Chapter 7: Problem 71
Writing Describe the various approaches for evaluating integrals of the form $$\int \sin ^{m} x \cos ^{n} x d x$$ Into what cases do these types of integrals fall? What procedures and identities are used in each case?
Short Answer
Expert verified
Use different techniques for each case: odd \( m \), odd \( n \), or both even.
Step by step solution
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Understanding Different Cases
Integrals of the form \( \int \sin^{m} x \cos^{n} x \; dx \) are solved based on the parity (odd or even) of \( m \) and \( n \). There are three main cases: 1) When \( m \) is odd; 2) When \( n \) is odd; 3) When both \( m \) and \( n \) are even.
02
Case 1 - When m is Odd
If \( m \) is odd, we can factor out one \( \sin x \) from the integrand. The remaining \( \sin^{m-1} x \) can then be expressed as \( (1 - \cos^2 x)^{\frac{m-1}{2}} \), allowing for a substitution \( u = \cos x \), \( du = -\sin x \, dx \). This simplifies the integral into a polynomial that can be easily integrated.
03
Case 2 - When n is Odd
If \( n \) is odd, we factor out one \( \cos x \) from the integrand. Then, the remaining \( \cos^{n-1} x \) can be rewritten as \( (1 - \sin^2 x)^{\frac{n-1}{2}} \). Using the substitution \( u = \sin x \), \( du = \cos x \, dx \), the integral becomes a manageable polynomial.
04
Case 3 - When Both m and n are Even
When both \( m \) and \( n \) are even, neither \( \sin x \) nor \( \cos x \) can be directly factored out. We use power-reduction identities: \( \sin^2 x = \frac{1 - \cos 2x}{2} \) and \( \cos^2 x = \frac{1 + \cos 2x}{2} \) to lower the powers of \( \sin x \) and \( \cos x \). This often requires multiple applications of these identities to fully simplify and integrate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration Techniques
Integration techniques are essential tools for solving trigonometric integrals. They provide a systematic way to find the integral of functions like \( \int \sin^{m} x \cos^{n} x \, dx \). This expression can be tricky, but recognizing it's composed of sine and cosine functions gives us a clear path on how to tackle it, based on whether the powers \( m \) and \( n \) are odd or even.
- Substitution Method: One of the most fruitful techniques involves substitution. When either sine or cosine has an odd power, substitution usually leads to simplification. For instance, if \( m \) is odd, substituting \( u = \cos x \) makes the integral easier to handle.
- Power-Reduction: When both \( m \) and \( n \) are even, simple substitutions aren't enough. Instead, we use power-reduction identities to transform higher power sine or cosine into multiple lower powers, making the integral approachable.
Odd and Even Functions
When dealing with \( \int \sin^{m} x \cos^{n} x \, dx \), identifying the parity of the exponents \( m \) and \( n \) is crucial. Odd and even functions influence the integration strategy, and knowing which is which determines our approach.
- Odd Functions: Consider \( m \) or \( n \) being odd. If \( m \), for example, is odd, \( \sin x \) or \( \cos x \) can be factored out to simplify the integral. This step allows applying trigonometric identities more effectively as it maintains symmetry in substitution.
- Even Functions: If \( m \) and \( n \) are even, direct substitution doesn’t suffice. Instead, power-reduction formulas are needed to simplify the trigonometric functions to lower degrees. This enables a clearer path to integration by slowly converting complex functions into sums of easier to digest components.
Power-Reduction Identities
Power-reduction identities are indispensable when both \( m \) and \( n \) are even in . These identities help reduce the exponents of trigonometric functions, making the integral easier to solve.
- Sine Power-Reduction: The identity \( \sin^2 x = \frac{1 - \cos 2x}{2} \) transforms \( \sin^2 x \) into something more manageable. It expresses the square of sine in terms of cosine, effectively lowering the power by decomposing it into two simpler parts.
- Cosine Power-Reduction: Similarly, the identity \( \cos^2 x = \frac{1 + \cos 2x}{2} \) simplifies \( \cos^2 x \) by expressing it in terms of \( \cos 2x \). This change reduces its power, thereby simplifying the integration process.