Chapter 9: Problem 24
Determine whether the series converges. $$ \sum_{k=1}^{\infty} \operatorname{sech}^{2} k $$
Short Answer
Expert verified
The series \( \sum_{k=1}^{\infty} \operatorname{sech}^{2} k \) converges.
Step by step solution
01
Understand the Sech Function
The function \( \operatorname{sech}(x) \) is the hyperbolic secant function, defined as \( \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \). It represents how rapidly the function diminishes as \( x \) grows.
02
Examine the Behavior of Sech Function
The function \( \operatorname{sech}(x) \) decreases as \( x \) increases because \( e^x \) grows exponentially. This implies that \( \operatorname{sech}^{2}(x) = (\operatorname{sech}(x))^2 \) also decreases and approaches zero.
03
Apply the nth Term Test for Divergence
The nth term test states if \( \lim_{k \to \infty} a_k eq 0 \), the series \( \sum a_k \) diverges. Calculate \( \lim_{k \to \infty} \operatorname{sech}^2(k) \). Since \( \operatorname{sech}(k) \to 0 \) as \( k \to \infty \), it follows that \( \operatorname{sech}^2(k) \to 0 \). This does not prove convergence but also does not indicate divergence.
04
Consider the Comparison Test
The comparison test can determine convergence by comparing with a known convergent or divergent series. For large \( k \), \( \operatorname{sech}^2(k) \approx \frac{4}{e^{2k}} \) which suggests an exponential decay.
05
Compare with P-Series or Exponential Decay
The term \( \frac{4}{e^{2k}} \) is similar to a geometric series \( \frac{1}{e^{2}} \)^k, which converges since \( |r| < 1 \). Therefore, \( \sum_{k=1}^{ ext{∞}} \operatorname{sech}^{2}(k) \) should also converge because each term is bounded by a convergent geometric series.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sech function
The hyperbolic secant function, symbolized as \( \operatorname{sech}(x) \), derives from hyperbolic trigonometry. It is defined mathematically as \( \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \). This function reflects the inverse of the hyperbolic cosine, \( \cosh(x) \).
It represents how the function diminishes as \( x \) grows. For positive \( x \), the value of \( \operatorname{sech}(x) \) decreases due to the exponential growth of \( e^x \). This functional behavior shows a rapid decline to zero, which plays a critical role in series and convergence analyses.
As the \( x \) increases, the denominator in \( \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \) becomes significantly large, thus making \( \operatorname{sech}(x) \) approach zero. This characteristic is vital when assessing series based on \( \operatorname{sech}(x) \).
It represents how the function diminishes as \( x \) grows. For positive \( x \), the value of \( \operatorname{sech}(x) \) decreases due to the exponential growth of \( e^x \). This functional behavior shows a rapid decline to zero, which plays a critical role in series and convergence analyses.
As the \( x \) increases, the denominator in \( \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \) becomes significantly large, thus making \( \operatorname{sech}(x) \) approach zero. This characteristic is vital when assessing series based on \( \operatorname{sech}(x) \).
Convergence tests
In series assessment, determining convergence is crucial for understanding whether a series sums to a finite number.
Several tests help us analyze this:
Several tests help us analyze this:
- The nth-term test - It states that if the limit of the sequence doesn't converge to zero, the series cannot converge.
- The comparison test - It involves comparing a series with another series that is known to converge or diverge.
Hyperbolic functions
Hyperbolic functions, like \( \operatorname{sech}(x) \), are analogous to trigonometric functions like sine and cosine. They arise out of hyperbolic geometry and calculus.
These functions include:
These functions include:
- \( \sinh(x) = \frac{e^x - e^{-x}}{2} \)
- \( \cosh(x) = \frac{e^x + e^{-x}}{2} \)
- \( \tanh(x) = \frac{ ext{sinh}(x)}{ ext{cosh}(x)} \)
- \( \operatorname{sech}(x) \), as described earlier
Series comparison
Series comparison is a valuable technique in calculus to determine the convergence or divergence of a series by comparing it to another series of known behavior.
Here are steps for a comparison test:
Here are steps for a comparison test:
- Choose a series \( \sum b_k \) with known convergence or divergence characteristics.
- If \( 0 \leq a_k \leq b_k \) for all \( k \), and \( \sum b_k \) converges, then \( \sum a_k \) converges.
- If \( a_k \geq b_k \), and \( \sum b_k \) diverges, then \( \sum a_k \) diverges.
Geometric series
A geometric series is a series where each term after the first is the product of the previous term and a constant called the common ratio \( r \).
Mathematically, it is expressed as \( a + ar + ar^2 + ar^3 + \ldots \), which simplifies to:
\( \sum_{n=0}^{\infty} ar^n \).
If \(|r| < 1\), the geometric series converges and its sum can be calculated using the formula:
\[S = \frac{a}{1 - r}\]
This particular series is immensely helpful as a benchmark when comparing other less obvious series. In our exercise, recognizing that \( \operatorname{sech}^2(k) \) eventually mirrors a geometric series ensures predictions of convergence are accurate. By comparing to \( \frac{4}{e^{2k}} \), we see a convergent pattern since the effective ratio \( e^{-2} \) is less than 1. Aiding the conclusion, this reliance on geometric tenets strengthens convergence tests in calculus.
Mathematically, it is expressed as \( a + ar + ar^2 + ar^3 + \ldots \), which simplifies to:
\( \sum_{n=0}^{\infty} ar^n \).
If \(|r| < 1\), the geometric series converges and its sum can be calculated using the formula:
\[S = \frac{a}{1 - r}\]
This particular series is immensely helpful as a benchmark when comparing other less obvious series. In our exercise, recognizing that \( \operatorname{sech}^2(k) \) eventually mirrors a geometric series ensures predictions of convergence are accurate. By comparing to \( \frac{4}{e^{2k}} \), we see a convergent pattern since the effective ratio \( e^{-2} \) is less than 1. Aiding the conclusion, this reliance on geometric tenets strengthens convergence tests in calculus.