Chapter 15: Problem 22
Let \(\mathbf{F}(x, y, z)=a \mathbf{i}+b \mathbf{j}+c \mathbf{k}\) be a constant vector field and let \(\sigma\) be the surface of a solid \(G .\) Use the Divergence Theorem to show that the flux of \(\mathbf{F}\) across \(\sigma\) is zero. Give an informal physical explanation of this result.
Short Answer
Expert verified
The flux of \(\mathbf{F}\) across \(\sigma\) is zero because its divergence is zero, indicating no net movement through \(\sigma\).
Step by step solution
01
Understand the Divergence Theorem
The Divergence Theorem states that for a vector field \(\mathbf{F}\) and a region \(G\) with boundary surface \(\sigma\): \[ \iint_{\sigma} \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_{G} abla \cdot \mathbf{F} \, dV \] where \(\mathbf{n}\) is the unit normal to the surface.
02
Calculate the Divergence of \(\mathbf{F}\)
For the constant vector field \(\mathbf{F}(x, y, z) = a \mathbf{i} + b \mathbf{j} + c \mathbf{k}\), the divergence is defined as \(abla \cdot \mathbf{F} = \frac{\partial a}{\partial x} + \frac{\partial b}{\partial y} + \frac{\partial c}{\partial z}\). Since \(\mathbf{F}\) is constant, the partial derivatives are zero, i.e., \(abla \cdot \mathbf{F} = 0\).
03
Integrate the Divergence Over the Volume
Since \(abla \cdot \mathbf{F} = 0\), the volume integral becomes \(\iiint_{G} abla \cdot \mathbf{F} \, dV = \iiint_{G} 0 \, dV = 0\).
04
Apply the Divergence Theorem Result
By the Divergence Theorem: \( \iint_{\sigma} \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_{G} abla \cdot \mathbf{F} \, dV \). Substituting the volume integral, we have: \( \iint_{\sigma} \mathbf{F} \cdot \mathbf{n} \, dS = 0 \).
05
Provide a Physical Explanation
Physically, the flux through the surface represents the 'flow' of the vector field out of the volume \(G\). Since the vector field \(\mathbf{F}\) is constant and its divergence is zero, it implies there is no 'source' or 'sink' within \(G\), meaning no net flow out of the surface.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a function that assigns a vector to every point in space. In our exercise, the vector field is represented by \[\mathbf{F}(x, y, z) = a \mathbf{i} + b \mathbf{j} + c \mathbf{k}\] where \(a\), \(b\), and \(c\) are constants. This particular vector field is uniform, meaning that its direction and magnitude are the same at every point in the space.
- Each vector in the field indicates a direction and a magnitude.
- The constant vector field suggests that vectors are not changing over space, making things simpler to analyze.
Flux
Flux refers to the quantity of a vector field passing through a given surface. Imagine water flowing through a net; the amount of water penetrating the net is similar to the concept of flux in a vector context. In the case of our vector field \(\mathbf{F}\), the flux across a surface \(\sigma\) can be calculated using a surface integral.
- The flux is calculated as \( \iint_{\sigma}\mathbf{F} \cdot \mathbf{n} \, dS \), where \(\mathbf{n}\) is the unit normal to the surface.
- Positive flux means that more field lines are exiting the surface than entering it.
- The physical significance of flux gives insight into how much of a field passes through a particular area, helping understand field interactions in spaces like magnetic fields or heat flow.
Surface Integral
A surface integral is a tool used to calculate the flux of a vector field across a surface. It extends the concept of integrals to two-dimensional surfaces and is particularly handy in physics and engineering for integrating over complex, curved surfaces. To compute the surface integral of a vector field \(\mathbf{F}\) over a surface \(\sigma\), we use \[\iint_{\sigma} \mathbf{F} \cdot \mathbf{n} \, dS\],where \(\mathbf{n}\) is the unit normal vector to the surface. Here's how it works:
- The integrand \(\mathbf{F} \cdot \mathbf{n}\) considers the component of the vector field perpendicular to the surface.
- The surface \(\sigma\) over which we're integrating must be smooth and well-defined.
- The integration essentially "sums up" the field's contribution over the entire surface.
Divergence
Divergence is a scalar measure of a vector field's tendency to originate from or converge into a point. You can think of divergence as measuring the 'expansiveness' or 'congestiveness' of a vector field at any point. In mathematical terms, for the vector field \(\mathbf{F}(x, y, z) = a \mathbf{i} + b \mathbf{j} + c \mathbf{k}\), the divergence \(abla \cdot \mathbf{F}\) is given by \[abla \cdot \mathbf{F} = \frac{\partial a}{\partial x} + \frac{\partial b}{\partial y} + \frac{\partial c}{\partial z}\].
- In the exercise provided, since each \(a\), \(b\), and \(c\) are constants, the partial derivatives are zero, leading to a zero divergence.
- Divergence provides us insights into whether the field has any "sources" (positive divergence) or "sinks" (negative divergence).
- Zero divergence indicates that there are no sources or sinks in the vector field, implying a uniform field throughout.