Chapter 5: Problem 34
Use a calculating utility with summation capabilities or a CAS to obtain an approximate value for the area between the curve \(y=f(x)\) and the specified interval with \(n=10,20,\) and 50 subintervals using the (a) left endpoint, (b) midpoint, and (c) right endpoint approximations. $$ f(x)=\sin x ;[0, \pi / 2] $$
Short Answer
Step by step solution
Problem Understanding
Divide the Interval
Left Endpoint Approximation
Midpoint Approximation
Right Endpoint Approximation
Sum Calculation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Left Endpoint Approximation
- Formula: The area is approximated by \( L_n = \Delta x \sum_{k=1}^{n} \sin(a + (k-1)\Delta x) \).
- Width of each subinterval: \( \Delta x = \frac{\pi}{2n} \).
- Procedure: Start at the left end of the interval, then step through the subintervals using these left endpoints to sum up the total area.
Midpoint Approximation
- Formula: The area is approximated by \( M_n = \Delta x \sum_{k=1}^{n} \sin \left(a + (k-1)\Delta x + \frac{\Delta x}{2}\right) \).
- Midpoint calculation: For any subinterval \((a + (k-1)\Delta x)\), the midpoint is \((a + (k-1)\Delta x) + \frac{\Delta x}{2}\).
- Benefit: This method often provides a good balance, especially for functions that don't change too abruptly.
Right Endpoint Approximation
- Formula: The area is calculated by \( R_n = \Delta x \sum_{k=1}^{n} \sin(a + k\Delta x) \).
- Endpoint choice: For each rectangle, the height is given by \( \sin(x_k) \) where \( x_k = a + k\Delta x \).
- Usage: Begin at the start of the interval and move rightwards, choosing the right endpoint for each rectangle.
Trapezoidal Rule
- Formula: The area using this rule is \( T_n = \frac{\Delta x}{2} \left(f(a) + 2\sum_{k=1}^{n-1} f(a+k\Delta x) + f(b)\right) \).
- Concept: Unlike the endpoint methods, which always use only one point from a subinterval, trapezoids use both endpoints to make a linear estimation.
- Advantage: By accounting for changes in \( y \) over \( \Delta x \), this method often provides a closer approximation of the true area.