Chapter 15: Problem 36
Let \(k\) be a constant, \(\mathbf{F}=\mathbf{F}(x, y, z), \mathbf{G}=\mathbf{G}(x, y, z),\) and \(\phi=\phi(x, y, z) .\) Prove the following identities, assuming that all derivatives involved exist and are continuous. $$ \operatorname{curl}(\phi \mathbf{F})=\phi \operatorname{curl} \mathbf{F}+\nabla \phi \times \mathbf{F} $$
Short Answer
Step by step solution
Understanding the Curl of a Vector Field
Expanding the Expression \(\operatorname{curl}(\phi \mathbf{F})\)
Applying the Product Rule for Derivatives
Verifying Each Component
Conclusion: Completing the Proof
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
The formula for finding the curl of \( \mathbf{F} \) is given by:\[ \operatorname{curl}(\mathbf{F}) = abla \times \mathbf{F} = \left( \frac{\partial F_3}{\partial y} - \frac{\partial F_2}{\partial z}, \frac{\partial F_1}{\partial z} - \frac{\partial F_3}{\partial x}, \frac{\partial F_2}{\partial x} - \frac{\partial F_1}{\partial y} \right)\]- The curl is a vector field that tells us how much the original field rotates around each point.- The greater the magnitude of the curl, the more intense the rotation or swirl.- A zero curl means the field is irrotational, like a smooth flow without eddies.Understanding the curl helps in visualizing fluid flow, electromagnetic fields, and more in vector calculus.
Product Rule for Derivatives
This is illustrated by:\[ \operatorname{curl}(\phi \mathbf{F}) = \phi \operatorname{curl} \mathbf{F} + (abla \phi \times \mathbf{F})\]Here’s how the product rule works in this context:- Differentiate the scalar \( \phi \) separately from the vector \( \mathbf{F} \).- The first term \( \phi \operatorname{curl} \mathbf{F} \) keeps the original curl of \( \mathbf{F} \), weighted by \( \phi \).- The second term involves a cross-product between the gradient of \( \phi \) and \( \mathbf{F} \).The product rule is a powerful tool. It allows us to expand complex derivative expressions into simpler components.