Chapter 2: Problem 6
Find \(d y / d x\) $$ y=\sqrt{2} x+(1 / \sqrt{2}) $$
Short Answer
Expert verified
\( \frac{dy}{dx} = \sqrt{2} \)
Step by step solution
01
Identify the function components
The given function is \( y = \sqrt{2}x + \frac{1}{\sqrt{2}} \). It consists of two components: \( \sqrt{2}x \) and a constant term \( \frac{1}{\sqrt{2}} \).
02
Differentiate the function with respect to x
Apply the derivative rules: The derivative of \( cx \) is \( c \) (where \(c\) is a constant), and the derivative of a constant is 0. Therefore, the derivative of \( \sqrt{2}x \) is \( \sqrt{2} \) and the derivative of \( \frac{1}{\sqrt{2}} \) is 0.
03
Combine the derivatives
Combine the derivatives computed for each term: \( \frac{d}{dx}(\sqrt{2}x) = \sqrt{2} \) and \( \frac{d}{dx}(\frac{1}{\sqrt{2}}) = 0 \). Thus, \( \frac{dy}{dx} = \sqrt{2} + 0 = \sqrt{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative Rules
Differentiation is a fundamental concept in calculus that deals with finding the rate of change of a function. When we talk about derivative rules, we are referring to a set of standard rules that simplify the process of differentiation. One crucial rule is the **constant multiple rule**, which states that when differentiating a function that is a constant multiplied by a variable, say \( cx \), the derivative is simply \( c \). This is because the slope of a line characterized by \( cx \) at any point is its coefficient. Another important rule is the **sum rule**, which allows us to differentiate terms separately in a function and then sum the results. In simple terms, if you have a function \( f(x) = g(x) + h(x) \), the derivative \( f'(x) = g'(x) + h'(x) \). This simplification is invaluable when handling polynomial or piecewise functions that include addition or subtraction of terms.
Constant Function Differentiation
A constant function is one that does not change as the input changes; it remains the same for any value of \( x \). An example is \( y = c \) where \( c \) is a constant. The differentiation rule for constant functions is straightforward: the derivative of a constant is **zero**. Why? Because a constant function has no rate of change; it is flat on a graph, creating a horizontal line with a slope of zero. Consider differentiating \( y = \frac{1}{\sqrt{2}} \). Since this is a constant value, applying the rule tells us that its rate of change is 0, meaning any change in \( x \) does not change the value of \( y \). This concept is essential when dealing with equations where constants are present, as it simplifies calculations dramatically.
Linear Functions
Linear functions are those that result in a straight line when graphed. They take the simple form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. When differentiating a linear function, we find the **derivative equals the slope**, \( m \). This means with a linear equation like \( y = \sqrt{2}x + \frac{1}{\sqrt{2}} \), the derivative is simply the coefficient of \( x \), which is \( \sqrt{2} \). Linear functions are unique in their simplicity: no matter the value of \( x \), the rate of increase is constant throughout.
This consistent change is what makes linear functions such a foundational element in algebra and calculus, providing a clear picture of constant rates of change across many contexts.
This consistent change is what makes linear functions such a foundational element in algebra and calculus, providing a clear picture of constant rates of change across many contexts.