Chapter 5: Problem 10
Estimate the area between the graph of the function \(f\) and the interval \([a, b] .\) Use an approximation scheme with \(n\) rectangles similar to our treatment of \(f(x)=x^{2}\) in this section. If your calculating utility will perform automatic summations, estimate the specified area using \(n=10,50,\) and 100 rectangles. Otherwise, estimate this area using \(n=2,5,\) and 10 rectangles. $$ f(x)=\ln x ;[a, b]=[1,2] $$
Short Answer
Step by step solution
Understand the Problem
Select the Approximation Method
Subdivide the Interval
Calculate the Sum of Rectangles
Estimate with n=10 Rectangles
Estimate with n=50 Rectangles
Estimate with n=100 Rectangles
Analyze and Conclude
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Approximation Method
In our problem, we employed the left-endpoint approximation method. This involves evaluating the function at the left endpoint of each rectangle's base to determine its height. Here’s how it works:
- Divide the interval into equal parts.
- Calculate the width of each rectangle (\(\Delta x = \frac{b-a}{n}\)).
- Determine the height of the rectangles by evaluating the function at the left endpoints \(f(x_i)\).
Definite Integral
The integral is represented as \(\int_{1}^{2} \ln x \, dx\). Calculating this offers the exact area under the curve between the specified limits. Here’s a simple breakdown:
- The definite integral sums up small "slices" or areas across an interval to give us a total area.
- Though challenging to compute manually for complex functions, numerical techniques like Riemann sums approximate it well.
Logarithmic Function
Key features include:
- It's only defined for positive values of \(x\) because logarithms of non-positive numbers are undefined.
- The function \(\ln x\) is continuous and differentiable for \(x > 0\).
- Graphically, it passes through the point \((1,0)\) and approaches infinity as \(x\) increases while descending to \(-\infty\) as \(x\) approaches zero positive from the right.