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Solve the differential equation by the method of integrating factors. $$ \frac{d y}{d x}+2 x y=x $$

Short Answer

Expert verified
The solution is \( y = \frac{1}{2} + Ce^{-x^2} \).

Step by step solution

01

Identify and Rearrange the Equation

The given differential equation can be written in standard linear form as \( \frac{d y}{d x} + P(x) y = Q(x) \). For the equation \( \frac{d y}{d x} + 2xy = x \), we identify \( P(x) = 2x \) and \( Q(x) = x \).
02

Find the Integrating Factor

The integrating factor \( \mu(x) \) is computed using \( \mu(x) = e^{\int P(x) \, dx } \). So, we calculate:\[\mu(x) = e^{\int 2x \, dx} = e^{x^2}\]
03

Multiply Through by the Integrating Factor

Multiply the entire differential equation by the integrating factor \( e^{x^2} \):\[e^{x^2} \frac{d y}{d x} + 2x e^{x^2} y = x e^{x^2}\]This simplifies to \( \frac{d}{dx} (e^{x^2} y) = x e^{x^2} \).
04

Integrate Both Sides

To solve for \( y \), integrate both sides with respect to \( x \):\[\int \frac{d}{dx} (e^{x^2} y) \, dx = \int x e^{x^2} \, dx\]The left side simplifies to \( e^{x^2} y \), while the right side requires substitution. Let \( u = x^2 \), then \( du = 2x \, dx \), or \( x \, dx = \frac{1}{2} du \). Integrating gives:\[e^{x^2} y = \int e^u \frac{1}{2} \, du = \frac{1}{2} e^u + C = \frac{1}{2} e^{x^2} + C\]where \( C \) is the constant of integration.
05

Solve for y

Solve for \( y \) by dividing both sides by \( e^{x^2} \):\[y = \frac{1}{2} + Ce^{-x^2}\]This is the general solution to the differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Differential Equations
Differential equations are powerful tools in mathematics that describe relationships involving rates of change. They are equations that include functions and their derivatives, representing how these functions change.
A simple way to think about them is that they tell us how something changes with respect to something else, like how the position of a car changes over time. This change is influenced by various factors, such as speed and acceleration.
Differential equations come in many forms, such as ordinary differential equations, partial differential equations, and linear differential equations, which we will cover next.
  • Ordinary Differential Equations (ODEs) involve one independent variable, often time.
  • Partial Differential Equations (PDEs) involve multiple independent variables.
  • Linear Differential Equations have solutions that can be added together to form more solutions.
The method of integrating factors is a useful technique often employed to solve linear differential equations with variable coefficients.
Linear Differential Equations Demystified
Linear differential equations are a special type of differential equations where the unknown function and its derivatives appear linearly. In simpler terms, the function is not multiplied or divided by itself in these equations.
They are generally expressed in the form: \[\frac{d y}{d x} + P(x) y = Q(x)\] Where \(P(x)\) and \(Q(x)\) are functions of the variable \(x\). These equations are widespread because they describe many physical phenomena, like heat transfer, sound waves, and fluid dynamics.
Solving linear differential equations often involves finding an integrating factor, a clever trick that simplifies the equation. This trick transforms the problem into something easier to integrate, making it possible to find the unknown function.
Understanding how to manipulate these equations can unlock a vast array of possibilities in both theoretical and applied sciences.
Mastering Integration Techniques
Integration is a fundamental technique in mathematics used to find the antiderivative, or the area under a curve, representing cumulative quantities. In solving differential equations, particularly linear ones, integration is key to determining the unknown function.
A common technique involves using an integrating factor. This factor is a function that simplifies a linear differential equation, making it easier to solve. To find this integrating factor, \(\mu(x)\), you solve the integral:\[ \mu(x) = e^{\int P(x) \, dx } \] The purpose of the integrating factor is to make the left side of the equation integrable as a whole, allowing you to convert it into a simple derivative form like, \(\frac{d}{dx}(\text{{something}})\).
Using substitution can often help solve more complex integrals that arise in the process. By setting a different variable, like letting \(u = x^2\), you can simplify the integration, making the whole process more straightforward.
These integration techniques are not just solutions to puzzles; they are essential for analyzing real-world phenomena, helping us understand the continuous changes in the environment around us.

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Most popular questions from this chapter

Radon-222 is a radioactive gas with a half-life of 3.83 days. This gas is a health hazard because it tends to get trapped in the basements of houses, and many health officials suggest that homeowners seal their basements to prevent entry of the gas. Assume that \(5.0 \times 10^{7}\) radon atoms are trapped in a basement at the time it is sealed and that \(y(t)\) is the number of atoms present \(t\) days later. (a) Find an initial-value problem whose solution is \(y(t) .\) (b) Find a formula for \(y(t) .\) (c) How many atoms will be present after 30 days? (d) How long will it take for \(90 \%\) of the original quantity of gas to decay?

True–False Determine whether the statement is true or false. Explain your answer. If \(p(y)\) is a cubic polynomial in \(y,\) then the slope field \(d y / d x=p(y)\) has an integral curve that is a horizontal line.

In each part, verify that the functions are solutions of the differential equation by substituting the functions into the equation. $$ \begin{array}{l}{y^{\prime \prime}+4 y^{\prime}+13 y=0} \\ {\text { (a) } e^{-2 x} \sin 3 x \text { and } e^{-2 x} \cos 3 x} \\ {\text { (b) } e^{-2 x}\left(c_{1} \sin 3 x+c_{2} \cos 3 x\right) \quad\left(c_{1}, c_{2} \text { constants }\right)}\end{array} $$

Determine whether the statement is true or false. Explain your answer. If the first-order linear differential equation $$ \frac{d y}{d x}+p(x) y=q(x) $$ has a solution that is a constant function, then \(q(x)\) is a constant multiple of \(p(x) .\)

Determine whether the statement is true or false. Explain your answer. If a radioactive element has a half-life of 1 minute, and if a container holds 32 g of the element at 1: 00 P.M., then the amount remaining at 1: 05 P.M. will be \(1 \mathrm{g} .\)

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