Identify the Series

The given series is \( \sum_{k=0}^{\infty} \frac{(k+4)!}{4!k! 4^k} \). This series resembles a binomial series with the form \( \sum_{k=0}^{\infty} \binom{n+k}{k} x^k \).
02

Simplify the Terms

Notice that \( \frac{(k+4)!}{4!k!} \) is a binomial coefficient form \( \binom{k+4}{4} \). So, the series can be rewritten as \( \sum_{k=0}^{\infty} \binom{k+4}{4} \left(\frac{1}{4}\right)^k \).
03

Apply the Binomial Series Test

Recognize that this is a binomial series of the type \( \sum_{k=0}^{\infty} \binom{n+k}{k} x^k \) which converges for \(|x| < 1\). Here, \(x = \frac{1}{4}\).
04

Conclusion on Convergence

Since \( \left| \frac{1}{4} \right| = \frac{1}{4} < 1 \), the series converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Series
A binomial series is a special kind of infinite series that generalizes the binomial theorem. It takes the form \( \sum_{k=0}^{\infty} \binom{n+k}{k} x^k\). Here, the term \( \binom{n+k}{k} \) represents a binomial coefficient. These series appear in various mathematical contexts like combinatorics and calculus. Generally, a binomial series expands expressions of the form \((1+x)^n\), where \( n \) can be any real number.
The series is valid for certain values of \( x \). Specifically, it converges when \(|x| < 1\). This is a crucial part of understanding and applying the binomial theorem.
In our example, the series can be rewritten to look like a binomial series: \( \sum_{k=0}^{\infty} \binom{k+4}{4} \left(\frac{1}{4}\right)^k \). Notice how the expression \( \left(\frac{1}{4}\right)^k \) corresponds to \( x^k \) in the binomial series. Understanding this transformation helps us apply convergence tests later.
Binomial Coefficient
The binomial coefficient is fundamental in combinatorics for calculating combinations. It's denoted by \( \binom{n}{k} \), often read as "n choose k". It calculates the number of ways to choose \( k \) items from \( n \) items without considering the order.
Mathematically, it is defined as \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \), where \( n! \) (read as "n factorial") is the product of all positive integers up to \( n \). Factorials are a key component of this operation.
In our series, the term \( \frac{(k+4)!}{4!k!} \) simplifies to \( \binom{k+4}{4} \), making it a binomial coefficient. Understanding how to simplify such expressions provides clarity in series transformation and analysis.
Convergence Test
In the context of series, a convergence test determines whether a series converges or diverges. One of the simple but powerful convergence tests is the ratio test, which applies well to power series like binomial series.
For a series \( \sum a_k \), the ratio test involves examining the limit of \( \left| \frac{a_{k+1}}{a_k} \right| \) as \( k \to \infty \). If this limit is less than 1, the series converges.
In a binomial series, the convergence depends on the value of \( x\). Specifically, for the series \( \sum_{k=0}^{\infty} \binom{n+k}{k} x^k \), convergence occurs if \(|x| < 1\).
In our given series, \( x = \frac{1}{4} \), and since \( \left| \frac{1}{4} \right| = \frac{1}{4} < 1 \), the series converges. Recognizing the pattern of a binomial series quickly guides us in applying this simple test efficiently.

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