Chapter 9: Problem 21
Find the Taylor polynomials of orders \(n=0,1,2,3,\) and 4 about \(x=x_{0},\) and then find the \(n\) th Taylor polynomial for the function in sigma notation. $$ \sin \pi x ; x_{0}=\frac{1}{2} $$
Short Answer
Expert verified
The nth Taylor polynomial in sigma notation is \( \sum_{k=0}^{n} \frac{(-1)^k \pi^{2k}}{(2k)!} (x - \frac{1}{2})^{2k} \).
Step by step solution
01
Understanding Taylor Series
The Taylor polynomial for a function \( f(x) \) about \( x = x_0 \) is given by the formula: \[ T_n(x) = f(x_0) + f'(x_0)(x-x_0) + \frac{f''(x_0)}{2!}(x-x_0)^2 + \ldots + \frac{f^n(x_0)}{n!}(x-x_0)^n \] where \( T_n(x) \) is the Taylor polynomial of order \( n \). In this case, \( f(x) = \sin(\pi x) \) and \( x_0 = \frac{1}{2} \). We need to find derivatives of \( f(x) \) evaluated at \( x_0 \).
02
Compute Derivatives at \( x_0 \)
First, compute the derivatives of \( f(x) = \sin(\pi x) \): \[ f(x) = \sin(\pi x), \quad f'(x) = \pi \cos(\pi x), \quad f''(x) = -\pi^2 \sin(\pi x) \] \[ f'''(x) = -\pi^3 \cos(\pi x), \quad f^{(4)}(x) = \pi^4 \sin(\pi x) \] Now evaluate these at \( x_0 = \frac{1}{2} \): \[ f\left(\frac{1}{2}\right) = \sin\left(\frac{\pi}{2}\right) = 1 \] \[ f'\left(\frac{1}{2}\right) = \pi \cos\left(\frac{\pi}{2}\right) = 0 \] \[ f''\left(\frac{1}{2}\right) = -\pi^2 \sin\left(\frac{\pi}{2}\right) = -\pi^2 \] \[ f'''\left(\frac{1}{2}\right) = -\pi^3 \cos\left(\frac{\pi}{2}\right) = 0 \] \[ f^{(4)}\left(\frac{1}{2}\right) = \pi^4 \sin\left(\frac{\pi}{2}\right) = \pi^4 \]
03
Calculate Taylor Polynomials
Plug these values into the Taylor polynomial formula to find polynomials of various orders: **Order 0:** \[ T_0(x) = 1 \]**Order 1:** \[ T_1(x) = 1 + 0 \cdot (x - \frac{1}{2}) = 1 \]**Order 2:** \[ T_2(x) = 1 + 0 \cdot (x - \frac{1}{2}) - \frac{\pi^2}{2}(x - \frac{1}{2})^2 \]**Order 3:** \[ T_3(x) = 1 + 0 \cdot (x - \frac{1}{2}) - \frac{\pi^2}{2}(x - \frac{1}{2})^2 + 0 \cdot (x - \frac{1}{2})^3 \]**Order 4:** \[ T_4(x) = 1 - \frac{\pi^2}{2}(x - \frac{1}{2})^2 + \frac{\pi^4}{24}(x - \frac{1}{2})^4 \]
04
Write the nth Taylor Polynomial in Sigma Notation
The general form of the Taylor polynomial in sigma notation can be written as: \[ T_n(x) = \sum_{k=0}^{n} \frac{f^{(k)}(x_0)}{k!}(x-x_0)^k \] For \( f(x) = \sin(\pi x) \) and \( x_0 = \frac{1}{2} \), using the calculated derivatives, the sigma notation becomes:\[ T_n(x) = \sum_{k=0}^{n} \frac{(-1)^k \pi^{2k}}{(2k)!} \left(x - \frac{1}{2}\right)^{2k} \] Here, only the even powers of \( k \) have non-zero coefficients due to alternating sine and cosine evaluated at \( \pi/2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
The Taylor Series is a way to approximate functions by polynomials. It expands a function into an infinite sum of terms calculated from the function's derivatives at a single point. This approach helps us understand the behavior of functions at and around a particular point. By choosing a specific number of terms, we create Taylor polynomials, which are finite approximations.
For a function, say \( f(x) \), the nth Taylor polynomial about \( x = x_0 \) is constructed using derivatives of \( f(x) \):
For a function, say \( f(x) \), the nth Taylor polynomial about \( x = x_0 \) is constructed using derivatives of \( f(x) \):
- Start with the constant term, \( f(x_0) \), which represents the function's value at the point.
- The first derivative term, \( f'(x_0)(x-x_0) \), describes the function's slope or rate of change at the point.
- Higher derivatives, like \( f''(x_0)/2! \) or \( f'''(x_0)/3! \), account for the curvature and more complex changes in the function around \( x_0 \).
Derivative
Derivatives are central to understanding how functions behave. They measure how functions change when you alter \( x \) slightly, giving a precise idea of the function's instantaneous rate of change at any point.
The derivative of \( f(x) \), written as \( f'(x) \) or \( \frac{df}{dx} \), can often tell us:
The derivative of \( f(x) \), written as \( f'(x) \) or \( \frac{df}{dx} \), can often tell us:
- If \( f'(x) > 0 \), it implies the function is increasing at that point.
- If \( f'(x) < 0 \), it shows the function is decreasing.
- If \( f'(x) = 0 \), the point could be a peak, trough, or point of inflection.
Sin Function
In mathematics, the sine function \( \sin(x) \) is a periodic function deeply significant in trigonometry. It relates to the geometry of circle and oscillates between 1 and -1 as it cycles.
For the exercise, \( f(x) = \sin(\pi x) \), this function is centered at \( x_0 = \frac{1}{2} \). Sine is known for:
For the exercise, \( f(x) = \sin(\pi x) \), this function is centered at \( x_0 = \frac{1}{2} \). Sine is known for:
- Cycling every \( 2\pi \), thus making it inherently periodic and oscillatory.
- Having zeros at values which are integer multiples of \( \pi \).
- Reaching its maximum value of 1 at odd multiples of \( \frac{\pi}{2} \).
Sigma Notation
Sigma notation, denoted by the Greek letter \( \Sigma \), is a shorthand way to express the sum of a series of terms. It makes polynomial expressions, like Taylor polynomials, concise and easy to comprehend.
In our exercise, sigma notation was utilized to compress the Taylor series:\[ T_n(x) = \sum_{k=0}^{n} \frac{f^{(k)}(x_0)}{k!}(x-x_0)^k \]With this concise representation:
In our exercise, sigma notation was utilized to compress the Taylor series:\[ T_n(x) = \sum_{k=0}^{n} \frac{f^{(k)}(x_0)}{k!}(x-x_0)^k \]With this concise representation:
- The expression clearly shows the range of summation, from \( k=0 \) to \( n \).
- Each term includes both the coefficient derived from the derivative \( f^{(k)}(x_0) \) and the polynomial \( (x-x_0)^k \).
- This summation seamlessly handles the calculation for any order \( n \), adapting as needed with changes in \( n \).