/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Evaluate the integrals using the... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals using the indicated substitutions. $$ \begin{array}{l}{\text { (a) } \int \frac{d x}{x \sqrt{9 x^{2}-1}} ; u=3 x} \\\ {\text { (b) } \int \frac{d x}{\sqrt{x}(1+x)} ; u=\sqrt{x}}\end{array} $$

Short Answer

Expert verified
(a) \( \frac{1}{3} \sec^{-1}(3x) + C \); (b) \( 2\tan^{-1}(\sqrt{x}) + C \)."}

Step by step solution

01

Setup Integration for Part (a)

For the integral \( \int \frac{d x}{x \sqrt{9x^2 - 1}} \), we are given the substitution \( u = 3x \). Start by expressing \( x \) and \( dx \) in terms of \( u \). Since \( u = 3x \), we have \( x = \frac{u}{3} \) and \( dx = \frac{du}{3} \).
02

Substitute in Integral Expression (a)

Substitute \( x = \frac{u}{3} \) and \( dx = \frac{du}{3} \) into the integral. The integral becomes \( \int \frac{1}{\frac{u}{3} \sqrt{u^2 - 1}} \cdot \frac{du}{3} \). Simplify it to \( \int \frac{3}{u\sqrt{u^2 - 1}} \cdot \frac{du}{9} \) or \( \frac{1}{3} \int \frac{1}{u \sqrt{u^2 - 1}} du \).
03

Recognize the Integral Type and Solve (a)

The integral \( \int \frac{1}{u \sqrt{u^2 - 1}} du \) resembles a standard integral form, which is \( \int \frac{1}{u \sqrt{u^2 - a^2}} du = \frac{1}{a} \sec^{-1}\left(\frac{|u|}{a}\right) \). Here, \( a = 1 \), so the integral evaluates to \( \sec^{-1}(u) + C \). Therefore, we have \( \frac{1}{3} \sec^{-1}(u) + C \), or replacing back \( u = 3x \), \( \frac{1}{3} \sec^{-1}(3x) + C \).
04

Setup Integration for Part (b)

For the integral \( \int \frac{d x}{\sqrt{x}(1+x)} \), use the substitution \( u = \sqrt{x} \). This implies that \( x = u^2 \) and thus \( dx = 2u \, du \).
05

Substitute in Integral Expression (b)

Substitute \( x = u^2 \) and \( dx = 2u \, du \) into the original integral. It becomes \( \int \frac{2u \, du}{u(1 + u^2)} = \int \frac{2 \, du}{1 + u^2} \).
06

Recognize the Integral Type and Solve (b)

The integral \( \int \frac{2}{1 + u^2} du \) is akin to the standard integral form of \( \int \frac{1}{1+u^2} du = \tan^{-1}(u) + C \). Therefore, this evaluates to \( 2\tan^{-1}(u) + C \). Substitute back \( u = \sqrt{x} \), finding the solution \( 2\tan^{-1}(\sqrt{x}) + C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a powerful technique used to solve integrals that are not directly approachable. It involves replacing a part of the integral with a variable (often referred to as "u") to make the integration simpler. Here's a practical example: Suppose you have the integral \( \int \frac{d x}{x \sqrt{9x^2 - 1}} \). You can use substitution to simplify this expression. By letting \( u = 3x \), you change the variables involved in the integral. Now, express \( x \) as \( x = \frac{u}{3} \) and \( dx \) as \( dx = \frac{du}{3} \).Once the substitution is completed, the integral is transformed into an easier form to solve, sometimes even resembling a standard integral form. The power of this method lies in its ability to reshape the integral into manageable chunks, helping you solve seemingly complex problems with ease. Always remember to substitute back to the original variable once you've integrated.
Inverse Trigonometric Functions
Inverse trigonometric functions, such as \( \sec^{-1}(x) \) and \( \tan^{-1}(x) \), arise naturally in certain integrals. These functions offer a way to find the angle whose trigonometric function equals a given number, which is especially useful when solving integrals involving square roots and squared terms. In the example \( \int \frac{1}{u \sqrt{u^2 - 1}} du \), it is recognized as a form of \( \sec^{-1} \) function. The standard formula utilized here is \( \int \frac{1}{u \sqrt{u^2 - a^2}} du = \frac{1}{a} \sec^{-1} \left(\frac{|u|}{a}\right) + C \). This kind of recognition saves time and simplifies computation. Substituting back the variables after integration gives the final expression with your original variables, allowing the solution to maintain its original context.Mastering these inverse functions helps improve your efficiency in solving integrals that would otherwise require more complex analytical techniques.
Definite and Indefinite Integrals
Understanding the distinction between definite and indefinite integrals is crucial in calculus. An indefinite integral, denoted by \( \int f(x) \, dx \), represents a family of functions and includes a constant of integration \( C \). This general form means the integral can have multiple possible antiderivatives that differ by a constant.On the other hand, a definite integral, written as \( \int_{a}^{b} f(x) \, dx \), calculates the net area under the curve \( y = f(x) \) from \( x = a \) to \( x = b \). This result is a specific number rather than a function, representing the accumulation of quantities.Both concepts come into play when using integration techniques. For instance, after employing the substitution method, the resulting antiderivative is often an indefinite integral, which can further reduce to a definite integral if limits are provided. Hence, understanding both types enables solving a broad range of calculus challenges effectively.

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Most popular questions from this chapter

Define \(F(x)\) by $$ F(x)=\int_{\pi / 4}^{x} \cos 2 t d t $$ (a) Use Part 2 of the Fundamental Theorem of Calculus to find \(F^{\prime}(x) .\) (b) Check the result in part (a) by first integrating and then differentiating.

(a) Use a CAS to find the exact value of the integral $$\int_{0}^{\pi / 6} \sin ^{4} x \cos ^{3} x d x$$ (b) Confirm the exact value by hand calculation. [Hint: Use the identity cos" \(\left.x=1-\sin ^{2} x .\right]\)

CASprograms have commands for working with most of the important nonelementary functions. Check your CAS documentantion for information about the error function erf(x) [see Formula (12)], and then complete the following. (a) Generate the graph of erf(x). (d) Use the graph to make a conjecture about the existence and location of any inflection points of erf \((x) .\) (e) Check your conjecture in part (d) using the second derivative of erf(x). (f) Use the graph to make a conjecture about the existence of horizontal asymptotes of erf(x). (g) Check your conjecture in part (f) by using the CAS to find the limits of erf(x) as \(x \rightarrow \pm \infty\). (b) Use the graph to make a conjecture about the existence and location of any relative maxima and minima of erf(x). (c) Check your conjecture in part (b) using the derivative of erf(x).

A function \(f(x)\) is defined piecewise on an interval. In these exercises: (a) Use Theorem 5.5 .5 to find the integral of \(f(x)\) over the interval. (b) Find an antiderivative of \(f(x)\) on the interval. (c) Use parts (a) and (b) to verify Part 1 of the Fundamental Theorem of Calculus. $$ f(x)=\left\\{\begin{array}{ll}{\sqrt{x},} & {0 \leq x<1} \\ {1 / x^{2},} & {1 \leq x \leq 4}\end{array}\right. $$

Evaluate the definite integral by expressing it in terms of \(u\) and evaluating the resulting integral using a formula from geometry. $$ \int_{\pi / 3}^{\pi / 2} \sin \theta \sqrt{1-4 \cos ^{2} \theta} d \theta ; u=2 \cos \theta $$

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