Chapter 5: Problem 27
Divide the specified interval into \(n=4\) subintervals of equal length and then compute $$\sum_{k=1}^{4} f\left(x_{k}^{*}\right) \Delta x$$ with \(x_{k}^{*}\) as (a) the left endpoint of each subinterval, (b) the midpoint of each subinterval, and (c) the right endpoint of each-subinterval. Illustrate each part with a graph of \(f\) that includes the rectangles whose areas are represented in the sum. $$ f(x)=3 x+1 ;[2,6] $$
Short Answer
Step by step solution
Determine the Subinterval Width
Find x_k^* for Left Endpoints
Calculate the Sum for Left Endpoints
Find x_k^* for Midpoints
Calculate the Sum for Midpoints
Find x_k^* for Right Endpoints
Calculate the Sum for Right Endpoints
Illustrate with Graphs
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Subintervals
So, for the interval \([2, 6]\) and \(n = 4\), we have:
- The length of the entire interval is \((6-2) = 4\).
- Each subinterval, therefore, has a length of \( \Delta x = \frac{4}{4} = 1\).
Function Evaluation
For this exercise, there are three main types of key points where function evaluation takes place:
- Left Endpoints: For the subintervals \([2, 3], [3, 4], [4, 5], [5, 6]\), the left endpoint evaluations are \(x_1^* = 2\), \(x_2^* = 3\), \(x_3^* = 4\), and \(x_4^* = 5\).
- Midpoints: For the same subintervals, the midpoints become \(x_1^* = 2.5\), \(x_2^* = 3.5\), \(x_3^* = 4.5\), and \(x_4^* = 5.5\).
- Right Endpoints: Here, you consider the right side of each subinterval for evaluation: \(x_1^* = 3\), \(x_2^* = 4\), \(x_3^* = 5\), and \(x_4^* = 6\).
Graphical Representation
Consider the function \(f(x) = 3x + 1\) over the interval \([2, 6]\). When plotting the function, you use:
- The slope \(3x\) plus the y-intercept, which is \(1\) in \(f(x)\).
- Left endpoint approximation: Draw rectangles starting at each left endpoint within the interval.
- Midpoint approximation: Rectangles are drawn from the mid-points within each subinterval.
- Right endpoint approximation: Place rectangles beginning at each right endpoint of the subintervals.