Chapter 5: Problem 3
Find the average value of the function over the given interval. $$ f(x)=3 x ;[1,3] $$
Short Answer
Expert verified
The average value of the function is 6.
Step by step solution
01
Understand the Formula for Average Value of a Function
The average value of a function \( f(x) \) over the interval \([a, b]\) is given by the formula: \[ f_{avg} = \frac{1}{b-a} \int_{a}^{b} f(x) \, dx \]. For this problem, our \( f(x) = 3x \), \( a = 1 \), and \( b = 3 \).
02
Set Up the Integral
Set up the integral to find the area under the curve of \( f(x) = 3x \) from 1 to 3. This is set up as: \[ \int_{1}^{3} 3x \, dx \].
03
Integrate the Function
Calculate the integral of \( 3x \). The antiderivative of \( 3x \) is \( \frac{3}{2}x^2 \). So, \[ \int 3x \, dx = \frac{3}{2}x^2 + C \].
04
Evaluate the Definite Integral
Evaluate the definite integral from 1 to 3: \[ \left[ \frac{3}{2}x^2 \right]_1^3 = \frac{3}{2}(3)^2 - \frac{3}{2}(1)^2 = \frac{3}{2}(9) - \frac{3}{2}(1) = \frac{27}{2} - \frac{3}{2} = \frac{24}{2} = 12 \].
05
Calculate the Average Value
Now, plug the result of the integral back into the average value formula: \[ f_{avg} = \frac{1}{3-1} \times 12 = \frac{1}{2} \times 12 = 6 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integral Calculus
Integral calculus is a fundamental aspect of calculus focusing on finding the integral of a function. This technique is crucial for determining areas under curves. Integrals are used to sum up small elements to find a total. In practical terms, we often use them to find the total value of a continuously changing quantity.
When we talk about the integral of a function, it means we are looking for a function whose derivative corresponds to the original function we have in mind. This derivative function provides the rate of change of `f(x)` at any given point on its domain.
In problems involving the average value of a function, we specifically look for the definite integral, which we'll touch more upon later. This involves setting up an integral over a given interval, like \([a, b]\), and then evaluating it to find the total change in `f(x)` over that interval.
When we talk about the integral of a function, it means we are looking for a function whose derivative corresponds to the original function we have in mind. This derivative function provides the rate of change of `f(x)` at any given point on its domain.
In problems involving the average value of a function, we specifically look for the definite integral, which we'll touch more upon later. This involves setting up an integral over a given interval, like \([a, b]\), and then evaluating it to find the total change in `f(x)` over that interval.
Antiderivative
An antiderivative is essentially the reverse of a derivative. It seeks to identify the original function given its rate of change function. If you have a function and you wish to determine an expression that results in the original function when differentiated, you would seek its antiderivative.
For example, consider the function `f(x) = 3x`. The antiderivative of `3x` will offer us the function whose derivative is `3x`. It is computed as:
For example, consider the function `f(x) = 3x`. The antiderivative of `3x` will offer us the function whose derivative is `3x`. It is computed as:
- Find the exponent of `x` in `3x`, which is 1.
- Add one to the exponent, making it `x^2`.
- Divide the coefficient by the new exponent value: \(\frac{3}{2}x^2\).
Definite Integral
The definite integral is a concept that allows us to compute the accumulation of quantities and find the net area under a curve between two points a and b on the x-axis. Unlike indefinite integrals that produce antiderivatives, definite integrals yield numerical values representing accumulated changes over an interval.
To compute a definite integral, follow these steps:
To compute a definite integral, follow these steps:
- Determine the antiderivative of the given function
- Evaluate it at the upper limit of the interval (b) and then at the lower limit (a).
- Subtract the value at `a` from the value at `b` to find the result.
- Find the antiderivative: `\(\frac{3}{2}x^2\)`.
- Evaluate at `x=3` to get `\(\frac{3}{2}(3)^2 = 13.5\)`.
- Evaluate at `x=1` to get `\(\frac{3}{2}(1)^2 = 1.5\)`.
- Subtract: `13.5 - 1.5 = 12`.